This is much more thorough and understandable.

Author: Mike Adams TheHealthRanger

Found this interesting video...

...by a kook. A kook who wants to make money off ads on YouBoob peddling CTs to even more gullible kooks.

But I think there's a flaw in his analysis, and that is that all the math is based on the premise that the second shooter was firing .223 rounds just as Paddock was. Adams even admits early in the video that the distance & shot report tables is different for different types of rounds.

But it's already known that Paddock has 1-2 dozen different firearms in the room. Some were .223, but I think others were of differing calibers. So perhaps Paddock fired .223 rounds some of the time, but also switched to different rifles of higher or lower caliber which would have differing acoustic lag times at the same distance. Has Adams accounted for that possibility?

There is also the speculative nature of matching bullet impact sounds with shot report acoustics. I.e you might hear on a recording 6 shot reports but only 5 bullet impacts, in which case determining which bullet impact sounds match which reports could be speculative, and if you get that wrong then you'll be wrong about the distance of the shooter.

Paddock switching rifles might also account for the differing shot acoustic recordings from the taxi at the base of tho hotel.

...by a kook. A kook who wants to make money off ads on YouBoob peddling CTs to even more gullible kooks.

When I first saw Mike Adams, the Health Ranger, chipping in on this, my first reaction was that when public figures try to demonstrate expertise in a field other than the field they are known for (health, in the case of Adams) it usually doesn't come off too well.

But Adams does seems to speak authoritatively in this video. He does claim to be an avid shooter, his message seems to affirm his is knowledgeable about firearms.

When I first saw Mike Adams, the Health Ranger, chipping in on this, my first reaction was that when public figures try to demonstrate expertise in a field other than the field they are known for (health, in the case of Adams) it usually doesn't come off too well.

But Adams does seems to speak authoritatively in this video. He does claim to be an avid shooter, his message seems to affirm his is knowledgeable about firearms.

What isn't he an expert on?

He spreads CTs and misinfo to ignorant people on:

• chemtrails
• fluoride in water
• dangers of antiperspirants
• dangers of laundry detergents
• monosodium glutamate
• vaccines causing autism
• GMOs

He claims he got diabetes at age 30 and cured himself. He claims ebola can be treated with herbal medicines, that Zika virus was carried by U.S. government genetically modified mosquitos, etc.

Natural News is considered an extremely odious fake-news anti-science site.

Mike Adams is a despicable con man. So we should not be surprised that he is peddling kookery about the Vegas shootings. We should only be surprised if he wasn't.

Personally I would probably agree with him on most of those items. Perhaps you don't like him for how he presents himself. If so, that's of course your prerogative. But on the point firearms, in the above video he does seem to show reasonable and authoritative knowledge, with the exception of the points of my own critique.

But I think there's a flaw in his analysis, and that is that all the math is based on the premise that the second shooter was firing .223 rounds just as Paddock was. Adams even admits early in the video that the distance & shot report tables is different for different types of rounds.

It is a weakness in his analysis, no doubt, but he does a good job of showing the calculation with a known round.

I cannot adopt the conclusion of proof of a second shooter based upon the limits of the analysis, and the limits of my own knowledge. I believe his analysis for a selected round is sound, but the conclusion has insufficient support.

Paddock switching rifles might also account for the differing shot acoustic recordings from the taxi at the base of tho hotel.

To his credit, Adams recommends that the FBI do a triangulation study. This is done on site, not just in the lab.

Get recordings of a discrete gunshot sound from multiple locations taken at the event and identify the locations and the time differences for when the same sound was recorded. That may be a bit of work for the FBI, but it can be done.

Adams used the single source sound analysis, the available data. Add serveral more recording locations, and the time differential will act to locate the point(s) of origin.

If cell phone location by geography is difficult, perhaps cell tower data or GPS could help pinpoint location at a specific time.

When the submarine Scorpion went down in the Atlantic, it imploded or exploded, but in either case it made a loud noise underwater and sunk to the bottom. We had a series of sonar listening stations (now obsolete and closed) at Iceland, Canada, the USA and the Caribbean islands. They picked up the report at slightly different times, depending on how long it took the sound to travel to each of them. To find the sunken sub, a ship trailed a sonobuoy (a device which can make a loud noise) underwater and set it off (repeatedly). We would all record the sound and HQ would check the time differences. When the time differences at the various stations matched the actual event, the sonobuoy was over the sunken sub. It was a lengthy trial and error process.

If several recording devices can have their location fixed at the time of the shooting, the same principle will apply to find the location of gunfire. If a gunfire noise from the 32nd floor cannot replicate the time differential at the several recording locations, they must look elsewhere until the sound arrives at the various recording locations with the known time differences.

Notably, many internet Marines and Army types appear certain that they hear the sound of a belt fed machine gun.

https://youtu.be/QCrNsC0mTBg

Las Vegas Shooting First Actual Shots - Rare

Tall Ace of Spades
Published on Oct 7, 2017

Most footage doesn't capture the real, initial, non automatic shots shown here that the shooter probably used as test shots before using the bump stock and continuous fire when the next song starts. People are clearly trying to leave the scene shortly after the initial shots which start at 3:12.

You sound like you work for the government like a pm I got years ago.

And you've hung around with LF's kooks long enough that you are starting to sound like and think like a kook.

But then, science and math are hard. And kooking is easy.

But then, science and math are hard.

Not really. They're just time consuming to learn.

No, they really are hard. The universe is not as we would like it to be. And it stubbornly refuses to behave as we think it should.

Theoretical physics is hard.

Ballistics and forensic chemistry are tedious, but not really hard.

Ballistics and forensic chemistry are tedious, but not really hard.

Well, the Natural News guy should be able to help out the FBI with both.

Did you know that he has two gas chromatographs? Take that, FBI.

by a kook. A kook who wants to make money off ads on YouBoob peddling CTs to even more gullible kooks.

BINGO~!

First Actual Shots

The speculation I've read is that those first isolated shots are Paddock's attempt to blow up the Jet fuel tanks... which he hit - whilst failing to understand that reality doesn't work like Hollywood's explosively delusional depiction of it.

This is much more thorough and understandable.

Don't you find it a little odd that he doesn't present any actual data or audio?

The model audio he's describing (without presenting any actual data) fits the scenario where the microphone is adjacent to the target:

[Using Sound of Target Impact for Acoustic Reconstructions of Shooting Events]

http:// www.btgresearch.org/AcousticReconstruction02042012.pdf

"For example, if the microphone is adjacent to the victim (such as a 911 recording might be), the equation for determining the distance becomes: t=tb - ts= d/Vb- d/Vs If the muzzle blast duration obscures the sound of the bullet hitting the target, simple inspection of the sound waveform is insufficient. "

In response to your request regarding this accusation against an LV Police Officer:

 

#4.  To: VxH  (#1 )

You didn't have time to watch the video yet.

Debunk it please.

A K A Stone   posted on  2017-10-08   15:46:17 ET 

Video claims shooter dressed as police

https://libertysflame.com/cgi- bin/readart.cgi?ArtNum=53025&Disp=78#C78

I found/took their formula, built a spreadsheet,  and plugged in 223 balistic data generated via shooterscalculator.com:

Important to note:

* Presently we don't have information regarding specificaly which weapons and amunition were used.  So the ballistic data was generated with a guestimate 223 configuration.

* My DAW (Sonar) doesn't appear to have the capability of capturing a sound spectrogram like the ones the authors of the study produced; but after reading their commentary on the blast noise obscuring impact noise, I filtered the crowd noise, and filtered/looked alternately for the report and then the high energy impact sounds - and I revised T1 and T2 accordingly.

More accurate results could possibly be obtained if the corresponding burst sequence on the Taxi-Driver video is identified and aligned, as the taxi-driver's audio contains only the muzzle blast and echo.  It doesn't have the crowd and impact noise to obscure the muzzle events.

The speculation I've read is that those first isolated shots are Paddock's attempt to blow up the Jet fuel tanks... which he hit - but failed to understand that reality doesn't work like Hollywood's explosive version of it.

I did see a report that they found tracer bullets in the suite but no indication he had fired a single round of tracer ammo.

Also, I saw another report (CNN) that he had and used "incendiary rounds" to shoot at the fuel tank. To be honest, I'm not sure what an incendiary round is or what it is supposed to be used for.

Anyway, I searched around and it seems that incendiary rounds are intended to create a substantial visual display of sparks to illuminate the exact position that a bullet struck. So it is a kind of tracer round apparently.

American Specialty Ammo: Starburst Ammo

Starburst Ammunition STARBURST AMMUNITION IS BASICALLY AN INCENDIARY ROUND LOADED WITH TITANIUM FLAKES.  UPON STRIKING A RELATIVELY SOLID OBJECT, A FLASH IS PRODUCED ALONG WITH A SHOWER OF SPARKS IN A 6-8 FOOT DIAMETER AREA. THIS ROUND CAN SERVE AS A SPOTTER ROUND, MUCH LIKE THE INCENDIARY TYPE AMMUNITION.  AMMUNITION IS NON-CORROSIVE AND MEETS SAAMI SPECIFICATIONS.  CAUTION MUST BE EXERCISED WHEN FIRING THESE ROUNDS TO PREVENT ACCIDENTAL BRUSH FIRES.  IT IS RECOMMENDED THAT THEY BE USED AT AN APPROVED FIRING RANGE.  CHECK YOUR STATE LAWS CONCERNING LAWFUL FIRING OF THIS AMMUNITION. 9MM LUGER PKG. OF 10   .40 S&W PKG. OF 10   .45 ACP PKG. OF 10   .223 REMINGTON (5.56 NATO) PKG. OF 10   .30M1 CARBINE PKG. OF 10   .308 WINCHESTER (7.62 NATO) PKG. OF 10   .30-06 SPRINGFIELD PKG. OF 10   7.62 X 39MM RUSSIAN PKG. OF 10 NOT AVAILABLE IN New York City; Marin, Napa, Ventura and Yolo counties, CA; Cook County, IL; D.C.; MA; all of Alaska; all of Flordia and All of Hawaii Price: $35.99  Special Order Only. Contact for Availability

There is also the speculative nature of matching bullet impact sounds with shot report acoustics

And he doesn't present a single sonogram - which is what the actual experts use to distinguish rifle report from impact sounds.

http:// www.btgresearch.org/AcousticReconstruction02042012.pdf

And yep - we don't know yet which weapons / ammunition were fired in association with the audio events.

Having that knowledge is essential to correctly computing the ballistic data - which include the changes in velocity he's using as "proof".

He's presented no "proof".

And yep - we don't know yet which weapons / ammunition were fired in association with the audio events.

I think the guesswork that the initial shots were the incendiary rounds fired at the fuel tanks is pretty good.

Then he changed to his main shooting window and used the bump-fire stock guns to open up on the crowd.

He wanted a big fire, possibly to panic (or just distract) the crowd or to draw off first responders. When that didn't work, he moved quickly into massacre mode.

He's presented no "proof".

I'm trying to decide if Stone has upgraded by switching from the Niburu/Planet X kooks to this Natural News kook. I think he has. This is a somewhat higher grade of kookery IMO.

This is a somewhat higher grade of kookery IMO.

He presents the process convincingly - WITHOUT any actual data.

Where's the audio/data/sonograms?

300k+ clicks on his youboob channel though. Shyster.

Don't you find it a little odd that he doesn't present any actual data or audio?

I don't. He's presenting his numeric analysis which is indeed easy to understand, and playing audio clips would not impress the lay audience. Those who are in a position to verify what he says because they have the raw audio data he's working with can certainly confirm it on their own, if inclined.

He's presented no "proof".

No, he clearly has not proved anything, and the vid should not have been labeled as such. But he has made an argument that there was a second shooter. Proving or disproving that argument would require more work.

300k+ clicks on his youboob channel though. Shyster.

Google already delisted his websites entirely.

It's only a matter of time before his kooking will get him demonetized on YouBoob also.

Google likes selling ads but there is a limit to the kinds of kooking they will tolerate, especially from a certifiable kook like Adams.

I don't.

If he had sonograms he could present them.

Why doesn't he?

they have the raw audio data

"raw audio data" is not required. The audio on the youtube videos, though compressed and degraded somewhat, would still be sufficient.

But you do need the ability/software to produce a detailed sonogram.

Does he have it or not?

He wanted a big fire, possibly to panic (or just distract) the crowd or to draw off first responders. When that didn't work, he moved quickly into massacre mode.

Given the "video game" motive, seeing a big fuel tank explode into flames would be a "cool" thing. But it was nighttime and it was at extremely long range, so he would have been uncertain that his shots were even hitting the tanks. Without any immediate gratification after a few shots, he turned his attention back to people.

Why doesn't he?

I already explained a reasonable motive.

But he has made an argument that there was a second shooter.

His argument/model is dependent upon:

A: Ballistic parameters he pulled out of his wherever

Please fill in the params on this balistic calculator with the correct REAL values?

http://www.jbmballistics.com/cgi-bin/jbmtraj-5.1.cgi

You can't.  He can't.  All anyone can do presently is guess.

B: Data from Audio that he doesn't present as part of documenting his methodology - which for this kind of sound would require a spectogram to differentiate the muzzle blast from the local sonic cracks and/or local impact sound events.

http:// www.btgresearch.org/AcousticReconstruction02042012.pdf

What he presented on the whiteboard is an example of an amplitude chart like this one I made for audio from a video recorded from the target zone.

That's NOT a spectogram. 

his numeric analysis

Based on numbers he pulled from where?

playing audio clips would not impress the lay audience.

Playing the audio clips AND showing the associated sonograms would have been possible ASSUMING he's got the expertise and capability he's claiming.

Drawing a model on a whiteboard isn't "proof" of anything. His title "Forensic acoustic proof" is a material misrepresentation of fact - aka FRAUD.

"proof" requires EVIDENCE, ie: DATA.

His title "Forensic acoustic proof" is a material misrepresentation of fact - aka FRAUD.

If you two have a personal dislike for Adams, even if very strong, that's perfectly fine and legitimate. But it would be reasonable to add that disclaimer when criticizing specific things he does, such as the video above.

That Google has imposed sanctions against him of whatever sort doesn't impress me, as Google is hardly the standard bearer of all that is right, good and honest.

Adams may be wrong about some things, and probably is as we all are. But personally, I think he's right about a lot of things too.

Given the "video game" motive, seeing a big fuel tank explode into flames would be a "cool" thing. But it was nighttime and it was at extremely long range, so he would have been uncertain that his shots were even hitting the tanks. Without any immediate gratification after a few shots, he turned his attention back to people.

No, with a scope, he would have seen when he hit the tanks.

We know that two of these shots did hit the tank, one bullet penetrating and one bouncing off. He undoubtedly was using a scoped rifle and would not have missed a 6' fireball when the bullets hit the tank.

He shot, hit the tank a couple of times, concluded it wasn't going to explode, then moved on to his main target.

That security guard panicked him, ruined his timetable all around.

He's claiming to have "proof" that he doesn't present - luring folks into clicking on his video, which is monetized.

That's FRAUD.

Adams may be wrong about some things, and probably is as we all are. But personally, I think he's right about a lot of things too.

That might just mean that you're gullible.

Remember what P.T. Barnum always said.

No, with a scope, he would have seen when he hit the tanks.

Remember this is, for all intents, a combat situation. Time if of the essence. If the tanks were all he was targeting, then fine, but if his goal is death and mayhem, taking that kind of shooting care costs time, and would be counter productive to his goal. He takes a couple shots. Nothing? Okay forget it, he concludes, and resumes targeting people. I think we agree on that. I hadn't heard he used incendiary rounds on the tanks.

That security guard panicked him, ruined his timetable all around.

I agree on this also. The guard was not part of the plan. Perhaps this guy had everything "over planned" and did not allow for the possibility of anything not going as he expected it to, and once that happened, he couldn't handle it. He was smart enough to do all this meticulous planning, but failed to realize that in an uncontrolled environment, unexpected things can happen during plan execution.

That might just mean that you're gullible.

Maybe I am. I would say though that the most gullible people are the people who think they are not.

Maybe I am. I would say though that the most gullible people are the people who think they are not.

I'm not sure exactly how that Bell curve is distributed.

Everyone is gullible about something. But a known grifter and CT peddler is another thing. That's a snake oil salesman.

Notice how Adams switched from his usual baloney and now presents himself as a ballistics expert. And he's mostly just rehashing other CT videos that he found on YouBoob. He even admits it.

 

psy·cho·sis

s+ÈkMsYs/

noun

1. a severe mental disorder in which thought and emotions are so impaired that contact is lost with external reality.
2.  
3. [The Architects of Western Decline:
4. A Study on the Frankfurt School and Cultural Marxism]
5. https://vid.me/UoQm#17m10s
   

"According to my opinion, and the opinions of many defectors of my caliber, only about 15% of time, money, and manpower is spent on espionage as such. The other 85% is a slow process which we call either  ideological subversion , active measures, or  psychological warfare. What it basically means is: to change the perception of reality of every American that despite of the abundance of information no one is able to come to sensible conclusions in the interest of defending themselves, their families, their community, and their country.

 

It's a great brainwashing process which goes very slow and is divided into four basic stages.

 

The first stage being "demoralization". It takes from 15 to 20 years to demoralize a nation. Why that many years? Because this is the minimum number of years required to educate one generation of students in the country of your enemy exposed to the ideology of [their] enemy. In other words, Marxism-Leninism ideology is being pumped into the soft heads of at least 3 generation of American students without being challenged or counterbalanced by the basic values of Americanism; American patriotism.

 

Most of the activity of the department [KGB] was to compile huge amount / volume of information, on individuals who were instrumental in creating public opinion.  Publisher, editors, journalists, uh actors, educationalists, professors of political science.  Members of parliament, representatives of business circles. 

 

Most of these people were divided roughly into two groups:  those who would tow the Soviet foreign policy, they would be promoted to positions of power through media and public manipulation;  [and] those who refuse the Soviet influence in their own country would be character assassinated OR executed physically, come Revolution.  "

--KGB Defector Yuri Bezmenov

--Soviet Subversion of the Free Press (Ideological subversion, Destabilization, CRISIS - and the KGB)

Notice how Adams switched from his usual baloney and now presents himself as a ballistics expert.

My first reaction when I saw the "Health Ranger" chiming in on the LV shooting was, as I pointed out, that he should stick to the field he's known for and not venture out into unrelated fields. It reminded me of G Edward Griffin, author of the book on the Federal Reserve. Seemingly well researched in that area, he apparently also made some public claims about how to fight cancer. Mentioning it to a guy I knew who had cancer issues (who has since died) the response was that Griffin should stick with federal reserve topics.

Still, I gave the video a listen and he does claim to be an avid shooting enthusiast. And apart from my own critique of the assumption that all shots used the same caliber weapon, his presentation does seem authoritative and free of "flat earth" type of argument fallacy.

I prefer to judge arguments people make without regard to the reputation of the person arguing them. Obviously there are limits when someone has already ruined their reputation like so many forum posters have, but still, that's my preference. With Adams, apparently he's already crossed that line with you, but not for me. Which is fine.

his presentation does seem authoritative

He's a buzzword and bullshyte artist.

I've cleaned up after more than one self-processed software "architect" whose work product failed to produce results - despite being able to regurgitate the latest fashionable vocabulary.

"Can you not see the emperor's new clothes?"

I prefer to judge arguments people make without regard to the reputation of the person arguing them

I prefer to judge their arguments based upon actual data.

Please fill in the params on this balistic calculator with the correct REAL values?

http://www.jbmballistics.com/cgi-bin/jbmtraj-5.1.cgi

You can't - and neither can Mr."Healthranger".

Thus, his buzzword and bullshyte "analysis" does not compile into "PROOF" - and his title is misleading, fraudulent, falsely advertised, click bait

In the context of postmodern "culture" where significant number of indivuals are so ignorant of (or even repelled by) science -- that they "believe" they can change their sex....

I'm unsure if they believe they can "change their sex" so much as they believe they already are, internally, of the opposite gender. It's not like they wake up one day and decide that they want to try something different by being a girl/boy.

Someone posted either here or on 4um a theory on at least the prevalence contemporary homosexuality, and that is that birth control pills might carry some of the blame. The theory goes, and supposedly has been demonstrated with rats, is that when a woman takes birth control pills, it screws up her hormones to have the desired effect of preventing pregnancy. When she comes off them, it takes time for her body to recover, but if she gets pregnant too soon, then the fetus is affected abnormally.

This offspring suffers no direct effects however. But then the chance of that child's children (i.e. the grand child of the woman who took BC pills) being homosexual is greatly increased.

Whether that's a cause or not, it does basically serve as a reminder that we do live in a chemical world which didn't exist 100 years ago, and enormous chemical exposure could be a factor in human development. Obviously homosexuality has existed for thousands of years so it couldn't be the only cause of it.

Now on transgenderism, I could give my own theory about that but it would be spiritually based, and though it makes a lot of sense to me, it's perhaps not welcome, so I'll not bother suggesting it.

 they believe they already are, internally, of the opposite gender.

Meanwhile, in reality land:  XX, XY, (and for a very small geneticaly malformed minority who are XXY etc) other .

Every Human is ONE of those at birth and, despite the latest fashionable Anti-Fa-LGBTQXYZWherever Transhumanist- Postgenderist, Newpeak - that. IS. Reality.

XX + XX = FAIL

XY + XY = FAIL

XX + XY = Human

Every Human is ONE of those at birth and, despite the latest fashionable Anti-Fa-LGBTQXYZWherever Transhumanist- Postgenderist, Newpeak - that. IS. Reality.

As I see it, we are more than "human". We are souls living in human bodies, and the soul makes up the bulk of our personality. If one believes that our human DNA defines all that we are, then yes, no further discussion is required.

Well, several billion years of BINARY natural selection speaks for itself.

YMMV.

XX + XX = FAIL

XY + XY = FAIL

XX + XY = Human

Well, several billion years of BINARY natural selection speaks for itself.

XX + XX = FAIL

XY + XY = FAIL

XX + XY = Human

Well, in the case of humans, true. But it's not true with all biological life, which if you subscribe to evolution, should perhaps be noted.

If I understood correctly, with some reptiles, they can have XX or XY or YX or YY chromes. If it's XY or YX, it's female. If XX or YY it's male.

One theory about how remote islands in the Pacific were populated suggests that a single female could cross the ocean and make landfall. Then it can have offspring without mating, meaning the offspring are all male, having either XX or YY chromes. Then the offspring could mate with their mother, generating both males and females. Kinda gross by human standards but hey, if that's what gets the species proliferated...

Just goes to show that relying on DNA XY chromes may not ultimately be an authoritative position.

So in nature, the line between male and female is not very straight, (no pun intended).

...by a kook. A kook who wants to make money off ads on YouBoob peddling CTs to even more gullible kooks.

But *you're* not always "peddling" a ridiculous discredited gubmint's, "Nothing to see here" CYA BS? That seems awfully "k00ky" to me.

The question here is whether it is plausible to consider elements within The Swamp are willing to do something/ANYTHING to sabotage the 2A or US Security in order to promote *their* agenda. After all, they operate in secrecy. With impunity and immunity. And appear married to the DNC, the MSM, and UN. As a sensible person, I'm sure you can do the math there.

Q: Whenever there are theories and heavy-duty circumstantial evidence that demonstrate *plausible* explanations for the inexplicable, why must you reflexively ALWAYS dismiss it? I'm hardly the only one who's always found that conspicuously odd. But since this isn't FR, a difference of opinion is expected.

However, there's doubt you've even delved a hair deep into analyzing this case (other than buying the gubmint's scripted SOS and MSM obfuscation.)

I suppose you believe TWA Flight 800 was just some mid-air "mishap" despite eyewitnesses to the contrary?

OR...0bama's Fast & Furious Op, the Benghazi Op, or IRS harassment of Tea Party organizers were just CTs too, right?

Well guess what? PROVEN: The SAME goob you respect and claim must be trusted on their version of events and speaks the truth...has as a rule conducted bogus investigation, lies and spins. REPEATEDLY.

This same gubmint whose version of "truth" YOU trust with all your heart is the VERY SAME gubmint whose Deep State and Swamp-Muck policies have over the decades purposely exposed regular Americans to damaging/fatal radiation, disease, and political saboteurs (Muzzies); protected and shielded the Klintoons and their shenanigans; AND made it crystal clear President Trump/MAGA = BAD, and Comrade 0bammy/Klintoon/Globalist-First = GOOD.

So...help me here. WHY can or should this goob be considered credible or trust-worthy any more than Alex Jones?

By what basis should we believe them? Over "investigations" about anything? Especially given the last 8 years under a Marxist/Alinsky-Disciple whose lack of historical transcripts and past, un-confirmed BC, collateral coincidental deaths (a la Klintoon), and elections are highly suspicious to begin with?

Since 1992 and Bubba's ridiculous election win over a sandbagging Poppy, it truly take the suspension of ALL logic to accept Swamp Critter versions of "troof" as gospel.

Kook on.

I'm not going to explore all these brave new worlds of kookery that you enjoy so much.

Much easier that way, eh?

Thought not.

Citing more kookeries doesn't actually help your case in proving a particular kookery, like this one from Natural News. But you'd know that if you weren't kooking out.

I will note that your anger...

I wouldn't waste an emotion like "anger" on your self-voluntary shilling for gubmint narratives. It's more like incredulity. The same emotion as with any zombie-fied Cultist...

That said, your reflexive reaction is typical of one whose "reality" is more wishful thinking than anything else.

Maybe that whole, "Santa is not real. REALLY, son!" spiel you heard in high school scarred you :-(

But I think there's a flaw in his analysis, and that is that all the math is based on the premise that the second shooter was firing .223 rounds just as Paddock was. Adams even admits early in the video that the distance & shot report tables is different for different types of rounds.

He likely used other calibers than .223 too, which makes his conclusion of a second shooter worthless. Even if he used .223 there's no guarantee that all of the ammo was 55gr bullets.

He's proved nothing. He's cherry picked one caliber, bullet weight, barrel length, twist and loading, to get hits to his crappy website.

I'm not saying that there wasn't more than one shooter, only that Adams hasn't proved it with his phony analysis.

Did you know that he has two gas chromatographs?

WHOA! Do his go to ELEVEN?

WHOA! Do his go to ELEVEN?

They can go as high as he wants.

WHOA! Do his go to ELEVEN?

Hehe... A reference to "Spinal Tap", no doubt.

Still funny....

Well, in the case of humans, true.

Uhuh. But don't tell the pronoun-challenged Transumanist-Postgenderists that... in California.

Hehe... A reference to "Spinal Tap", no doubt.

'Zactly!

He's claiming to have "proof" that he doesn't present - luring folks into clicking on his video, which is monetized.

That's FRAUD.

https://support.google.com/youtube/answer/6162278?hl=en

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[...]

Google already delisted his websites entirely.

Have you actually tried to google it?

Funny, entering healthranger.com into google yields this link. It it supposed to yield no result?

https://www.google.com/search?q=healthranger.com&oq=healthranger.com&gs_l=psy-ab.12..0.390751.399119.0.402145.19.18.1.0.0.0.119.1560.14j3.18.0....0...1.1.64.psy-ab..0.18.1569.0..0i131k1j0i67k1j0i10k1j0i10i30k1.80.HuDbfmMh_yo

You obviously don't understand what delisting is.

It means it won't show up in a google search. It is removed from the index. If it is not in the index, it cannot be found in the index. If it is still there, it is not delisted.

http://www.webopedia.com/TERM/D/delisting.html

You obviously don't understand what delisting is.

If KlingonBurger.com got delisted then they wouldn't show up in a search for "healthy burgers in gamma quadrant 4"

That kinda how it works?

If KlingonBurger.com

You still pushing the teleportion echo theory I see.

Paddock teleporting around shooting and your Klingon pic there to teleport him back and forth as he pleases.

You still pushing the teleportion echo theory I see.

Paddock teleporting around shooting and your Klingon pic there to teleport him back and forth as he pleases.

There's as much evidence for that as there is "PROOF!" that Paddock wasn't the only murderer.

That security guard panicked him, ruined his timetable all around.

Agreed

The rest of this amateur hour sleuthing via YouBoob videos is just a distraction.

I've responded and or handled many high profile crime scenes... and over the following weeks until the full incident is reported by LE, I've heard the most retarded conspiracy theories... when I know what actually happened. It's not even laughable.

I've responded and or handled many high profile crime scenes... and over the following weeks until the full incident is reported by LE, I've heard the most retarded conspiracy theories... when I know what actually happened. It's not even laughable.

A lot of the CT peddlers know full well they're hawking complete BS. But their objective is monetizing videos on YouBoob and driving clicks to their clickbaity websites.

We're seeing a steady stream of these frauds and their fanbois here at LF, from the Niburu/Planet X people to that Health Ranger idiot. So of course only idiocy can result from discussing any of it.

There are a lot of unanswered questions about Vegas. Hopefully, some of that will be cleared up tomorrow if they produce their big timeline and evidence dump as promised.

Found this interesting video.

Adams assumes a shooter using an AR-15 with .223 Remington 55 grain ammo.

He states 20% humidity.

He states a 925 m/s bullet velocity which is ~3034.8 fps.

He specifies a 16.5" barrel, but a 3034.8 fps initial velocity would seem to indicate a 20" barrel or different ammo.

I believe the white board has an error. The flight time should be 0.532s, not 0.528s.

It lists both the 400 yard flight time and the lag time as 0.528s. This would mean the bullet velocity was precisely double the speed of sound, and that double 0.528s, or 1.056s would be the 400 yard travel time for the speed of sound. The time of sound travel for 400 yards at 1130 fps is 1.062.

http://gundata.org/blog/post/223-ballistics-chart/

He cites his use of a gundata ballistics chart for travel time.

gundata indicates for 400 yards, the time of travel is 5.32s, specifying a standard 55gr Remington .223 bullet leaving the barrel at 3,215fps. Adams also specified a 16.5 inch barrel, but it seems an AR-15 with a 16.5 barrel does not achieve 3,215 initial velocity.

https://rifleshooter.com/2014/04/223-remington5-56-nato-velocity-versus-barrel-length-a-man-his-chop-box-and-his-friends-rifle/

Testing with different barrel lengths indicates an AR-15, 16.5" barrel, with Remington .223 ammo, does not achieve 3,034.8 muzzle ("initial") velocity.

With a 20" barrel, the same setup gets 3,071 fps muzzle velocity.

A 25" barrel gets it up to 3,221 fps muzzle velocity.

A 16.5" with Federal M193/55 gets 3,187 fps muzzle velocity.

http://guide.sportsmansguide.com/ballistic-chart/remington_charts/223rembal.htm

A ballistics chart indicates that a Remington .223 will not get the stated bullet velocity.

Assuming the shots were fired from room 32135, and that end of the Mandalay Bay Hotel was 1208 feet from the base of the bandstand, and that a bullet struck the pavement at or near the base of the bandstand, the long side a right triangle would be 1208 feet and the short side would be the height of room 32135.

The building claims a height of 480 feet and 44 stories, for an average of 10.91 feet per story. The 32nd floor would be 338.21 feet up. (31 x 10.91, base of floor 1 has zero height).

With sides of 1208 and 338.21, the hypotenuse would be 1254.45 feet.

The actual distance the bullet traveled would be more than that as it would not follow a straight path, but would follow an arc.

Using estimates of distance to striking the venue surface of ~1250 feet, and detected lag times of 0.559 sec and 0.374 sec, the slower bullet made the 0.374 lag time; the faster bullet arrived .559 sec before the muzzle blast.

At 1130 fps, the sound would cover 1250 feet in about 1.106 seconds.

A bullet making the 1250 ft trip .559 sec before the sound, made the trip in .547 sec.

A bullet making the 1250 ft trip .374 sec before the sound, made the trip in .732 sec.

1250 feet in .547 sec is an avg velocity of ~2236 fps.

1250 feet in .732 sec is an avg velocity of ~1708 fps.

This assumes both shots were taken from the same location.

What bullets were used can be ascertained by collecting the bullets. What was left in the room should be inventoried, along with what guns were in the room.

http://onyourownadventures.com/hunttalk/showthread.php?267715-308-Ammo-Help/page2

Thread: 308 Ammo Help

Most mfgs recommend a minimum velocity of 1800 fps for proper expansion. The so called "magic number" associate with elk hunting is 1200 lb ft Energy. Below that is risky and I prefer 1400 lb ft as my personal standard. Although every gun is different the ammo mfg. Will put their tested numbers out for their loads. According to Federal their TBT 165 gr out of a 308 maintains 1939 fps and 1377 lb ft at 500 yards. Mathematically that should do the job as long as the bullet hits it's mark. Federal lists the same weight game King at 1708 FPS and 1069 ft lb at 500 yards. Obviously not the best option. If you keep 400 yards and in either a 150 or 165 gr factory loaded bonded round should work fine on elk. You just need to find the one that goes exactly where you want it to every time you press the trigger.

This would suggest the possibility of the 1708 fps round being a .308 (or whatever else gets around 1708 fps at 400 - 450 yards.

http://gundata.org/blog/post/223-ballistics-chart/

This is a .223 ballistics chart (external) generated using our ballistic trajectory calculator. Based off a standard 55gr bullet leaving the barrel at 3,215fps and follows the bullet trajectory all the way to 1000 yards in steps of 50 yard increments. The charting shows the range, drop (based off a 1.5" scope mount), current velocity, energy, and time in seconds in relation to the bullets movement through space and time. This chart does not account for atmospheric conditions, so if you want to take in to effect these things check out the calculators official page. The Ballistic Coefficient for the .223 Remington, Remington Metal Case, 55gr is 0.202 (in this example) but, but may also range from .185 bc to .257

[...]

.223 Remington, Remington Metal Case, 55gr.

400 yards
-31.7981 [drop, inches]
1588 [Velocity]
308 [energy]
532 [time, milliseconds]

This ballistics chart indicates .532 seconds for 400 yards, at 1588 velocity.

.532 seconds would indicate 2255.6 average velocity for the 400 yards, and the velocity of the bullet leaving the barrel is specified at 3215 fps.

What was left in the room should be inventoried, along with what guns were in the room.

Keyword: "SHOULD"

Based on ballistics data, there are apparently unexplained inconsistencies. Now how can the science be explained away? (Oh wait -- it was already done in spades over 911.)

Why should we expect the same investigative agencies who ignored every shred of slam-dunk evidence regarding Hitlery (on a myriad of rock-solid federal charges) would EVER honestly investigate this case? Especially IF The Truth is politically incendiary?

Here's the bottom line:

Alphabet Agencies have a severe credibility problem that dates back at LEAST to Flight 800. Or even further -- past The Keith Hernandez Magic Loogie Incident, way back to JFK. This Cred-Gap was on full display during Hitlery's Hearing(s), as well as during their "RUSSIA-TRUMP RUSSIA-TRUMP RUSSIA-TRUMP!!" obsession and charade (that still percolates.)

We will NEVER get any definite truth out of these people on this case -- especially because THE Truth exposes every OTHER lie The Sheeple have been told, and because The Usual Suspects are involved.

Now how can the science be explained away? (Oh wait -- it was already done in spades over 911.)

In the Kennedy case, they not only sold a magic bullet, they sold that they took Oswald into custody but kept no reord of any question asked or any answer given, and Oswald was killed while in police custody by mafia good Jack Ruby who just happened to walk in off the street into the police HQ where Oswald was kept, and just happened to arrive as they were walking Oswald to a car for transfer, and Ruby felt so bad for Jackie that he just pulled out his gun and killed Oswald live, on national television.

You are so anal you MUST be a reloader/target shooter.

If not,you owe it to yourself to become one.

You were BORN to be one.

Come home,to where you belong.

Chances are you will develop a love-hate relationship with trap and skeet shooting,too.

I believe the white board has an error. The flight time should be 0.532s, not 0.528s.

Well you're smarter than I am.

Plus there's the little problem that he doesn't present any actual audio evidence.

I'm not saying there was one gunman or many. Just that your image doesn't prove shit.

Just that your image doesn't prove shit.

My meme references, measures, and explains actual audio.

An analysis of two sequential burts of gunfire between:
["Taxi Driver Video" the Zapruder Film of the Las Vegas shooting UNCUT / UNEDITED]
https://www.youtube.com/watch ?v=mBbOFwWquAw&feature=youtu.be&t=1m7s
and
https://www.youtube.com/watc h?v=mBbOFwWquAw&feature=youtu.be&t=1m24s

===============
T1: Time from start of video (1minute N seconds) at the time of the last shot in the burst.
T2: Time from the start of the video (1minute N seconds) at the time of the echoed sound event corresponding to T1.
TempF: the air temperature (72 degrees F)  
FPS:   1130 ft per second -- The speed of sound at 72 degrees F
Elapsed Time:  T2 minus T1, the number of seconds between the last shot, and the echo of the last shot in each burst.  
Total Distance:  Elapsed Time * FPS = the total distance traveled between T1 and T2.
Echo Distance  = The distance the echo traveled from the aiming point back to the point of origin.
===============

Conclusion:  Burst B is NOT two weapons being fired simultaneously.  It is one weapon being fired at a more distant target.  The longer distance, observable in the period between Burst B's T1 and T2, manifests a corresponding longer period of reverb.  It is the reverb that is being incorrectly interpreted as a second weapon (and second shooter) firing at the same time.

Research resources:
https://www.google.co m/search?biw=1544&bih=856&q=Forensic+Acoustics+gunfire
http://www.physic sclassroom.com/mmedia/waves/er.cfm
https://www.timeanddate.com/weather/usa/las- vegas/historic
http://www.csgnetwork.c om/soundspeedcalc.html

All numbers he pulled out of his arse?

Plus there's the little problem that he doesn't present any actual audio evidence.

The audio he used is presented.

Your chartoon is an absurdity.

The audio he used is presented.

LOL. He scribbled on a whiteboard.

The amplitude graphs of the audio referenced on my meme can be reproduced by anyone with minimal tools. It's REPRODUCIBLE - that's what differentiates valid science from conspiratorial buffoonery.

Show us the actual amplitude graphs or STFU.

The amplitude graphs of the audio referenced on my meme can be reproduced by anyone with minimal tools. It's REPRODUCIBLE - that's what differentiates valid science from conspiratorial buffoonery.

That you reproduce meaningless bullshit is meaningful, but not as you intend.

My meme references, measures, and explains actual audio.

Your chartoon lists "Test for Echo" and gives links to the Taxi Driver video.

Echo has nothing to do with measurements at the target site.

The methodology you link, and cite, is for measurements at the target site, only. It uses the sound of bullet strikes on the venue surface, and the sound wave of the muzzle blast reaching the same recording device, not any echo. They are recorded on the same nearby microphone at line of sight, not at two different locations, not line of sight, and over 300 feet apart.

You are absolutely clueless.

Here are your exact words about your chartoon being about two different sounds from the Taxi Driver Video:

https://libertysflame.com/cgi-bin/readart.cgi?ArtNum=53025&Disp=42#C42

I used the same speed I used in my other analysis (appended below) - based upon an air temperature of 72 degrees

Then I calculated the difference in time between the last bullet sound (T1) and the corresponding last report sound (T2).

[graphic omitted]

T2-T1 = time the report traveled = 1.07

1.07 * FPS of 1130.8 = 1208.8

[graphic omitted]

An analysis of two sequential burts of gunfire between:
["Taxi Driver Video" the Zapruder Film of the Las Vegas shooting
UNCUT / UNEDITED]
https://www.youtube.com/watch ?v=mBbOFwWquAw&feature=youtu.be&t=1m7s
and
https://www.youtube.com/watc h?v=mBbOFwWquAw&feature=youtu.be&t=1m24s
===============
T1: Time from start of video (1minute N seconds) at the time of the last shot in the burst.
T2: Time from the start of the video (1minute N seconds) at the time of the echoed sound event corresponding to T1.
TempF: the air temperature (72 degrees F)
FPS: 1130 ft per second -- The speed of sound at 72 degrees F
Elapsed Time: T2 minus T1, the number of seconds between the last shot, and the echo of the last shot in each burst.
Total Distance: Elapsed Time * FPS = the total distance traveled between T1 and T2.
Echo Distance = The distance the echo traveled from the aiming point back to the point of origin.

===============

Here you are citing times sounds are heard in the taxi, at least 340 feet from the shooter and around the corner, and the time en echo returned from who knows where, by an unknown path, back to the taxi, still at least 340 feet from the shooter. Nothing can be accurately calculated with this data.

T2 - T1 is not the time some report traveled. It is time difference between the time of the bullet arrival report and the sound arrival report. If your dippy calculation were correct, and the bullet were subsonic, T1 would be larger than T2, the the time some mythical report traveled would be a negative number. T2 - T1 is larger or smaller depending on the difference between the speed of the bullet and the speed of sound. If the difference of the flight time of the bullet and sound at 1200 feet were .2 seconds, you would calculate (T2 - T1) the muzzle report traveled 400 yards in .2 seconds. The speed of sound would still take 1.06 seconds to travel 1200 feet. Regardless of what T2 - T1 indicates, the muzzle report will travel 1200 feet in 1.06 seconds. The difference between the two report times indicates the difference in the velocity of time and the velocity of the bullet. If the sound took 1.06 seconds, the distance was 1200 feet. With the known distance, the velocity of the bullet can be calculated.

NOTE: "1.07 * FPS of 1130.8 = 1208.8" is incorrect. 1.07 * 1130.8 = 1209.956.

NOTE: In the next mention FPS is 1130 ft per second at 72 degrees.

NOTE: If you are measuring time between two different gunshots, rather than a shot and its own echo, you cannot derive distance. You would be measuring the time between two shots, saying nothing of distance about either one.

The sounds are all from the Taxi Lady recording.

These sounds do not give the aiming point, or point of origin of the shots.

These sounds give the time sounds were recorded at the taxi.

A sound that traveled 1.07 seconds at the speed of sound went 1,209.1 feet. (1,130 * 1.07).

You cannot measure the Echo Distance from the aiming point back to the point of origin as there is no recording at the point of origin, the point of origin being the 32nd floor (supposedly). Both links go to the taxi video. The Echo Distance is from the point the sound reflected back, to the taxi location where it was recorded, following the path of the sound at ground level back to the taxi.

What is recorded on the Taxi Lady video is the sound that traveled from the 32nd floor to the taxi, and whatever may have come from elsewhere as a sound reflected back. For a sound and its echo to show up on the taxi video at a 1.07 second interval, it had to travel to a reflective surface and back in 1.07 seconds, going a total distance of 1,209.1 feet. The event venue was about 400 yards away.

For any recorded echo, the sound of the shot had to travel to the taxi, and the sound also had to travel from the 32nd floor to a reflecting surface and come back to the taxi. If the echo came from the venue area, 400 yards away, the echoed sound had to travel 400 yards to a reflective surface, then turn around and travel at least 400 yards, if the path were unobstructed at ground level, to the taxi location.

If 1,209.1 feet were one way, the round trip out and back to the 32nd floor would be about 2,418.2 feet. The path back to the taxi, if unobstructed would be somewhat shorter, as 1,209.1 would be the hypotenuse of a triangle, with the distance back to the taxi being the long side of the right triangle, if unobstructed. Any obstructions at ground level would cause the sound to take an indirect path back to the taxi.

You can make pretty graphics, and wonderful word salads, and throw around terms like relativity, but you cannot do simple calculation.

Your analysis is pretty, but it is complete bullshit. No echo traveled to the venue and returned in 1.07 seconds. For a sound recorded in the taxi, there can be no corresponding echo of that sound recorded 1.07 seconds later in the taxi, if the echo came from the venue area.

https://www.nytimes.com/interactive/2017/10/02/us/mandalay-bay-vegas-shooting.html

Las Vegas Shooting: Chaos at a Concert
and a Frantic Search at Mandalay Bay

New York Times
UPDATED 10:30 PM ET, OCT. 2, 2017

Here is where 400 yards or 1200 feet come from. It is an estimated distance between Mandalay Bay and the Harvest Festival stage, at ground level, based on a Google image.

As for your bullshit figure of 1209 feet distance for the bullet, it has a major problem. The approximate 400 yards you are using as known distance was measured at ground level from a google image. In the scenario where the gunman is at the 32nd floor, and floors average 10.9 feet, the gunman is about 338 feet in the air. You would have 338 feet be the short side of a right triangle, where the hypotenuse is 1209 feet. The long side of the right triangle, representing distance at ground level would be 1,160.79 feet.

a² + b² = c²

338² + x² = 1209²

114244 + x² = 1461681

x² = 1461681 - 114244

x² = 1347437

x = 1160.79 feet.

50 feet here, 50 feet there, pretty soon it affects your calculations.

Your chartoon lists "Test for Echo" and gives links to the Taxi Driver video.

That's right.

What part of TWO. SEPARATE. ANALYSIS. are you failing to comprehend?

That you reproduce meaningless bullshit is meaningful

The amplitude graphs are reproducible by anyone who has simple tools and access to the video on Youtube.

Where's yours?

What part of TWO. SEPARATE. ANALYSIS. are you failing to comprehend?

What part of TWO idiotic analyses don't you understand?

The amplitude graphs are reproducible...

Proving imbeciles can reproduce. As the U.S. Supreme Court observed, "Three generations of imbeciles are enough."

Your chartoons, with your hilarious analysis, are entertaining, sort of like the scientific sounding youtubers preaching flat Earth theory.

Where's yours?

{ shrug } Maybe you just don't have what it takes.

Maybe you just don't have what it takes.

On your spreadsheet chartoon, notice that you calculate T = T_b - T_s.

You calculate elapsed time as the time it took the bullet to travel, minus the time it took the sound to travel.

As the bullet is supersonic, and sound is a constant, the sound would travel 400 yards in 1.06s and the bullet would travel the 400 yards in less than 1.06s. Subtracting 1.06 from a smaller number will always yield a negative number.

At 1200 feet, you actually calculate T_b as 0.448578s, and T_s as 1.062s and calculate the T as -0.6126, negative 0.6126 seconds. The average donkey could recognize that something is wrong when the result is negative time.

Just what do you think happens in negative 0.6126 seconds?

You could at least recognize that if you get a negative number, you have stated the required formula backwards, and you proceeded to perform the calculation backwards, and present the bass ackwards result of your understanding of the study you looked at.

You've got what it takes to make bullets travel in negative time.

Your brain apparently has zero amplitude.

>>at 1200 feet, you actually calculate T_b  as 0.448578s, and T_s as 1.062s and calculate the T as -0.6126, negative 0.6126 seconds.

0.448578 is the ballistic projectile time. 1.062 is the time to travel the same distance at the speed of sound

The MEASURED, absolute value, of the Ellapsed Time difference, per the audio amplitude graph...

...between the Last Bullet sound event and the Last Report sound event is 0.689655 

Now, ask your donkey - what distance does that MEASURED absolute time difference correspond to on the chart?

Now, ask your donkey - what distance does that MEASURED absolute time difference correspond to on the chart?

No Absolute value is ever expressed as a negative number. Had your undisclosed formula for the last column of your spreadsheet included code to express an absolute value, your spreadsheet results would not appear as negative numbers. But your spreadsheet displays negative numbers and you did not even question it or fix your spreadsheet.

The results should all be positive, like this:

Bullet Time, Velocity FPS, T_b–T_s

d = distance 400 yards, 1200 feet
T_b = Time of bullet
T_s = Time of sound, 1.062 seconds @ 1,130 feet per second (FPS) (72ºF, 20% Humidity)
T_s – T_b = Time difference between T_b and T_s

Column 1 = d/FPS = time in seconds
Column 2 = T_b stepped in 100 FPS increments, beginning with T_s
Column 3 = T_s – T_b (time in seconds supersonic bullet arrives ahead of sound)

Row 1 = directly inserted data. Data display is set to show 3 decimal places.

• 1.062947 is the time for sound to travel 400 yds/1200 ft.

• 1130 is the distance sound travels in one second. Here it is stated as an assumed bullet average velocity over 400 yds/1200 ft.

• 0.000 is the time difference between a bullet traveling the speed of sound over 1200 ft and sound traveling 1200 feet.

Row 2 = spreadsheet formulas

• Column 1 = 1200 / column 2 (distance / bullet avg velocity) bullet travel time for 1200 ft.

• Column 2 = Row 1, Col 1 + 100 (stepping the assumed bullet velocity by 100 fps).

• Column 3 = 1.061947 - Row 2, Col 1 (time of sound @1200 ft - time of bullet travel) = time diff between time of sound and time of bullet at 1200 ft.

The formulas for Row 2 are dragged down to generate Rows 3-30.

Bullet time (s), Bullet average velocity (FPS), time difference to sound at 1,200 feet (s)

>>No Absolute value is ever expressed as a negative number.

 

https://www.mathsisfun.com/numbers/absolute-value.html

===========

Since we KNOW from the observed audio Vb is supersonic, we can treat the difference between Tb and Ts as Absolute.

Range corresponds to the ABSOLUTE value of the difference in time.

And BTW, You're not even reading from the relevant part of the paper - where the microphone adjacent to the victim scenario is discussed.

http://ww w.btgresearch.org/AcousticReconstruction02042012.pdf

That's the same formula I have in my illustration:

Since we KNOW from the observed audio Vb is supersonic, we can treat the difference between Tb and Ts as Absolute.

I know. They have a spreadsheet function for that. It has been around since Lotus 123 and Quatro. ABS(number).

They have a spreadsheet function for that.

Yes, but in this case the ABS is implied in knowledge of what the spreadsheet is actually calculating.

If you applied ABS(Tb-Ts-) the chart would loose the information regarding whether the Vb was super-sonic or not, which the negative numbers conveniently tell us.

The author's formula works just fine without your tweakage.

http://ww w.btgresearch.org/AcousticReconstruction02042012.pdf

And that IS the same formula I have in my illustration:

Why do you keep posting this chartoon when all your data is not only wrong, but farcical? The only things you proved is that you do not know how to calculate the average velocity of an imaginary bullet and you are hopeless at spreadsheets. Your entertainment value as a useful idiot is over for now, and you will never figure it out without more help. Help is on the way, grasshopper.

Columns 1, 2, and 3 are direct entry of data generated by entering imaginary data into a generator at http://www.shooterscalculator.com/. I replicated the data taken from the calculator with “My BB's.” If I input initial velocity as 3240 fps, and other data, and call it “My BB's,” I can show a chart for magical bb’s.

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=34fa8220

The Shooter’s Calculator only provides a result based on user input. It does not present a spreadsheet with the formulas to generate the data. The data from the Calculator can be cut and pasted into a spreadsheet, or entered by direct entry; this produces data in the cells, but no spreadsheet formulas in the cells. The chart states the speed of sound as 1130 feet per second (fps).

The remaining 4 columns, (4, 5, 6, 7) were generated by VxH.

Column 6 uses 1130.8 fps to calculate the time for sound to travel the distance stated in Column 1.

Column 4 is labeled as (Avg V) Vb. This column purports to present the average velocity of the bullet to cover the distance for the row it is in. All of the data in this column is epically wrong as the methodology of calculation is absurdly wrong.

To calculate the average velocity of the bullet, divide distance by time.

Instead of this, a personal misbegotten formula was used. Probably a pocket calculator for each cell in Column 4 was used to perform the calculations, and the data was directly entered into the cells by hand.

For the first two data rows, sum 3240 and 3163 and divide by 2. 6403/2 yields the 3201 in Column 4.

For the first three data rows, sum 3240+3163+3088 for 9491. 9491 / 3 yields the 3163.6667 in Column 4.

And so on, and so forth. All the calculated Column 4 data (average Vb), is garbage.

The chosen methodology was to sum the velocity given for each distance, and divide by the number of elements summed. This produces nonsensical data.

Example: You drive a car 100 miles at 80 mph. You drive another 100 miles at 20 mph. With this bogus methodology, 80 + 20 = 100, divide by 2, and your average velocity was 50 mph. Not.

In the real world, you drove 100/80 or 1.25 hours at 80 mph. You drove 100/20 or 5 hours at 20 mph. And you drove 200 miles in 6.25 hours. Your average speed was 200/6.25, or 32 mph.

Column 4, in addition to using an absurd methodology for its calculations, also incorporates two summing errors for the velocities taken from Column 3, at 900 feet and 1275 ft. In each case, the actual sum was 1 less than that calculated.

Spreadsheet formulas are not prone to fat finger syndrome, and do not make such errors, but someone with a pocket calculator or pen and paper does. The data was typed in after external calculation.

Where you calculate 2367.5926 average Vb at 1950 feet, 1950/1.211933 (the velocity of the bullet in Column 5), it yields 1608.9998 fps, remarkably close to the 1609 in Column 3. But then, the elapsed time in Column 2 is 0.86, not 1.21933. It is a conundrum how the bullet traveled for 1.21933 seconds in an elapsed time of 0.86 seconds.

Of course, when you use Column 1 1950 ft and Column 3 1609 fps to derive the time of flight, the formula is d/Vb, and Vb is the Average Velocity.

The bullet will travel 1905 feet distance (Col 1) in 0.86 sec time (Col 2) in 1905/0.86 or 2267.4418 average Vb. Stated in your headnote is Tb is d/Vb.

It is noteworthy that you used Column 3 as the "average" velocity of the bullet in order to derive the other average velocity of the bullet in Column 4.

Column 5 (Tb) incorporates the garbage data from Column 4 into its calculations, and all the resulting calculated data is wrong. GIGO.

Column 7 (T = Tb – Ts) incorporates the garbage data from Column 5 and all the calculated data is wrong. GIGO.

The chart is multicolor and pretty, but the data for the imaginary bullet is demonstrably wrong in every column you created, except for column 6 where you succeeded in dividing the distance by 1130.8.

LOL please tell the class why the bullet accelerates / decelerates / accelerates repeatedly when your "analysis" is applied?

The time in the chart rendered by the ballistic calculator only has 2 decimals of precision.

Calculating the average per the reported velocity is thus more accurate.

>> and the data was directly entered into the cells by hand.

Bzzzt.  Fail again.

d is the target distance.(range)
Vs is the velocity of sound, and
Vb is the average bullet velocity over the distance
Tb is d / Vb (time to cover distance @ Vb)
Ts is d/Vs (time to cover distance @Vs)

LOL please tell the class why the bullet accelerates / decelerates / accelerates repeatedly when your "analysis" is applied?

The time in the chart rendered by the ballistic calculator only has 2 decimals of precision.

Calculating the average per the reported velocity is thus more accurate.

More accurate is to divide the distance by the velocity and get the time to more decimal places and eliminate the rounding error. Your bullshit methodology of summing velocities and dividing does not work. It is bullshit.

Your chart in Column 2 from btgresearch indicates Tb for range 1950 is 0.86 seconds. Column 5 for 1950 range indicates Tb is 0.823621. You call that fixing a rounding error???? How did displaying only two decimal places to 0.86 convert to 0.823621.

Of course, the time of 0.02 could represent a figure rounded to two decimal places for presentation, and actually represent anything from 0.0150 to 0.0249.

75 feet divided by Vel[x] 3239 75/3239 feet, taken to six decimal places gives 0.0231552 seconds bullet travel time. Hot damn, it's within the rounding error.

At Vel[x+y] 3240 feet per second, and 75 feet distance, the time to six decimal places would be 0.0231481 seconds bullet travel time and hot damn, that's within the rounding error too.

You have the distance and velocity as a given from btgresearch. Divide the distance by the velocity d/V, and you can calculate the time to however many decimal places you desire.

The stupid... it hurts!

The chart results are based on the data you entered.

As I demonstratred, the same data entered for My BB's produces a chart with the same data for BB's.

If the chart correctly calculated the ballistic data for the parameters you entered,

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=34fa8220

Tell everybody how you derived average velocity.

Come on. Question my analysis of how you made a botch of the Average Bullet Velocity. Give us your methodology and formula.

Why were all your calculations wrong except for distance divided by time?

The data which you input did not come from any real life ammunition, you just entered stuff, as I did for My BB's. I just entered the same stuff you did, proving my bb's have an initial Vel[x+y] of 3240 fps. My BB's perform precisely as do your imaginary cartridge. Are you saying the ballistics chart you used produced invalid results?

If the chart results are valid, please tell the class why the chart indicates the bullet traveled 75 ft. in 0.02 seconds and that indicates average velocity d/time of 750/.02 = 3750 fps.

It's your data. If the ballistics chart calculated correctly, you should understand the chart you presented, and be able to explain the results given.

Do you think you are entitled to just use a nonsense formula which produces nosense results because you do not understand the chart data that you selected and presented?

The note at the bottom of the chart indicates:

Keep in mind this is an approximation....

Thank you, Lord.

and the data was directly entered into the cells by hand.

Bzzzt. Fail again.

Nope. You said you created spreadsheet and used their formulas. Had you used their formulas you would not have bullshit results, including arithmetic errors in the columns.

Which formula of theirs did you use to manufacture the wrong bullet velocities?

Cite any source that says to find average velocity with the method you used.

When you introduced this bullshit on the other thread at your #19 to A K A Stone, you said:

https://libertysflame.com/cgi-bin/readart.cgi?ArtNum=53046&Disp=19#C19

I found/took their formula, built a spreadsheet, and plugged in 223 balistic data generated via shooterscalculator.com:

Only you did not use their formulas or you would not have gotten all the data you derived bass ackwards wrong, and you did not create formulas and drag them down through the rows, or you would not have the calculation errors the are apparent.

I created a spreadsheet using the same data and created formulas and dragged them down through the rows. They work. That is how I can pinpoint where you made calculating errors in your data entry.

All you did was cut and paste the chart data into a spreadsheet workbook.

Columns 1 thru 3 were cut and paste.

For Column 4, there is no chance that you created a formula and dragged it down through the rows. You go off at range 900 where you summed to 36497 instead of 36496. This error of 1 continues through to range 1275, where you summed to 47,572 instead of 45,570. This put the summing error at 2, which continued through range 1950 where you ended.

This is not a spreadsheet error. I used two different formulas to sum the velocities, with results identical to each other. You used no formula. You sat there with your pocket calculator and added the first two and typed in the result. Then you added the third velocity and typed in the result. And you did this for each data entry in that column. If you have any spreadsheet formula that can replicate your results, produce it.

As Column 4 calculates the sum of the velocities divided by the number of velocities, and the sum of the velocities was not created by a formula on a spreadsheet column, the column was manual data entry.

In Column 5, d/Vb, the distance is correctly divided by the bogus average velocity, yielding a bogus result. When it is as simple as programming one column divided by another, good job. When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.

In Column 6, I stated you were able to divide distance by 1130.8. When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.

In Column 7, you managed to correctly subtract the bogus data in Column 5 from the bogus data in Column 6, yielding all bogus results. When it is as simple as programming one column subtracted from another, good job. It should have included an ABS function to avoid getting negative time results.When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.

As Columns 5 and 7 incorporate the brain dead data in Column 4, with a double whammy of a bogus formula and calculation errors, all data in Columns 5 and 7 is bogus.

Your chart in Column 2 from btgresearch indicates Tb for range 1950 is 0.86 seconds. Column 5 for 1950 range indicates Tb is 0.823621. You call that fixing a rounding error???? How did displaying only two decimal places to 0.86 convert to 0.823621????

As Column 4 calculates the sum of the velocities divided by the number of velocities, and the sum of the velocities was not created by a formula on a spreadsheet column, the column was manual data entry.

Bzzzt. Another Nolu-FAIL.

=SUM(C9:C10)/L9
=SUM(C$9:C11)/L10
=SUM(C$9:C12)/L11
etc.
Where column L contains 1 @ row 8 and =+L8+1, =+L9+1 etc for rows 9..34

Now please tell us how Nolu-Time works and then explain why the values of Column J are closer to Time (Column B) than Nolu-Time(Column I)?

"more accurate is to divide the distance by the velocity and get the time to more decimal places

nolu chan    posted on  2017-10-28   18:47:52 ET 

https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53025&Disp=153#C153

You stipulate a DISTANCE ratio of 99:1. Nice try.

I correctly illustrate the flaw inherent in taking a momentary point velocity of a continuously decelerating proctile and ASSuming it to be an average.

There's a question regarding whether the value of Vel[x+y] for a given 75ft vector segment is the average Velocity OR whether it's just the momentry V at point d.

Here is the spreadsheet updated with Tcalc where Tcalc is an attempt to reconstruct the elapsed Time for a given Vector:

We're moving in the right direction - but the calculation for Tcalc could be even more accurate by deriving it from the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment, rather than taking momentary V at point d and ASSuming it's a constant velocity over the entire 75ft segment... like you are.

Chan is kicking your ass and you are looking foolish with all your errors.

Says the genius who posts videos with scribbling on a whiteboard presented as "PROOF".

Can you solve for T given a 75 foot vector having Vmin and Vmax?

Let's see if Noluchan's donkey can!

How's that workin' for ya?

Meanwhile:

Q: Can you solve for T given a 75 foot vector having Vmin and Vmax?
A: { crickets crickets crickets }

Could you provide me a list of all of your errors that you posted so I can remove them from the site so people don't look at bullshit?

Blue 42 Blue 42 hut hut hike.

Ok I proved you are wrong.

How do you determine your opinion?

My mind it is a beautiful thing.

You agree with his analysis 100 percent correct.

Or is your mind superior like mine and know that his analysis is bullshit. To many errors. To many things not factored in.

I'm not saying that there were multiple shooters. I'm not saying Pollock or Paddock or whatever his name was didn't act alone.

I'm just saying what V dude offers as 100 percent conclusive proof is not conclusive or proof.

Says the genius who posts videos with scribbling on a whiteboard presented as "PROOF".

Says the genius who made up an image with lots of wrong and made up numbers.

I know the truth know. Spock is controlling your mind.

Does that work in AKA Stoned Land?

There's nothing wrong with refining an analysis in the context of an honest desire to seek the truth.

Time is still not being calculated with 100% accuracy. Why is that?

Truth is great and will prevail unless deprived of her natural weapons, free argument and debate.

Does that work in AKA Stoned Land?

That is fine.

Truth also works if false things are no longer out there.

If you care about truth why don't you find a list of all the posts yoy made with errors so we can correct them with the latest and the greatest.

If you care about truth why don't you find a list of all the posts yoy made with errors

In this case, the truth is still a work in process.

For the next step in the process - Maybe "yoy" and Noluchan's donkey can tell us why applying a linear calculation (d/v) to a non-linear velocity produces values for Time which are farther away from the Ballistic chart's value for T than rounding can explain?

Maybe you and Noluchan's donkey can tell us why applying a linear calculation (d/v) to a non-linear velocity produces values for Time which are farther away from the Ballistic chart's value for T than rounding can explain?

ROTFL

{ crickets crickets crickets }

So,

Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel
Illustration B: Vb using my original Average of summed Velocity values.

A: B:

Please explain how, in the context of the highlighted range of interest on the concert field, Noluchan's idea to reconstruct Time by taking (d=75ft)/Vel[x+y]
 does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into "bullshit"

?

Feel free to consult Noluchan's Donkey, since it probably has better temperament and reading comprehension skills than either of you two have demonstrated.

I correctly illustrate the flaw inherent in taking a momentary point velocity of a continuously decelerating proctile and ASSuming it to be an average.

There's a question regarding whether the value of Vel[x+y] for a given 75ft vector segment is the average Velocity OR whether it's just the momentry V at point d.

The problem is that you are clueless and do not know what your are doing and do not know what a vector is.

Here is a correct spreadsheet:

BALLISTICS DATA SPREADSHEET

As a vector is described by a line and not a point, the Column D velocity at 75 feet describes the average bullet velocity for the segment from 0 to 75 feet, and the velocity at 150 feet describes the average bullet velocity from 0 to 150 feet, and so on.

The time for 75 feet indicates the elapsed time for 0 to 75 feet. The time for 150 feet indicates the elapsed time for 0 to 150 feet.

Column C, the time, is derived by dividing Column B (distance) by Column D. In your chart it is was rounded off to two decimal places. I took it to four decimal places.

Your added Rube Goldberg nonsense was not only wrong but unecessary. Average velocity at the stated distances was staring you in the face.

In Columns H thru L, I have provided the data for each 75-foot segment.

At 1575 feet, the bullet opens its largest gap on sound at 0.05502 seconds.

From 1575 to 1650 feet, the bullet travels at an average velocity of 1127.9144 fps, dipping below the speed of sound. After that, sound is traveling faster than the bullet and the gap diminishes.

>>Here is a correct spreadsheet

Too bad it's not one you created with ballistic data as per the methodology:

http://www.btgr esearch.org/AcousticReconstruction02042012.pdf

Meanwhile,

Please explain how, in the context of the highlighted range of interest on the concert field, Your idea to reconstruct Time by taking (d=75ft)/Vel[x+y] does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into " bullshit"

?

Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel
Illustration B: Vb using my original Average of summed Velocity values.

A:  B:

Please explain how, in the context of the highlighted range of interest on the concert field, Noluchan's idea to reconstruct Time by taking (d=75ft)/Vel[x+y]
 does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into " bullshit"

?

There are experts out there. So why aren't we hearing from them? Is it because they find the audio data to be ambiguous? Who knows.

There are experts out there. So why aren't we hearing from them?

I asked the authors of the study

http://www.btgresearch.org/AcousticReconstruction02042012.pdf

They replied:

"our standard operating procedure is to avoid public comments on shooting events. This better protects our neutrality and value of our analysis in the event that we are retained by an agency or party to subsequent legal proceedings. We also like to restrict our analysis to materials that come into our possession following a proper and documented chain of custody regarding handling of evidence.

When it comes time for depositions or courtroom testimony, most experts who have made prior public comments on a matter find that opposing legal counsel, opposing experts, and the blogosphere find ways to make them regret earlier public comments."

===============

In light of what can be observed here - that makes sense.

Well, it is an explanation.

Yeah. In the meantime, I've found this exercise to be a worthwhile learning experience.

At 1950 ft your "spreadsheet" has an elapsed time of 1.2119 with a corresponding Vel[x+y] of 1609.

Meanwhile observe the corresponding elapsed time and Vel[x+y] generated by:

ShooterCalculator.com

OOPS!

How'd ya manage to do that, Professor DonkyChan? 

Yeah. In the meantime, I've found this exercise to be a worthwhile learning experience.

I'm not telling you to stop or that you're wasting your time. You might stumble over something unnoticed by everyone. Recall how Dan Rather was brought down by a persistent guy that noticed the fonts in the fake documents about Dumbya's military service.

Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel

If your Column c, Vel[x+y] (ft/s) represents an instantaneous velocity, it cannot be used in this manner.

Make up your mind, does Column C represent instantaneous velocities, valid only at a single point, and not over any range?

it cannot be used in this manner.

Says the Donkey who managed to transform 0.86 seconds into 1.2119 seconds.

Meanwhile...

http://www.answers.com/Q /What_is_instantaneous_slope

As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105 the next step in the quest is to explore methods of deriving Time relative to the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment.

Meanwhile...

http://www.answers.com/Q /What_is_instantaneous_slope

As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105 the next step in the quest is to explore methods of deriving Time relative to the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment.

To find what is at your source, we go to the link, which, like the link to the Khan Academy, only shows that you are bullshitting.

You seem to have a special affinity in providing cut and paste bullshit as as some sort of profound knowledge.

http://www.answers.com/Q/What_is_instantaneous_slope

Answer byBlue
Confidence votes 38.3K

The instantaneous slope of a curve is the slope of that curve at a single point. In calculus, this is called the derivative. It also might be called the line tangent to the curve at a point.

If you imagine an arbitrary curve (just any curve) with two points on it (point P and point Q), the slope between P and Q is the slope of the line connecting those two points. This is called a secant line. If you keep P where it is and slide Q closer and closer to P along the curve, the secant line will change slope as it gets smaller and smaller. When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P.

Mathematically, we say that the slope at P = limh—>0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x.

The formula above is a specific case where the derivative is in terms of x and we're dealing with two dimensions. In physics, the instantaneous slope (derivative) of a position function is velocity, the derivative of velocity is acceleration, and the derivative of acceleration is jerk.

Of course, the calculus formula P = limh—>0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x was not used anywhere in your spreadsheet, so you are just bullshitting.

Also,

When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P.

However, the slope of a bullet in flight is constantly changing, the deceleration is not constant, and the slope contains an infinite number of points.

Moreover, you have merely bullshitted and have not described any formula to obtain the average velocity of the bullet over a given range, using instantaneous velocities.

While you claim calculus formulas in your spreadsheet, you have yet to show a formula to sum changing parts of a spreadsheet column, i.e., sum row 1 and 2, sum row 1 thru 3, then row 1 thru 4, and so forth. I used such a formula and it showed that your column contained arithmetical errors not created by a spreadsheet formula. When you can program adding sums, I'll consider you doing calculus. As it is, you have not demostrated the ability to consistently add two numbers together, which is what you did to to sum that column. You added rows 1 and 2 to get the row 2 total; then you added row 3 to get the row 3 total, and so on, making two errors in 26 rows. You are fortunate it was now a thousand rows on a spreadsheet in a finance office.

The formula for calculating average velocity (d/t) is given by the Khan Academy in the video you referenced. In their example, they divide a distance fo 1000m by 200s and get an average velocity of 5 m/s, and then they explicitly state, that siad result "doesn't necessarily equal the instantaneous velocities at particular points."

The Khan Academy does not say that you can sum two instantaneous velocities and divide by two, and get an average velocity between the two points. See what you referenced. The first sentence is important — pretend you are a physics student.

https://www.khanacademy.org/science/physics/one-dimensional-motion/displacement-velocity-time/v/instantaneous-speed-and-velocity

Video transcript

- [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time.

And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.

Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip.

In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second.

Just as your instantaneous velocity at two discrete and infinitesimal points can not be summed and divided by two to obtain average velocity, the instantaneous slope at two discrete and infinitesimal points will be different and cannot be used to calculate the slope of a traveling bullet whose velocity is contantly changing.

While this bullshit about instantaneous slopes has diverted from your other bullshit about instantaneous velocities, you are still left searching to explain

(1) your calculation used to derive average velocity over the specified distances,

(2) your calculation used to change the formula for calculating average velocity over distance.

Your chart stipulated distance and time.

For 75 feet, you stipulated 0.02 seconds. This is your data, not mine.

Using the formula, d/t=V(avg), that is 3,750 feet per second average velocity.

If we assume that you meant the time to be anything between 0.015 and 0.025 seconds, that is 3000 - 5000 feet per second average velocity.

For 1950 feet, you stipulated 0.86 seconds, and an average velocity of 2367.5926 feet per second, obtained by a formula you can neither present nor explain, nor can you provide any citation to any authority for your bullshit calculation.

V(avg) = d/t = 1950/0.86 = 2267.4418 feet per second average velocity.

If we assume that you meant the time to be anything between 0.855 and 0.865, then,

V(avg) may equal 1950/0.0855 = 2280.7017

V(avg) may equal 1950/0.0865 = 2254.3353

Meanwhile, your bullshit 2367.5926 average velocity allows one to derive the time required to travel 1950 feet. 1950/2367.5926 = 0.823621429 seconds.

Indeed, your second time for Tb, the time of the bullet, in your column E, reflects a bullet flight time of 0.823621 seconds, giving three less decimal points than I did, but rounding the the same precise thing at your chosen four decimal places, indicating how you derived that bullshit Tb from the bullshit average velocity.

To check whether this bullshit time is not impossible with the stipulated data, one need only check if it is within the rounding possibilities of the stipulated data, i.e., from 0.855 to 0.865 seconds. Oh noes, your bullshit average velocity (0.823621) is not possible to reconcile with the stiplulated time, even allowing for the maximum rounding error. Your misbegotten time would round to 0.82 instead of 0.86.

You have yet to explain how you can stipulate a bullet time of 0.86 seconds, and through the magic of VxH formulas, transform that time into 0.823621 seconds, and then use that visibly bullshit time to perform further bullshit calculations.

If the bullet flew 1950 feet in 0.823621, why sure enough it went at an average velocity of 2367.5938 and covered 1950 feet.

However, at the stipulated time of 0.86 seconds, at the bullshit average velocity of 2367.5938 feet per second, the bullet would have flown 2036.1307 feet. The stipulated distance is 1950 feet.

At the maximum rounding down error to 0.855 seconds, at your bullshit average velocity of 2367.5926, the bullet would have flown 2024.292699 feet (0.855 x 2367.5926). The stipulated distance is 1950 feet.

With your stipulated data, you may not have more or less than 1950 feet. You may not have less than 0.855 seconds flight time, nor more than 0.865 seconds flight time. You cannot change the distance the bullet flew, nor do more than consider a rounding error on the time. Your calculated numbers fail miserably.

Your bullshit calculated numbers fall outside the maximum possible error attributable to a rounding error.

Your bullshit calculations result in a new time, not within any rounding error, replacing 0.86 with 0.823621.

Your bullshit average velocity over 1950 feet (2367.5926), at the maximum rounding error for stipulated time (0.86 rounded down to 0.855), requires the bullet to fly a minimum of 2024.292699 feet.

WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???

LOL. Idiot.

ShooterCalculator.com Says:

========================

Professor DonkeyChan says:

4

d

Time

(avg) Vel[x+y]

5

(ft)

d/Vel[x+y]

(ft/s)

32

1950

1.2119

1609

1.2119 seconds

nolu chan     posted on  2017-10-30   19:58:41 ET

https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53025&Disp=160#C160

Unresponsive obfuscatory yukonesque bullshit

WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???

Column B of above spreadsheet shows the specified distance and the specified time for that distance.

Column C shows the specified time for the distance traveled.

Column D shows the time rounded down to the minimum time possibly explained by rounding.

Column E shows the time rounded up to the maximum time possibly explained by rounding.

Column F shows the Average Velocity (d/t) calculated with the unadjusted time from Column C.

Column G shows the Average Velocity (d/t) calculated with the minimum time possible from Column D. This minimum time of flight shows the maximum possible average velocity of the bullet.

Column H shows the Average Velocity (d/t) calculsted with the maximum time possible from Column E. This maximum time of flight show the minimum average velocity of the bullet.

Column I shows the time for sound to travel the distance at 1130 fps.

Column J shows the time difference between the bullet and the sound using unadjusted time from Column C.

Column K shows the maximum possible time difference between the bullet and the sound using the time rounded down in Column D.

Column L shows the minimum possible time difference between the bullet and the sound using the time rounded up in Column E.

Column N states VXH Average Velocity using undisclosed math, presumably of Klingon origin.

Column O states the instantaneous velocities at the distances specified in Column B. These velocities reflect a specific and infinitesimal point it time only, and do not describe velocity at any other point in time.

Comparing Columns H and N, Column H calculates the maximum possible average velocity with the time round down as far is is possible. Column N is the average velocity claimed by VxH, using his secret Klingon mathematics.

Notice his secret method obtain an average velocity well below the maximum possible for 75 feet, but comes nearer to the maximum possible with every calculation, and at 1200 feet his calculations leave the realm of the possible.

At 1200 feet, at the specified time of 0.46 seconds, the average velocity would be 2608.70 feet per second (1200/0.46). Anyone can do the arithmetic. At 1200 feet, at 0.46 seconds rounded down as far as possible to 0.455 seconds (Column D), the maximum average veocity of 2637.36 feet per second (Column G) is achieved (2637.36/0.455). Anyone can still do the arithmetic. At this point, the VxH calculations exceed the possibilities of reality and achieve 2675.1176 feet per second.

After this point, every VxH calculation widens the error.

At 1950 feet, the Column G max average velocity is 2280.70 (1950/0.0855). After more calculations, the VxH error expands the difference to 2367.5926 feet per second.

If carried on to further distances, the error will simply keep increasing. He started with 64% of the maximum possible average velocity, and surpassed 100% of the maximum on his 16th calculation, and continued to surpass the maximum possible average velocity by a greater and greater amount.

Moreover, the distance and the time were a given.

....d ........ t ... Vxh

...ft........ sec .... sec per VxH

   75      0.02     0.023427     
  150     0.05     0.047413
  225     0.07     0.071971
  300     0.10     0.097113
  375     0.12     0.122843
  450     0.15     0.149183
  525     0.18     0.176138
  600     0.20     0.203720
  675     0.23     0.231943
  750     0.26     0.260820
  825     0.29     0.290357
  900     0.32     0.320574
  975     0.36     0.351496
1050     0.39     0.383128
1125     0.42     0.415484
1200    0.46     0.448578
1275    0.49     0.482427
1350    0.53     0.517054
1425    0.56     0.552465
1500    0.60     0.588675
1575    0.64     0.625711
1650    0.68     0.663578
1725    0.73     0.702290
1800    0.77     0.741864
1875    0.81     0.782303
1950    0.86     0.082621

Notice how VxH, in his calculations, at and after 1200 feet, reduces the time of flight of the bullet by more than any possible amount of rounding from two decimal places.

By 1950 feet, VxH has "rounded off" 0.86 and amazingly reduced the stated flight time to his own preferred 0.82621.

>>By 1950 feet, VxH has "rounded off" 0.86

Nope. Not a rounding error Super Genius.  It's an artifact manufacted from the AVERAGING curve.

>>preferred 0.82621.

Nope. Try to keep up - - I've moved on with a revised curve that reconstructs time from Velocity and Distance,

As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105  the next step in the quest is to explore methods of deriving Time relative to  the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment.

So, Professor DonkeyChan -- Here is the ballistic data table generated for 1 yard intervals from 1875 to 1950 ft.

http://www.shooterscalculator.com/ballistic- trajectory-chart.php? pl=223+RemingtonLVA&presets=223+RemingtonLVA~%5BChart+Label%5D~G1~0.300~62~3240~ 100~1.5~-33~0~0~true~2000~72~29.92~21~true~1000~25&df=G1&bc=0.300&bw=62& amp; amp; amp; amp;vi=3240&zr=100&sh=1.5&sa=-33&ws=0&wa=0&cfa=on&alt=0& amp; amp; amp; amp;tmp=72&bar=29.92&hum=21&ssb=on&cr=1000&ss=1&chartColumns =Range~ft%3BTime~s%3BVel%5Bx%2By%5D~ft%2Fs&lbl=Test&submitst=+Create+Chart+

Range	Time	Vel[x+y]
(ft)	(s)	(ft/s)
1875	0.81	1658
1878	0.81	1656
1881	0.82	1654
1884	0.82	1652
1887	0.82	1650
1890	0.82	1648
1893	0.82	1646
1896	0.83	1644
1899	0.83	1642
1902	0.83	1640
1905	0.83	1638
1908	0.83	1636
1911	0.83	1634
1914	0.84	1632
1917	0.84	1630
1920	0.84	1628
1923	0.84	1626
1926	0.84	1624
1929	0.85	1622
1932	0.85	1621
1935	0.85	1619
1938	0.85	1617
1941	0.85	1615
1944	0.86	1613
1947	0.86	1611
1950	0.86	1609

Give it up you are looking foolish.

Nah, foolish is not knowing that in order to recreate the ballistic data curve (and thus the average Velocity over a given distance) with complete accuracy would require duplicating the function used in the Ballistic chart generator.

Meanwhile, averaging via various methods to get an approximation is completely acceptable - and USEFUL for gaining an understanding into what the audio is telling us.

[VxH #133] Nope. Try to keep up - - I've moved on with a revised curve that reconstructs time from Velocity and Distance,

You have explored methods which require require rewriting the bullet flight times far beyond any possible rounding error. Reconstructing the given travel time is VxH BULLSHIT.

YOUR CALCULATED DATA IS ALL BULLSHIT, AS ARE YOU

Time and distance are given. Rounding the given time up or down does not help your bullshit work. Your bullshit methodology changes the given 0.86 seconds elapsed time to 0.82 seconds.

There is no valid formula in the world for that.

Time and distance are given data. Average velocity equals distance divided by time. Distance in feet, divideded by time in seconds, yields velocity in feet per second.

WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???

Column B of above spreadsheet shows the specified distance and the specified time for that distance.

Column C shows the specified time for the distance traveled.

Column D shows the time rounded down to the minimum time possibly explained by rounding.

Column E shows the time rounded up to the maximum time possibly explained by rounding.

Column F shows the Average Velocity (d/t) calculated with the unadjusted time from Column C.

Column G shows the Average Velocity (d/t) calculated with the minimum time possible from Column D. This minimum time of flight shows the maximum possible average velocity of the bullet.

Column H shows the Average Velocity (d/t) calculsted with the maximum time possible from Column E. This maximum time of flight show the minimum average velocity of the bullet.

Column I shows the time for sound to travel the distance at 1130 fps.

Column J shows the time difference between the bullet and the sound using unadjusted time from Column C.

Column K shows the maximum possible time difference between the bullet and the sound using the time rounded down in Column D.

Column L shows the minimum possible time difference between the bullet and the sound using the time rounded up in Column E.

Column N states VXH Average Velocity using undisclosed math, presumably of Klingon origin.

Column O states the instantaneous velocities at the distances specified in Column B. There velocities reflect a specific and infinitesimal point it time only, and do not describe velocity at any other point in time.

Comparing Columns H and N, Column H calculates the maximum possible average velocity with the time round down as far is is possible. Column N is the average velocity claimed by VxH, using his secret Klingon mathematics.

Notice his secret method obtain an average velocity well below the maximum possible for 75 feet, but comes nearer to the maximum possible with every calculation, and at 1200 feet his calculations leave the realm of the possible.

At 1200 feet, at the specified time of 0.46 seconds, the average velocity would be 2608.70 feet per second (1200/0.46). Anyone can do the arithmetic. At 1200 feet, at 0.46 seconds rounded down as far as possible to 0.455 seconds (Column D), the maximum average veocity of 2637.36 feet per second (Column G) is achieved (2637.36/0.455). Anyone can still do the arithmetic. At this point, the VxH calculations exceed the possibilities of reality and achieve 2675.1176 feet per second.

After this point, every VxH calculation widens the error.

At 1950 feet, the Column G max average velocity is 2280.70 (1950/0.0855). After more calculations, the VxH error expands the difference to 2367.5926 feet per second.

If carried on to further distances, the error will simply keep increasing. He started with 64% of the maximum possible average velocity, and surpassed 100% of the maximum on his 16th calculation, and continued to surpass the maximum possible average velocity by a greater and greater amount.

Moreover, the distance and the time were a given.

d ........ given..........Vxh bullshit

ft.......... sec..... sec

    75     0.02     0.023427     
  150     0.05     0.047413
  225     0.07     0.071971
  300     0.10     0.097113
  375     0.12     0.122843
  450     0.15     0.149183
  525     0.18     0.176138
  600     0.20     0.203720
  675     0.23     0.231943
  750     0.26     0.260820
  825     0.29     0.290357
  900     0.32     0.320574
  975     0.36     0.351496
1050     0.39     0.383128
1125     0.42     0.415484
1200    0.46     0.448578
1275    0.49     0.482427
1350    0.53     0.517054
1425    0.56     0.552465
1500    0.60     0.588675
1575    0.64     0.625711
1650    0.68     0.663578
1725    0.73     0.702290
1800    0.77     0.741864
1875    0.81     0.782303
1950    0.86     0.082621

Notice how VxH, in his calculations, at and after 1200 feet, reduces the time of flight of the bullet by more than any possible amount of rounding from two decimal places.

By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology, the stated flight time to his own preferred 0.82621.

That is VxH bullshit. Not only wrong but impossible on its face.

[VxH]

    1950	0.86	1609

Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)?

The average velocity of any object covering 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4419 feet per second. It could be a flying refrigerator. If it goes 1950 feet in 0.86 seconds, the average velocity is 2267.4419 seconds.

The object could have sped up and slowed down between 0 and 1950 feet in any manner and it makes no difference. If the object covers the 1950 feet in 0.86 seconds, the average velocity for the 1950 foot distance is 2267.4419 seconds.

Recall the Khan Academy video you previously referenced:

https://www.khanacademy.org/science/physics/one-dimensional-motion/displacement-velocity-time/v/instantaneous-speed-and-velocity

Video transcript

- [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time.

And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.

Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip.

In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second.

[snip]

The instantaneous velocity at 1950 feet is irrelevant to the calculation of the average velocity over the range 0 to 1950 feet.

beyond any possible rounding error

LOL. It's not a rounding error Professor DonkeyChan.

How you coming along with that Average Velocity for the 75 foot segment ending at 1950 ft?

How you coming along with that Average Velocity for the 75 foot segment ending at 1950 ft?

It came along quite well. Anything that travels 1950 feet in 1.06 seconds travels an average velocity of 2122.64 feet per second. The formula is distance divided by time.

How are you coming along with your bullet going splat at ~520 feet ground distance from Mandalay Bay?

How did you work out that negative 33º angle?

Side a represents the vertical height of Paddock's vantage point. At the 32nd floor, and at 10.9 feet per floor, (32-1) x 10.9 = 338 feet.

The VxH specified shooting angle was -33°. This should probably be expressed as a positive angle of declination. Not all ballistic calculators will even accept a negative angle value, but specify 0 to 90 degrees.

For another calculator, see:

http://gundata.org/blog/post/223-ballistics-chart/

It appears that VxH drew an imaginary horizontal line d at a vertical height of 338 feet from the ground, and an imaginary 338 foot line e down to the ground, bringing into view a rectangle with a mirror image triangle to that above.

VxH guessed 33º as the acute angle formed at the junction of sides c and imaginary side d at point B. VxH guessed very wrongly.

With a specified shooting angle of 33º at the junction of lines c and d, the angle made by sides c and b would also be 33º, and angle ß, made by sides a and c would be 57º. (The right angle at point A is 90º. The other two angles must add up to 90º.)

With side a being 338 feet, side b would be 520.4743578 feet, and side c would be 620.5944 feet.

As may be seen, disregarding gravity, if the bullet flew downward at the specified 33º from a height of 338 feet, it would fly a straight line of sight path into the ground at ~520 feet from the Mandalay Bay at ground level.

Calculating the bullet velocity after that point may be difficult, even with secret Klingon math.

>>The formula is distance divided by time.

And when you don't have data for time with enough precision - what then, professor Donkeychan?

http://www.shooterscalculator.com/ballistic- trajectory-chart.php? pl=223+RemingtonLVA&presets=223+RemingtonLVA~%5BChart+Label%5D~G1~0.300~ 62~3240~ 100~1.5~-33~0~0~true~2000~72~29.92~21~true~1000~25&df=G1&bc=0.300&am p;bw=62& amp; amp; amp; amp;vi=3240&zr=100&sh=1.5&sa=-33&ws=0&wa=0&cfa=on&am p;alt=0& amp; amp; amp; amp;tmp=72&bar=29.92&hum=21&ssb=on&cr=1000&ss=1&char tColumns =Range~ft%3BTime~s%3BVel%5Bx%2By%5D~ft%2Fs&lbl=Test&submitst=+Create +Chart+

Range	Time	Vel[x+y]
(ft)	(s)	(ft/s)
1875	0.81	1658
1878	0.81	1656
1881	0.82	1654
1884	0.82	1652
1887	0.82	1650
1890	0.82	1648
1893	0.82	1646
1896	0.83	1644
1899	0.83	1642
1902	0.83	1640
1905	0.83	1638
1908	0.83	1636
1911	0.83	1634
1914	0.84	1632
1917	0.84	1630
1920	0.84	1628
1923	0.84	1626
1926	0.84	1624
1929	0.85	1622
1932	0.85	1621
1935	0.85	1619
1938	0.85	1617
1941	0.85	1615
1944	0.86	1613
1947	0.86	1611
1950	0.86	1609

This should probably be expressed as a positive angle of declination.

BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity:

(0.33) 1950 0.89 1489

(-0.33) 1950 0.86 1609

By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology,

Bzzzt:

Nope no secret.

https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=102#C102

You just can't/won't read. That's not a secret either.

This should probably be expressed as a positive angle of declination.

BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity:

There is no 33 degree angle involved. Using your trajectory, Paddock would have come closer to shooting off his big toe than hitting anywhere in the festival venue.

Learn to read:

Declination is downward. Negative 33 degrees inclination is the same as 33 degrees declination. It is the difference between your preferred -33 degrees upward and 33 degrees downward.

33 degrees downward points down. Negative 33 degrees downward points up.

It is like walking negative 33 feet east is walking 33 feet west.

The VxH specified shooting angle was -33°. This should probably be expressed as a positive angle of declination. Not all ballistic calculators will even accept a negative angle value, but specify 0 to 90 degrees.

For another calculator, see:

http://gundata.org/blog/post/223-ballistics-chart/

The gundata entry specifies "Shooting angle (0..89)." Stick a negative value in there and it will reject.

As there is no such thing as a triangle with negative angles, the values for every angle of a triangle are positive values.

In a triangle with sides -3 and -4, a² + b² = c² would yield a hypotenuse of positive 5.

BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity:

(0.33) 1950 0.89 1489

(-0.33) 1950 0.86 1609

The data available at the links shows the only data change between my two charts is one is -33 and the other is 33. Not so for the chart you just created with yet another time calculation. You changed the input data.

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=75dcb734

-33 degrees

http://www.shooterscalculator.com/images/trajectory/ballistic_trajectory_chart_75dcb734.png

This chart made with the original -33 data, shows the bullet rise above the original altitude, and remain above that altitude, for over 300 yards. This is an amazing feat for a bullet shot on a steep downward angle.

- - - - - - - - - -

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=fd15e1b9

33 degrees

http://www.shooterscalculator.com/images/trajectory/ballistic_trajectory_chart_fd15e1b9.png

Amazingly, when the angle is changed from -33 to 33, the flight path does not change, according to your calculator.

- - - - - - - - - -

When your calculator permits you to enter ridiculous data, it provides you with ridiculous results.

As one may observe, it provides the precise same flight trajectory, whether at 33 or -33. When fired at 33 degrees downward, the bullet goes upward and remains above the original location for over 300 yards.

The data available at the links shows the only data change to be -33 to 33.

The time for 650 yards/1950 feet is 0.86 in either instance. The average velocity for any object that travels 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4418 ft/sec.

- - - - - - - - - -

YOUR DATA WITH A NEW TIME SHOWS YOU ALTERED THE INPUT DATA.

And your flight trajectory chart for -33 degrees featuring a new time

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=81e7edd6

http://www.shooterscalculator.com/images/trajectory/ballistic_trajectory_chart_81e7edd6.png

Notice that with the projectile purported fired at a 33 degree downward angle, the projectile maintains its original altitude for about 150 yards.

Of course, in your derivation of data, you changed the properties of the chart:

Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd [Was 25 yd/75 feet]
Chart Range: 1000 yd[Was 750 yd]
Maximum Range: 50002 yd [Was 750 yd/2250 ft]
Step Size: 1 yd [Was 25 yd/75 ft]

Corrected For Atmosphere
Adjusted BC: 0.307 [was 0.300]
Altitude: 0 ft [was 2000 ft]
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps

- - - - - - - - - - - - - - - - - - - -

To see the prior input data, just look:

As for your magic ability to fire rounds down at 33º, and have them either rise or maintain altitude for hundreds of yards,

The formula is distance divided by time.

And when you don't have data for time with enough precision - what then, professor Donkeychan?

By the way, if the given time and distance data was imprecise, what was used to calculate the instantaneous velocities?

[VxH at #175] LOL. It's not a rounding error Professor DonkeyChan.

If the given data is not subject to a rounding error, then it is totally accurate and precise, distance/time works fine, and your bogus calculated data is bullshit.

If the given data is subject to a rounding error, then it is accurate ± 0.005, in which case using distance/time works to define the possible range of average velocity within the rounding factor, and this also proves your bogus calculated data is bullshit.

By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology,

Bzzzt:

Nope no secret.

The given time is 0.86.

[nolu chan #137]

By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology, the stated flight time to his own preferred 0.82621.

That is VxH bullshit. Not only wrong but impossible on its face.

[VxH]

    1950	0.86	1609

Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)?

The average velocity of any object covering 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4419 feet per second. It could be a flying refrigerator. If it goes 1950 feet in 0.86 seconds, the average velocity is 2267.4419 seconds.

The object could have sped up and slowed down between 0 and 1950 feet in any manner and it makes no difference. If the object covers the 1950 feet in 0.86 seconds, the average velocity for the 1950 foot distance is 2267.4419 seconds.

Recall the Khan Academy video you previously referenced:

https://www.khanacademy.org/science/physics/one-dimensional-motion/displacement-velocity-time/v/instantaneous-speed-and-velocity

Video transcript

- [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time.

And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.

Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip.

In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second.

[snip]

#140. To: nolu chan (#139)

The formula is distance divided by time.

And when you don't have data for time with enough precision - what then, professor Donkeychan?

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?pl=223+RemingtonLVA&presets=223+RemingtonLVA~%5BChart+Label%5D~G1~0.300~62~3240~100~1.5~-33~0~0~true~2000~72~29.92~21~true~1000~25&df=G1&bc=0.300&bw=62&vi=3240&zr=100&sh=1.5&sa=-33&ws=0&wa=0&cfa=on&alt=0&tmp=72&bar=29.92&hum=21&ssb=on&cr=1000&ss=1&chartColumns=Range~ft%3BTime~s%3BVel%5Bx%2By%5D~ft%2Fs&lbl=Test&submitst=+Create+Chart

Below is the bogus input data presented for this chart [boldface added]:

Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°

Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 1000 yd
Maximum Range: 50002 yd
Step Size: 1 yd

Corrected For Atmosphere
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps

The data actually attached to this new bullshit chart is shown below, as it appears at the link [boldface added]:

Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°

Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 1000 yd
Maximum Range: 50002 yd
Step Size: 1 yd

Corrected For Atmosphere
Adjusted BC: 0.307
Altitude: 0 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps

Below is the bogus input data presented for this chart [boldface added]:

YAWN.

http://www.shooterscalculator.com/

Has a bug where input values don't always populate from the parameters in the URL.

How ya comin' with that CURVE professor DonkeyChan?