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Title: Forensic acoustic proof of SECOND shooter in the Las Vegas massacre
Source:
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URL Source: https://www.youtube.com/watch?v=JxmEFeKy8aI
Published: Oct 11, 2017
Author: Mike Adams TheHealthRanger
Post Date: 2017-10-11 00:40:47 by A K A Stone
Keywords: None
Views: 45640
Comments: 148
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#109. To: VxH (#108)
You have repeatedly changed and modified your numbers. Could you provide me a list of all of your errors that you posted so I can remove them from the site so people don't look at bullshit?
Here is an analogy of your "proof" Blue 42 Blue 42 hut hut hike. Ok I proved you are wrong.
My mind it is a beautiful thing.
I see your problem, now; it is called, profane vanity.
So you are with the V guy. That''s ok You agree with his analysis 100 percent correct. Or is your mind superior like mine and know that his analysis is bullshit. To many errors. To many things not factored in. I'm not saying that there were multiple shooters. I'm not saying Pollock or Paddock or whatever his name was didn't act alone. I'm just saying what V dude offers as 100 percent conclusive proof is not conclusive or proof.
Says the genius who made up an image with lots of wrong and made up numbers. I know the truth know. Spock is controlling your mind.
Truth is great and will prevail unless deprived of her natural weapons, free argument and debate. Does that work in AKA Stoned Land? There's nothing wrong with refining an analysis in the context of an honest desire to seek the truth. Time is still not being calculated with 100% accuracy. Why is that?
Does that work in AKA Stoned Land? That is fine. Truth also works if false things are no longer out there. If you care about truth why don't you find a list of all the posts yoy made with errors so we can correct them with the latest and the greatest.
In this case, the truth is still a work in process. For the next step in the process - Maybe "yoy" and Noluchan's donkey can tell us why applying a linear calculation (d/v) to a non-linear velocity produces values for Time which are farther away from the Ballistic chart's value for T than rounding can explain?
ROTFL
So, Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel A: Please explain how, in the context of the highlighted range of interest on the concert field, Noluchan's idea to reconstruct Time by taking (d=75ft)/Vel[x+y] Feel free to consult Noluchan's Donkey, since it probably has better temperament and reading comprehension skills than either of you two have demonstrated.
There's a question regarding whether the value of Vel[x+y] for a given 75ft vector segment is the average Velocity OR whether it's just the momentry V at point d. The problem is that you are clueless and do not know what your are doing and do not know what a vector is. Here is a correct spreadsheet: As a vector is described by a line and not a point, the Column D velocity at 75 feet describes the average bullet velocity for the segment from 0 to 75 feet, and the velocity at 150 feet describes the average bullet velocity from 0 to 150 feet, and so on. The time for 75 feet indicates the elapsed time for 0 to 75 feet. The time for 150 feet indicates the elapsed time for 0 to 150 feet. Column C, the time, is derived by dividing Column B (distance) by Column D. In your chart it is was rounded off to two decimal places. I took it to four decimal places. Your added Rube Goldberg nonsense was not only wrong but unecessary. Average velocity at the stated distances was staring you in the face. In Columns H thru L, I have provided the data for each 75-foot segment. At 1575 feet, the bullet opens its largest gap on sound at 0.05502 seconds. From 1575 to 1650 feet, the bullet travels at an average velocity of 1127.9144 fps, dipping below the speed of sound. After that, sound is traveling faster than the bullet and the gap diminishes.
>>Here is a correct spreadsheet Too bad it's not one you created with ballistic data as per the methodology: http://www.btgr esearch.org/AcousticReconstruction02042012.pdf Meanwhile, Please explain how, in the context of the highlighted range of interest on the concert field, Your idea to reconstruct Time by taking (d=75ft)/Vel[x+y] does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into " bullshit" Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel A: Please explain how, in the context of the highlighted range of interest on the concert field, Noluchan's idea to reconstruct Time by taking (d=75ft)/Vel[x+y]
It surprises me a little that we have seen no attempts at forensic reconstruction of the shooting by recognized shooting experts and/or audio experts. Other than that sad-sack attempt by the NYSlimes, I haven't seen anything along these lines. There are experts out there. So why aren't we hearing from them? Is it because they find the audio data to be ambiguous? Who knows.
I asked the authors of the study http://www.btgresearch.org/AcousticReconstruction02042012.pdf They replied: "our standard operating procedure is to avoid public comments on shooting events. This better protects our neutrality and value of our analysis in the event that we are retained by an agency or party to subsequent legal proceedings. We also like to restrict our analysis to materials that come into our possession following a proper and documented chain of custody regarding handling of evidence. When it comes time for depositions or courtroom testimony, most experts who have made prior public comments on a matter find that opposing legal counsel, opposing experts, and the blogosphere find ways to make them regret earlier public comments." =============== In light of what can be observed here - that makes sense.
Well, it is an explanation. They're hoping to be hired guns as expert witnesses in the upcoming civil litigation.
Yeah. In the meantime, I've found this exercise to be a worthwhile learning experience.
At 1950 ft your "spreadsheet" has an elapsed time of 1.2119 with a corresponding Vel[x+y] of 1609. Meanwhile observe the corresponding elapsed time and Vel[x+y] generated by: OOPS! How'd ya manage to do that, Professor DonkyChan?
I'm not telling you to stop or that you're wasting your time. You might stumble over something unnoticed by everyone. Recall how Dan Rather was brought down by a persistent guy that noticed the fonts in the fake documents about Dumbya's military service.
If your Column c, Vel[x+y] (ft/s) represents an instantaneous velocity, it cannot be used in this manner. Make up your mind, does Column C represent instantaneous velocities, valid only at a single point, and not over any range?
Says the Donkey who managed to transform 0.86 seconds into 1.2119 seconds. Meanwhile... http://www.answers.com/Q /What_is_instantaneous_slope As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105 the next step in the quest is to explore methods of deriving Time relative to the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment.
http://www.answers.com/Q /What_is_instantaneous_slope As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105 the next step in the quest is to explore methods of deriving Time relative to the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment. To find what is at your source, we go to the link, which, like the link to the Khan Academy, only shows that you are bullshitting. You seem to have a special affinity in providing cut and paste bullshit as as some sort of profound knowledge. http://www.answers.com/Q/What_is_instantaneous_slope The instantaneous slope of a curve is the slope of that curve at a single point. In calculus, this is called the derivative. It also might be called the line tangent to the curve at a point. If you imagine an arbitrary curve (just any curve) with two points on it (point P and point Q), the slope between P and Q is the slope of the line connecting those two points. This is called a secant line. If you keep P where it is and slide Q closer and closer to P along the curve, the secant line will change slope as it gets smaller and smaller. When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P. Mathematically, we say that the slope at P = limh—>0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x. The formula above is a specific case where the derivative is in terms of x and we're dealing with two dimensions. In physics, the instantaneous slope (derivative) of a position function is velocity, the derivative of velocity is acceleration, and the derivative of acceleration is jerk. Of course, the calculus formula P = limh—>0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x was not used anywhere in your spreadsheet, so you are just bullshitting. Also, However, the slope of a bullet in flight is constantly changing, the deceleration is not constant, and the slope contains an infinite number of points. Moreover, you have merely bullshitted and have not described any formula to obtain the average velocity of the bullet over a given range, using instantaneous velocities. While you claim calculus formulas in your spreadsheet, you have yet to show a formula to sum changing parts of a spreadsheet column, i.e., sum row 1 and 2, sum row 1 thru 3, then row 1 thru 4, and so forth. I used such a formula and it showed that your column contained arithmetical errors not created by a spreadsheet formula. When you can program adding sums, I'll consider you doing calculus. As it is, you have not demostrated the ability to consistently add two numbers together, which is what you did to to sum that column. You added rows 1 and 2 to get the row 2 total; then you added row 3 to get the row 3 total, and so on, making two errors in 26 rows. You are fortunate it was now a thousand rows on a spreadsheet in a finance office. The formula for calculating average velocity (d/t) is given by the Khan Academy in the video you referenced. In their example, they divide a distance fo 1000m by 200s and get an average velocity of 5 m/s, and then they explicitly state, that siad result "doesn't necessarily equal the instantaneous velocities at particular points." The Khan Academy does not say that you can sum two instantaneous velocities and divide by two, and get an average velocity between the two points. See what you referenced. The first sentence is important — pretend you are a physics student. - [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time. Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip. In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second. Just as your instantaneous velocity at two discrete and infinitesimal points can not be summed and divided by two to obtain average velocity, the instantaneous slope at two discrete and infinitesimal points will be different and cannot be used to calculate the slope of a traveling bullet whose velocity is contantly changing. While this bullshit about instantaneous slopes has diverted from your other bullshit about instantaneous velocities, you are still left searching to explain (1) your calculation used to derive average velocity over the specified distances, (2) your calculation used to change the formula for calculating average velocity over distance. Your chart stipulated distance and time. For 75 feet, you stipulated 0.02 seconds. This is your data, not mine. Using the formula, d/t=V(avg), that is 3,750 feet per second average velocity. If we assume that you meant the time to be anything between 0.015 and 0.025 seconds, that is 3000 - 5000 feet per second average velocity. For 1950 feet, you stipulated 0.86 seconds, and an average velocity of 2367.5926 feet per second, obtained by a formula you can neither present nor explain, nor can you provide any citation to any authority for your bullshit calculation. V(avg) = d/t = 1950/0.86 = 2267.4418 feet per second average velocity. If we assume that you meant the time to be anything between 0.855 and 0.865, then, V(avg) may equal 1950/0.0855 = 2280.7017 V(avg) may equal 1950/0.0865 = 2254.3353 Meanwhile, your bullshit 2367.5926 average velocity allows one to derive the time required to travel 1950 feet. 1950/2367.5926 = 0.823621429 seconds. Indeed, your second time for Tb, the time of the bullet, in your column E, reflects a bullet flight time of 0.823621 seconds, giving three less decimal points than I did, but rounding the the same precise thing at your chosen four decimal places, indicating how you derived that bullshit Tb from the bullshit average velocity. To check whether this bullshit time is not impossible with the stipulated data, one need only check if it is within the rounding possibilities of the stipulated data, i.e., from 0.855 to 0.865 seconds. Oh noes, your bullshit average velocity (0.823621) is not possible to reconcile with the stiplulated time, even allowing for the maximum rounding error. Your misbegotten time would round to 0.82 instead of 0.86. You have yet to explain how you can stipulate a bullet time of 0.86 seconds, and through the magic of VxH formulas, transform that time into 0.823621 seconds, and then use that visibly bullshit time to perform further bullshit calculations. If the bullet flew 1950 feet in 0.823621, why sure enough it went at an average velocity of 2367.5938 and covered 1950 feet. However, at the stipulated time of 0.86 seconds, at the bullshit average velocity of 2367.5938 feet per second, the bullet would have flown 2036.1307 feet. The stipulated distance is 1950 feet. At the maximum rounding down error to 0.855 seconds, at your bullshit average velocity of 2367.5926, the bullet would have flown 2024.292699 feet (0.855 x 2367.5926). The stipulated distance is 1950 feet. With your stipulated data, you may not have more or less than 1950 feet. You may not have less than 0.855 seconds flight time, nor more than 0.865 seconds flight time. You cannot change the distance the bullet flew, nor do more than consider a rounding error on the time. Your calculated numbers fail miserably. Your bullshit calculated numbers fall outside the maximum possible error attributable to a rounding error. Your bullshit calculations result in a new time, not within any rounding error, replacing 0.86 with 0.823621. Your bullshit average velocity over 1950 feet (2367.5926), at the maximum rounding error for stipulated time (0.86 rounded down to 0.855), requires the bullet to fly a minimum of 2024.292699 feet.
LOL. Idiot. ShooterCalculator.com Says: ======================== Professor DonkeyChan says: 1.2119 seconds nolu chan posted on 2017-10-30 19:58:41 ET https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53025&Disp=160#C160
Column B of above spreadsheet shows the specified distance and the specified time for that distance. Column C shows the specified time for the distance traveled. Column D shows the time rounded down to the minimum time possibly explained by rounding. Column E shows the time rounded up to the maximum time possibly explained by rounding. Column F shows the Average Velocity (d/t) calculated with the unadjusted time from Column C. Column G shows the Average Velocity (d/t) calculated with the minimum time possible from Column D. This minimum time of flight shows the maximum possible average velocity of the bullet. Column H shows the Average Velocity (d/t) calculsted with the maximum time possible from Column E. This maximum time of flight show the minimum average velocity of the bullet. Column I shows the time for sound to travel the distance at 1130 fps. Column J shows the time difference between the bullet and the sound using unadjusted time from Column C. Column K shows the maximum possible time difference between the bullet and the sound using the time rounded down in Column D. Column L shows the minimum possible time difference between the bullet and the sound using the time rounded up in Column E. Column N states VXH Average Velocity using undisclosed math, presumably of Klingon origin. Column O states the instantaneous velocities at the distances specified in Column B. These velocities reflect a specific and infinitesimal point it time only, and do not describe velocity at any other point in time. Comparing Columns H and N, Column H calculates the maximum possible average velocity with the time round down as far is is possible. Column N is the average velocity claimed by VxH, using his secret Klingon mathematics. Notice his secret method obtain an average velocity well below the maximum possible for 75 feet, but comes nearer to the maximum possible with every calculation, and at 1200 feet his calculations leave the realm of the possible. At 1200 feet, at the specified time of 0.46 seconds, the average velocity would be 2608.70 feet per second (1200/0.46). Anyone can do the arithmetic. At 1200 feet, at 0.46 seconds rounded down as far as possible to 0.455 seconds (Column D), the maximum average veocity of 2637.36 feet per second (Column G) is achieved (2637.36/0.455). Anyone can still do the arithmetic. At this point, the VxH calculations exceed the possibilities of reality and achieve 2675.1176 feet per second. After this point, every VxH calculation widens the error. At 1950 feet, the Column G max average velocity is 2280.70 (1950/0.0855). After more calculations, the VxH error expands the difference to 2367.5926 feet per second. If carried on to further distances, the error will simply keep increasing. He started with 64% of the maximum possible average velocity, and surpassed 100% of the maximum on his 16th calculation, and continued to surpass the maximum possible average velocity by a greater and greater amount. Moreover, the distance and the time were a given.
...ft........ sec .... sec per VxH
75 0.02 0.023427
150 0.05 0.047413
225 0.07 0.071971
300 0.10 0.097113
375 0.12 0.122843
450 0.15 0.149183
525 0.18 0.176138
600 0.20 0.203720
675 0.23 0.231943
750 0.26 0.260820
825 0.29 0.290357
900 0.32 0.320574
975 0.36 0.351496
1050 0.39 0.383128
1125 0.42 0.415484
1200 0.46 0.448578
1275 0.49 0.482427
1350 0.53 0.517054
1425 0.56 0.552465
1500 0.60 0.588675
1575 0.64 0.625711
1650 0.68 0.663578
1725 0.73 0.702290
1800 0.77 0.741864
1875 0.81 0.782303
1950 0.86 0.082621
Notice how VxH, in his calculations, at and after 1200 feet, reduces the time of flight of the bullet by more than any possible amount of rounding from two decimal places. By 1950 feet, VxH has "rounded off" 0.86 and amazingly reduced the stated flight time to his own preferred 0.82621.
>>By 1950 feet, VxH has "rounded off" 0.86 Nope. Not a rounding error Super Genius. It's an artifact manufacted from the AVERAGING curve. >>preferred 0.82621. Nope. Try to keep up - - I've moved on with a revised curve that reconstructs time from Velocity and Distance, As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105 the next step in the quest is to explore methods of deriving Time relative to the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment. So, Professor DonkeyChan -- Here is the ballistic data table generated for 1 yard intervals from 1875 to 1950 ft. Drag Function: G1 Wind Speed: 0 mph Corrected For Atmosphere
Incomplete charts wilt errors constantly changing the data. Yet magically every time you change your numbers they still ,magically work. Give it up you are looking foolish. There is no way for you to prove anything from your keyboard using this method.
Nah, foolish is not knowing that in order to recreate the ballistic data curve (and thus the average Velocity over a given distance) with complete accuracy would require duplicating the function used in the Ballistic chart generator. Meanwhile, averaging via various methods to get an approximation is completely acceptable - and USEFUL for gaining an understanding into what the audio is telling us.
Sumtymes these assholes fart on a selected thread. Ignore them.
You have explored methods which require require rewriting the bullet flight times far beyond any possible rounding error. Reconstructing the given travel time is VxH BULLSHIT. Time and distance are given. Rounding the given time up or down does not help your bullshit work. Your bullshit methodology changes the given 0.86 seconds elapsed time to 0.82 seconds. There is no valid formula in the world for that. Time and distance are given data. Average velocity equals distance divided by time. Distance in feet, divideded by time in seconds, yields velocity in feet per second. Column B of above spreadsheet shows the specified distance and the specified time for that distance. Column C shows the specified time for the distance traveled. Column D shows the time rounded down to the minimum time possibly explained by rounding. Column E shows the time rounded up to the maximum time possibly explained by rounding. Column F shows the Average Velocity (d/t) calculated with the unadjusted time from Column C. Column G shows the Average Velocity (d/t) calculated with the minimum time possible from Column D. This minimum time of flight shows the maximum possible average velocity of the bullet. Column H shows the Average Velocity (d/t) calculsted with the maximum time possible from Column E. This maximum time of flight show the minimum average velocity of the bullet. Column I shows the time for sound to travel the distance at 1130 fps. Column J shows the time difference between the bullet and the sound using unadjusted time from Column C. Column K shows the maximum possible time difference between the bullet and the sound using the time rounded down in Column D. Column L shows the minimum possible time difference between the bullet and the sound using the time rounded up in Column E. Column N states VXH Average Velocity using undisclosed math, presumably of Klingon origin. Column O states the instantaneous velocities at the distances specified in Column B. There velocities reflect a specific and infinitesimal point it time only, and do not describe velocity at any other point in time. Comparing Columns H and N, Column H calculates the maximum possible average velocity with the time round down as far is is possible. Column N is the average velocity claimed by VxH, using his secret Klingon mathematics. Notice his secret method obtain an average velocity well below the maximum possible for 75 feet, but comes nearer to the maximum possible with every calculation, and at 1200 feet his calculations leave the realm of the possible. At 1200 feet, at the specified time of 0.46 seconds, the average velocity would be 2608.70 feet per second (1200/0.46). Anyone can do the arithmetic. At 1200 feet, at 0.46 seconds rounded down as far as possible to 0.455 seconds (Column D), the maximum average veocity of 2637.36 feet per second (Column G) is achieved (2637.36/0.455). Anyone can still do the arithmetic. At this point, the VxH calculations exceed the possibilities of reality and achieve 2675.1176 feet per second. After this point, every VxH calculation widens the error. At 1950 feet, the Column G max average velocity is 2280.70 (1950/0.0855). After more calculations, the VxH error expands the difference to 2367.5926 feet per second. If carried on to further distances, the error will simply keep increasing. He started with 64% of the maximum possible average velocity, and surpassed 100% of the maximum on his 16th calculation, and continued to surpass the maximum possible average velocity by a greater and greater amount. Moreover, the distance and the time were a given.
ft.......... sec..... sec
75 0.02 0.023427
150 0.05 0.047413
225 0.07 0.071971
300 0.10 0.097113
375 0.12 0.122843
450 0.15 0.149183
525 0.18 0.176138
600 0.20 0.203720
675 0.23 0.231943
750 0.26 0.260820
825 0.29 0.290357
900 0.32 0.320574
975 0.36 0.351496
1050 0.39 0.383128
1125 0.42 0.415484
1200 0.46 0.448578
1275 0.49 0.482427
1350 0.53 0.517054
1425 0.56 0.552465
1500 0.60 0.588675
1575 0.64 0.625711
1650 0.68 0.663578
1725 0.73 0.702290
1800 0.77 0.741864
1875 0.81 0.782303
1950 0.86 0.082621
Notice how VxH, in his calculations, at and after 1200 feet, reduces the time of flight of the bullet by more than any possible amount of rounding from two decimal places. By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology, the stated flight time to his own preferred 0.82621. That is VxH bullshit. Not only wrong but impossible on its face. Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)? The average velocity of any object covering 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4419 feet per second. It could be a flying refrigerator. If it goes 1950 feet in 0.86 seconds, the average velocity is 2267.4419 seconds. The object could have sped up and slowed down between 0 and 1950 feet in any manner and it makes no difference. If the object covers the 1950 feet in 0.86 seconds, the average velocity for the 1950 foot distance is 2267.4419 seconds. Recall the Khan Academy video you previously referenced: - [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time. Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip. In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second. [snip] The instantaneous velocity at 1950 feet is irrelevant to the calculation of the average velocity over the range 0 to 1950 feet.
LOL. It's not a rounding error Professor DonkeyChan. How you coming along with that Average Velocity for the 75 foot segment ending at 1950 ft?
It came along quite well. Anything that travels 1950 feet in 1.06 seconds travels an average velocity of 2122.64 feet per second. The formula is distance divided by time. How are you coming along with your bullet going splat at ~520 feet ground distance from Mandalay Bay? How did you work out that negative 33º angle? Side a represents the vertical height of Paddock's vantage point. At the 32nd floor, and at 10.9 feet per floor, (32-1) x 10.9 = 338 feet. The VxH specified shooting angle was -33°. This should probably be expressed as a positive angle of declination. Not all ballistic calculators will even accept a negative angle value, but specify 0 to 90 degrees. For another calculator, see: http://gundata.org/blog/post/223-ballistics-chart/ It appears that VxH drew an imaginary horizontal line d at a vertical height of 338 feet from the ground, and an imaginary 338 foot line e down to the ground, bringing into view a rectangle with a mirror image triangle to that above. VxH guessed 33º as the acute angle formed at the junction of sides c and imaginary side d at point B. VxH guessed very wrongly. With a specified shooting angle of 33º at the junction of lines c and d, the angle made by sides c and b would also be 33º, and angle ß, made by sides a and c would be 57º. (The right angle at point A is 90º. The other two angles must add up to 90º.) With side a being 338 feet, side b would be 520.4743578 feet, and side c would be 620.5944 feet. As may be seen, disregarding gravity, if the bullet flew downward at the specified 33º from a height of 338 feet, it would fly a straight line of sight path into the ground at ~520 feet from the Mandalay Bay at ground level. Calculating the bullet velocity after that point may be difficult, even with secret Klingon math.
>>The formula is distance divided by time. And when you don't have data for time with enough precision - what then, professor Donkeychan? Drag Function: G1 Wind Speed: 0 mph Corrected For Atmosphere
BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity: (0.33) 1950 0.89 1489 (-0.33) 1950 0.86 1609
Bzzzt: Nope no secret. https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=102#C102 You just can't/won't read. That's not a secret either.
BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity: There is no 33 degree angle involved. Using your trajectory, Paddock would have come closer to shooting off his big toe than hitting anywhere in the festival venue. Learn to read: Declination is downward. Negative 33 degrees inclination is the same as 33 degrees declination. It is the difference between your preferred -33 degrees upward and 33 degrees downward. 33 degrees downward points down. Negative 33 degrees downward points up. It is like walking negative 33 feet east is walking 33 feet west. For another calculator, see: The gundata entry specifies "Shooting angle (0..89)." Stick a negative value in there and it will reject. As there is no such thing as a triangle with negative angles, the values for every angle of a triangle are positive values. In a triangle with sides -3 and -4, a2 + b2 = c2 would yield a hypotenuse of positive 5. (0.33) 1950 0.89 1489 (-0.33) 1950 0.86 1609 The data available at the links shows the only data change between my two charts is one is -33 and the other is 33. Not so for the chart you just created with yet another time calculation. You changed the input data. http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=75dcb734 -33 degrees http://www.shooterscalculator.com/images/trajectory/ballistic_trajectory_chart_75dcb734.png This chart made with the original -33 data, shows the bullet rise above the original altitude, and remain above that altitude, for over 300 yards. This is an amazing feat for a bullet shot on a steep downward angle. - - - - - - - - - - http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=fd15e1b9 33 degrees http://www.shooterscalculator.com/images/trajectory/ballistic_trajectory_chart_fd15e1b9.png Amazingly, when the angle is changed from -33 to 33, the flight path does not change, according to your calculator. - - - - - - - - - - When your calculator permits you to enter ridiculous data, it provides you with ridiculous results. As one may observe, it provides the precise same flight trajectory, whether at 33 or -33. When fired at 33 degrees downward, the bullet goes upward and remains above the original location for over 300 yards. The data available at the links shows the only data change to be -33 to 33. The time for 650 yards/1950 feet is 0.86 in either instance. The average velocity for any object that travels 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4418 ft/sec. - - - - - - - - - - YOUR DATA WITH A NEW TIME SHOWS YOU ALTERED THE INPUT DATA. And your flight trajectory chart for -33 degrees featuring a new time http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=81e7edd6 http://www.shooterscalculator.com/images/trajectory/ballistic_trajectory_chart_81e7edd6.png Notice that with the projectile purported fired at a 33 degree downward angle, the projectile maintains its original altitude for about 150 yards. Of course, in your derivation of data, you changed the properties of the chart: Drag Function: G1 Corrected For Atmosphere - - - - - - - - - - - - - - - - - - - - To see the prior input data, just look: As for your magic ability to fire rounds down at 33º, and have them either rise or maintain altitude for hundreds of yards,
And when you don't have data for time with enough precision - what then, professor Donkeychan? By the way, if the given time and distance data was imprecise, what was used to calculate the instantaneous velocities? [VxH at #175] LOL. It's not a rounding error Professor DonkeyChan. If the given data is not subject to a rounding error, then it is totally accurate and precise, distance/time works fine, and your bogus calculated data is bullshit. If the given data is subject to a rounding error, then it is accurate ± 0.005, in which case using distance/time works to define the possible range of average velocity within the rounding factor, and this also proves your bogus calculated data is bullshit.
Bzzzt: Nope no secret. The given time is 0.86. [nolu chan #137] That is VxH bullshit. Not only wrong but impossible on its face. Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)? The average velocity of any object covering 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4419 feet per second. It could be a flying refrigerator. If it goes 1950 feet in 0.86 seconds, the average velocity is 2267.4419 seconds. The object could have sped up and slowed down between 0 and 1950 feet in any manner and it makes no difference. If the object covers the 1950 feet in 0.86 seconds, the average velocity for the 1950 foot distance is 2267.4419 seconds. Recall the Khan Academy video you previously referenced: - [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time. Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip. In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second. [snip]
And when you don't have data for time with enough precision - what then, professor Donkeychan? Below is the bogus input data presented for this chart [boldface added]: Wind Speed: 0 mph Corrected For Atmosphere The data actually attached to this new bullshit chart is shown below, as it appears at the link [boldface added]: Wind Speed: 0 mph Corrected For Atmosphere
YAWN. http://www.shooterscalculator.com/ Has a bug where input values don't always populate from the parameters in the URL. How ya comin' with that CURVE professor DonkeyChan?
If the given data is not subject to a rounding error, then it is totally accurate and precise, distance/time works fine, and your bogus calculated data is bullshit. It's still not a rounding error, Super Genius. It's a result of the AVERAGING calculation that was used in the context of Time data that was truncated to an insufficiently precise (for the purpose of determining average velocity) 2 decimal points. =SUM(C9:C10)/L9
#110. To: VxH (#108)
#111. To: buckeroo (#104)
How do you determine your opinion?
#112. To: A K A Stone (#111)
#113. To: buckeroo (#112)
#114. To: VxH (#106)
(Edited)
Says the genius who posts videos with scribbling on a whiteboard presented as "PROOF".
#115. To: A K A Stone (#109)
#116. To: VxH (#115)
(Edited)
Truth is great and will prevail unless deprived of her natural weapons, free argument and debate.
#117. To: A K A Stone (#116)
(Edited)
If you care about truth why don't you find a list of all the posts yoy made with errors
#118. To: VxH, A K A Stone, noluchan (#117)
Maybe you and Noluchan's donkey can tell us why applying a linear calculation (d/v) to a non-linear velocity produces values for Time which are farther away from the Ballistic chart's value for T than rounding can explain?
#119. To: A K A Stone, noluchan, buckeroo (#117)
(Edited)
{ crickets crickets crickets }
Illustration B: Vb using my original Average of summed Velocity values.
B:
does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into "bullshit"?
#120. To: VxH, A K A Stone (#105)
I correctly illustrate the flaw inherent in taking a momentary point velocity of a continuously decelerating proctile and ASSuming it to be an average.
BALLISTICS DATA SPREADSHEET
A1 AVERAGE VELOCITY AND TIME DIFF OVER TOTAL DISTANCE AVERAGE VELOCITY FOR EACH 75 FEET SEGMENT 2 3 B C D E F G H I J K L 4 d Time (avg) Vel[x+y] Ts=d/Vs T=Tb - Ts Tb 75 ft Avg Velocity for Segment Segment Segment 5 (ft) d/Vel[x+y] (ft/s) d/Vs ABS(Tb-Ts) +C7-C6 75 foot segment distance begin end 6 0 0.0000 3240 +75/H4 +B7-B6 +K7+75 A7 7 75 0.0237 3163 0.0664 0.0427 0.0237 3163.0000 75 0 75 8 150 0.0486 3088 0.1327 0.0842 0.0249 3016.4744 75 75 150 9 225 0.0747 3014 0.1991 0.1245 0.0261 2876.1533 75 150 225 10 300 0.1020 2941 0.2655 0.1635 0.0274 2741.7798 75 225 300 11 375 0.1307 2870 0.3319 0.2012 0.0287 2617.2620 75 300 375 12 450 0.1608 2799 0.3982 0.2375 0.0301 2490.8930 75 375 450 13 525 0.1923 2730 0.4646 0.2723 0.0315 2378.2353 75 450 525 14 600 0.2254 2662 0.5310 0.3056 0.0331 2266.7686 75 525 600 15 675 0.2601 2595 0.5973 0.3372 0.0347 2160.0657 75 600 675 16 750 0.2966 2529 0.6637 0.3672 0.0364 2057.9351 75 675 750 17 825 0.3347 2465 0.7301 0.3954 0.0381 1967.1773 75 750 825 18 900 0.3750 2400 0.7965 0.4215 0.0403 1860.3774 75 825 900 19 975 0.4172 2337 0.8628 0.4456 0.0422 1777.1863 75 900 975 20 1050 0.4615 2275 0.9292 0.4677 0.0443 1691.5924 75 975 1050 21 1125 0.5081 2214 0.9956 0.4874 0.0466 1609.7315 75 1050 1125 22 1200 0.5571 2154 1.0619 0.5048 0.0490 1531.4566 75 1125 1200 23 1275 0.6089 2094 1.1283 0.5194 0.0518 1448.4509 75 1200 1275 24 1350 0.6631 2036 1.1947 0.5316 0.0542 1384.2156 75 1275 1350 25 1425 0.7201 1979 1.2611 0.5410 0.0570 1315.8863 75 1350 1425 26 1500 0.7800 1923 1.3274 0.5474 0.0600 1250.6135 75 1425 1500 27 1575 0.8436 1867 1.3938 0.5502 0.0636 1179.8360 75 1500 1575 28 1650 0.9101 1813 1.4602 0.5501 0.0665 1127.9144 75 1575 1650 29 1725 0.9801 1760 1.5265 0.5464 0.0700 1071.1245 75 1650 1725 30 1800 1.0539 1708 1.5929 0.5391 0.0738 1016.9418 75 1725 1800 31 1875 1.1309 1658 1.6593 0.5284 0.0770 973.8184 75 1800 1875 32 1950 1.2119 1609 1.7257 0.5137 0.0811 925.3285 75 1875 1950 33 2025 1.2972 1561 1.7920 0.4948 0.0853 879.1211 75 1950 2025 34 2100 1.3861 1515 1.8584 0.4723 0.0889 843.7085 75 2025 2100 35 2175 1.4796 1470 1.9248 0.4452 0.0935 802.5405 75 2100 2175 36 2250 1.5778 1426 1.9912 0.4133 0.0982 763.3722 75 2175 2250 37 38 Total 39 1.5780 40 SUM G7:G36
#121. To: nolu chan (#120)
(Edited)
?
Illustration B: Vb using my original Average of summed Velocity values. B:
does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into " bullshit"?
#122. To: VxH (#121)
(Edited)
#123. To: Tooconservative (#122)
There are experts out there. So why aren't we hearing from them?
#124. To: VxH (#123)
#125. To: Tooconservative (#124)
Well, it is an explanation.
#126. To: nolu chan (#120)
(Edited)
4 d Time (avg) Vel[x+y] 5 (ft) d/Vel[x+y] (ft/s) 32 1950 1.2119 1609 1950 0.86 1609 Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 750 yd
Maximum Range: 50002 yd
Step Size: 25 ydCorrected For Atmosphere
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%Range Time Vel[x+y] (ft) (s) (ft/s) 0 0.00 3240 75 0.02 3163 150 0.05 3088 225 0.07 3014 300 0.10 2941 375 0.12 2870 450 0.15 2799 525 0.18 2730 600 0.20 2662 675 0.23 2595 750 0.26 2529 825 0.29 2465 900 0.32 2401 975 0.36 2337 1050 0.39 2275 1125 0.42 2214 1200 0.46 2154 1275 0.49 2095 1350 0.53 2036 1425 0.56 1979 1500 0.60 1923 1575 0.64 1867 1650 0.68 1813 1725 0.73 1760 1800 0.77 1708 1875 0.81 1658 1950 0.86 1609 2025 0.91 1561 2100 0.96 1515 2175 1.01 1470 2250 1.06 1426
#127. To: VxH (#125)
Yeah. In the meantime, I've found this exercise to be a worthwhile learning experience.
#128. To: VxH, A K A Stone (#119)
Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel
#129. To: nolu chan (#128)
(Edited)
it cannot be used in this manner.
#130. To: VxH, A K A Stone (#129)
Meanwhile...
Answer byBlue
Confidence votes 38.3K When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P.
Video transcript
WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???
#131. To: nolu chan (#130)
Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 750 yd
Maximum Range: 50002 yd
Step Size: 25 ydCorrected For Atmosphere
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%1950 0.86 1609 4 d Time (avg) Vel[x+y] 5 (ft) d/Vel[x+y] (ft/s) 32 1950 1.2119 1609
#132. To: VxH, A K A Stone (#131)
Unresponsive obfuscatory yukonesque bullshit
WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???
Distance and time specified Time rounded to plus or minus maximum Avg velocity Avg velocity Avg velocity time for sound ABS Tb - Ts ABS Tb - Ts ABS Tb - Ts time as given max possible min possible to travel dist time as given max possible min possible B C D E F G H I J K L N O P d Time Time -.005 Time +.005 Avg Vel unadj Avg Vel max Avg Vel min t for sound ABS Tdiff unadj ABS Tdiff MAX ABS Tdiff MIN VxH Avg Vel VxH Instant VxH Tdiff (ft) (seconds) (seconds) b/c b/d b/e b/1130 ABS(c8-i8) ABS(d8-i8) ABS(E8-I8) Velocity Tb-Ts 7 0 0.00 3240 8 75 0.02 0.015 0.025 3750.00 5000.00 3000.0000 0.0664 0.0464 0.0514 0.0414 3201.5000 3163 0.0429 9 150 0.05 0.045 0.055 3000.00 3333.33 2727.2727 0.1327 0.0827 0.0877 0.0777 3163.6667 3088 0.0852 10 225 0.07 0.065 0.075 3214.29 3461.54 3000.0000 0.1991 0.1291 0.1341 0.1241 3126.2500 3014 0.1270 11 300 0.10 0.095 0.105 3000.00 3157.89 2857.1429 0.2655 0.1655 0.1705 0.1605 3089.2000 2941 0.1682 12 375 0.12 0.115 0.125 3125.00 3260.87 3000.0000 0.3319 0.2119 0.2169 0.2069 3052.6667 2870 0.2088 13 450 0.15 0.145 0.155 3000.00 3103.45 2903.2258 0.3982 0.2482 0.2532 0.2432 3016.4286 2799 0.2488 14 525 0.18 0.175 0.185 2916.67 3000.00 2837.8378 0.4646 0.2846 0.2896 0.2796 2980.6250 2730 0.2881 15 600 0.20 0.195 0.205 3000.00 3076.92 2926.8293 0.5310 0.3310 0.3360 0.3260 2945.2222 2662 0.3269 16 675 0.23 0.225 0.235 2934.78 3000.00 2872.3404 0.5973 0.3673 0.3723 0.3623 2910.2000 2595 0.3650 17 750 0.26 0.255 0.265 2884.62 2941.18 2830.1887 0.6637 0.4037 0.4087 0.3987 2875.5455 2529 0.4024 18 825 0.29 0.285 0.295 2844.83 2894.74 2796.6102 0.7301 0.4401 0.4451 0.4351 2841.3333 2465 0.4392 19 900 0.32 0.315 0.325 2812.50 2857.14 2769.2308 0.7965 0.4765 0.4815 0.4715 2807.4615 2401 0.4753 20 975 0.36 0.355 0.365 2708.33 2746.48 2671.2329 0.8628 0.5028 0.5078 0.4978 2773.8571 2337 0.5107 21 1050 0.39 0.385 0.395 2692.31 2727.27 2658.2278 0.9292 0.5392 0.5442 0.5342 2740.6000 2275 0.5454 22 1125 0.42 0.415 0.425 2678.57 2710.84 2647.0588 0.9956 0.5756 0.5806 0.5706 2707.6875 2214 0.5794 23 1200 0.46 0.455 0.465 2608.70 2637.36 2580.6452 1.0619 0.6019 0.6069 0.5969 2675.1176 2154 0.6260 24 1275 0.49 0.485 0.495 2602.04 2628.87 2575.7576 1.1283 0.6383 0.6433 0.6333 2642.8889 2095 0.6451 25 1350 0.53 0.525 0.535 2547.17 2571.43 2523.3645 1.1947 0.6647 0.6697 0.6597 2610.9474 2036 0.6768 26 1425 0.56 0.555 0.565 2544.64 2567.57 2522.1239 1.2611 0.7011 0.7061 0.6961 2579.3500 1979 0.7077 27 1500 0.60 0.595 0.605 2500.00 2521.01 2479.3388 1.3274 0.7274 0.7324 0.7224 2548.0952 1923 0.7378 28 1575 0.64 0.635 0.645 2460.94 2480.31 2441.8605 1.3938 0.7538 0.7588 0.7488 2517.1364 1867 0.7671 29 1650 0.68 0.675 0.685 2426.47 2444.44 2408.7591 1.4602 0.7802 0.7852 0.7752 2486.5217 1813 0.7956 30 1725 0.73 0.725 0.735 2363.01 2379.31 2346.9388 1.5265 0.7965 0.8015 0.7915 2456.2500 1760 0.8232 31 1800 0.77 0.765 0.775 2337.66 2352.94 2322.5806 1.5929 0.8229 0.8279 0.8179 2426.3200 1708 0.8499 32 1875 0.81 0.805 0.815 2314.81 2329.19 2300.6135 1.6593 0.8493 0.8543 0.8443 2395.7692 1658 0.8758 33 1950 0.86 0.855 0.865 2267.44 2280.70 2254.3353 1.7257 0.8657 0.8707 0.8607 2367.5926 1609 0.9008 34 2025 0.91 0.905 0.915 2225.27 2237.57 2213.1148 1.7920 0.8820 0.8870 0.8770 35 2100 0.96 0.955 0.965 2187.50 2198.95 2176.1658 1.8584 0.8984 0.9034 0.8934 36 2175 1.01 1.005 1.015 2153.47 2164.18 2142.8571 1.9248 0.9148 0.9198 0.9098 37 2250 1.06 1.055 1.065 2122.64 2132.70 2112.6761 1.9912 0.9312 0.9362 0.9262
....d ........ t ... Vxh
#133. To: nolu chan (#132)
(Edited)
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 1000 yd
Maximum Range: 50002 yd
Step Size: 1 yd
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fpsRange Time Vel[x+y] (ft) (s) (ft/s) 1875 0.81 1658 1878 0.81 1656 1881 0.82 1654 1884 0.82 1652 1887 0.82 1650 1890 0.82 1648 1893 0.82 1646 1896 0.83 1644 1899 0.83 1642 1902 0.83 1640 1905 0.83 1638 1908 0.83 1636 1911 0.83 1634 1914 0.84 1632 1917 0.84 1630 1920 0.84 1628 1923 0.84 1626 1926 0.84 1624 1929 0.85 1622 1932 0.85 1621 1935 0.85 1619 1938 0.85 1617 1941 0.85 1615 1944 0.86 1613 1947 0.86 1611 1950 0.86 1609
Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)?
#134. To: VxH (#133)
#135. To: A K A Stone, NoluChan (#134)
(Edited)
Give it up you are looking foolish.
#136. To: VxH, A K A Stone, NoluChan (#135)
#137. To: VxH (#133)
[VxH #133] Nope. Try to keep up - - I've moved on with a revised curve that reconstructs time from Velocity and Distance,
YOUR CALCULATED DATA IS ALL BULLSHIT, AS ARE YOU
WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???
Distance and time specified Time rounded to plus or minus maximum Avg velocity Avg velocity Avg velocity time for sound ABS Tb - Ts ABS Tb - Ts ABS Tb - Ts time as given max possible min possible to travel dist time as given max possible min possible B C D E F G H I J K L N O P d Time Time -.005 Time +.005 Avg Vel unadj Avg Vel max Avg Vel min t for sound ABS Tdiff unadj ABS Tdiff MAX ABS Tdiff MIN VxH Avg Vel VxH Instant VxH Tdiff (ft) (seconds) (seconds) b/c b/d b/e b/1130 ABS(c8-i8) ABS(d8-i8) ABS(E8-I8) Velocity Tb-Ts 7 0 0.00 3240 8 75 0.02 0.015 0.025 3750.00 5000.00 3000.0000 0.0664 0.0464 0.0514 0.0414 3201.5000 3163 0.0429 9 150 0.05 0.045 0.055 3000.00 3333.33 2727.2727 0.1327 0.0827 0.0877 0.0777 3163.6667 3088 0.0852 10 225 0.07 0.065 0.075 3214.29 3461.54 3000.0000 0.1991 0.1291 0.1341 0.1241 3126.2500 3014 0.1270 11 300 0.10 0.095 0.105 3000.00 3157.89 2857.1429 0.2655 0.1655 0.1705 0.1605 3089.2000 2941 0.1682 12 375 0.12 0.115 0.125 3125.00 3260.87 3000.0000 0.3319 0.2119 0.2169 0.2069 3052.6667 2870 0.2088 13 450 0.15 0.145 0.155 3000.00 3103.45 2903.2258 0.3982 0.2482 0.2532 0.2432 3016.4286 2799 0.2488 14 525 0.18 0.175 0.185 2916.67 3000.00 2837.8378 0.4646 0.2846 0.2896 0.2796 2980.6250 2730 0.2881 15 600 0.20 0.195 0.205 3000.00 3076.92 2926.8293 0.5310 0.3310 0.3360 0.3260 2945.2222 2662 0.3269 16 675 0.23 0.225 0.235 2934.78 3000.00 2872.3404 0.5973 0.3673 0.3723 0.3623 2910.2000 2595 0.3650 17 750 0.26 0.255 0.265 2884.62 2941.18 2830.1887 0.6637 0.4037 0.4087 0.3987 2875.5455 2529 0.4024 18 825 0.29 0.285 0.295 2844.83 2894.74 2796.6102 0.7301 0.4401 0.4451 0.4351 2841.3333 2465 0.4392 19 900 0.32 0.315 0.325 2812.50 2857.14 2769.2308 0.7965 0.4765 0.4815 0.4715 2807.4615 2401 0.4753 20 975 0.36 0.355 0.365 2708.33 2746.48 2671.2329 0.8628 0.5028 0.5078 0.4978 2773.8571 2337 0.5107 21 1050 0.39 0.385 0.395 2692.31 2727.27 2658.2278 0.9292 0.5392 0.5442 0.5342 2740.6000 2275 0.5454 22 1125 0.42 0.415 0.425 2678.57 2710.84 2647.0588 0.9956 0.5756 0.5806 0.5706 2707.6875 2214 0.5794 23 1200 0.46 0.455 0.465 2608.70 2637.36 2580.6452 1.0619 0.6019 0.6069 0.5969 2675.1176 2154 0.6260 24 1275 0.49 0.485 0.495 2602.04 2628.87 2575.7576 1.1283 0.6383 0.6433 0.6333 2642.8889 2095 0.6451 25 1350 0.53 0.525 0.535 2547.17 2571.43 2523.3645 1.1947 0.6647 0.6697 0.6597 2610.9474 2036 0.6768 26 1425 0.56 0.555 0.565 2544.64 2567.57 2522.1239 1.2611 0.7011 0.7061 0.6961 2579.3500 1979 0.7077 27 1500 0.60 0.595 0.605 2500.00 2521.01 2479.3388 1.3274 0.7274 0.7324 0.7224 2548.0952 1923 0.7378 28 1575 0.64 0.635 0.645 2460.94 2480.31 2441.8605 1.3938 0.7538 0.7588 0.7488 2517.1364 1867 0.7671 29 1650 0.68 0.675 0.685 2426.47 2444.44 2408.7591 1.4602 0.7802 0.7852 0.7752 2486.5217 1813 0.7956 30 1725 0.73 0.725 0.735 2363.01 2379.31 2346.9388 1.5265 0.7965 0.8015 0.7915 2456.2500 1760 0.8232 31 1800 0.77 0.765 0.775 2337.66 2352.94 2322.5806 1.5929 0.8229 0.8279 0.8179 2426.3200 1708 0.8499 32 1875 0.81 0.805 0.815 2314.81 2329.19 2300.6135 1.6593 0.8493 0.8543 0.8443 2395.7692 1658 0.8758 33 1950 0.86 0.855 0.865 2267.44 2280.70 2254.3353 1.7257 0.8657 0.8707 0.8607 2367.5926 1609 0.9008 34 2025 0.91 0.905 0.915 2225.27 2237.57 2213.1148 1.7920 0.8820 0.8870 0.8770 35 2100 0.96 0.955 0.965 2187.50 2198.95 2176.1658 1.8584 0.8984 0.9034 0.8934 36 2175 1.01 1.005 1.015 2153.47 2164.18 2142.8571 1.9248 0.9148 0.9198 0.9098 37 2250 1.06 1.055 1.065 2122.64 2132.70 2112.6761 1.9912 0.9312 0.9362 0.9262
d ........ given..........Vxh bullshit
[VxH]
1950 0.86 1609
Video transcript
#138. To: nolu chan (#137)
beyond any possible rounding error
#139. To: VxH, A K A Stone (#138)
How you coming along with that Average Velocity for the 75 foot segment ending at 1950 ft?
#140. To: nolu chan (#139)
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 1000 yd
Maximum Range: 50002 yd
Step Size: 1 yd
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fpsRange Time Vel[x+y] (ft) (s) (ft/s) 1875 0.81 1658 1878 0.81 1656 1881 0.82 1654 1884 0.82 1652 1887 0.82 1650 1890 0.82 1648 1893 0.82 1646 1896 0.83 1644 1899 0.83 1642 1902 0.83 1640 1905 0.83 1638 1908 0.83 1636 1911 0.83 1634 1914 0.84 1632 1917 0.84 1630 1920 0.84 1628 1923 0.84 1626 1926 0.84 1624 1929 0.85 1622 1932 0.85 1621 1935 0.85 1619 1938 0.85 1617 1941 0.85 1615 1944 0.86 1613 1947 0.86 1611 1950 0.86 1609
#141. To: nolu chan (#139)
This should probably be expressed as a positive angle of declination.
#142. To: nolu chan (#137)
By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology,
#143. To: VxH, A K A Stone (#141)
This should probably be expressed as a positive angle of declination.
The VxH specified shooting angle was -33°. This should probably be expressed as a positive angle of declination. Not all ballistic calculators will even accept a negative angle value, but specify 0 to 90 degrees.
BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity:
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd [Was 25 yd/75 feet]
Chart Range: 1000 yd[Was 750 yd]
Maximum Range: 50002 yd [Was 750 yd/2250 ft]
Step Size: 1 yd [Was 25 yd/75 ft]
Adjusted BC: 0.307 [was 0.300]
Altitude: 0 ft [was 2000 ft]
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps
#144. To: VxH, A K A Stone (#140)
The formula is distance divided by time.
#145. To: VxH, A K A Stone (#142)
By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology,
By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology, the stated flight time to his own preferred 0.82621.
[VxH]
1950 0.86 1609
Video transcript
#146. To: VxH, A K A Stone (#140)
#140. To: nolu chan (#139)
The formula is distance divided by time.
Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 1000 yd
Maximum Range: 50002 yd
Step Size: 1 yd
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 1000 yd
Maximum Range: 50002 yd
Step Size: 1 yd
Adjusted BC: 0.307
Altitude: 0 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps
#147. To: nolu chan (#146)
Below is the bogus input data presented for this chart [boldface added]:
#148. To: nolu chan (#144)
(Edited)
[VxH at #175] LOL. It's not a rounding error Professor DonkeyChan.
=SUM(C$9:C11)/L10
=SUM(C$9:C12)/L11
etc.
Where column L contains 1 @ row 8 and =+ L8+1, =+L9+1 etc for rows 9..34
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