Title: Forensic acoustic proof of SECOND shooter in the Las Vegas massacre Source:
[None] URL Source:https://www.youtube.com/watch?v=JxmEFeKy8aI Published:Oct 11, 2017 Author:Mike Adams TheHealthRanger Post Date:2017-10-11 00:40:47 by A K A Stone Keywords:None Views:45551 Comments:148
#73. To: A K A Stone, VXH, buckeroo, tooconservative, cz82, redleghunter, sneakypete, Pinguinite, Vicomte13, Liberator, Deckard (#1)
Found this interesting video.
Adams assumes a shooter using an AR-15 with .223 Remington 55 grain ammo.
He states 20% humidity.
He states a 925 m/s bullet velocity which is ~3034.8 fps.
He specifies a 16.5" barrel, but a 3034.8 fps initial velocity would seem to indicate a 20" barrel or different ammo.
I believe the white board has an error. The flight time should be 0.532s, not 0.528s.
It lists both the 400 yard flight time and the lag time as 0.528s. This would mean the bullet velocity was precisely double the speed of sound, and that double 0.528s, or 1.056s would be the 400 yard travel time for the speed of sound. The time of sound travel for 400 yards at 1130 fps is 1.062.
He cites his use of a gundata ballistics chart for travel time.
gundata indicates for 400 yards, the time of travel is 5.32s, specifying a standard 55gr Remington .223 bullet leaving the barrel at 3,215fps. Adams also specified a 16.5 inch barrel, but it seems an AR-15 with a 16.5 barrel does not achieve 3,215 initial velocity.
Testing with different barrel lengths indicates an AR-15, 16.5" barrel, with Remington .223 ammo, does not achieve 3,034.8 muzzle ("initial") velocity.
With a 20" barrel, the same setup gets 3,071 fps muzzle velocity.
A 25" barrel gets it up to 3,221 fps muzzle velocity.
A 16.5" with Federal M193/55 gets 3,187 fps muzzle velocity.
A ballistics chart indicates that a Remington .223 will not get the stated bullet velocity.
Assuming the shots were fired from room 32135, and that end of the Mandalay Bay Hotel was 1208 feet from the base of the bandstand, and that a bullet struck the pavement at or near the base of the bandstand, the long side a right triangle would be 1208 feet and the short side would be the height of room 32135.
The building claims a height of 480 feet and 44 stories, for an average of 10.91 feet per story. The 32nd floor would be 338.21 feet up. (31 x 10.91, base of floor 1 has zero height).
With sides of 1208 and 338.21, the hypotenuse would be 1254.45 feet.
The actual distance the bullet traveled would be more than that as it would not follow a straight path, but would follow an arc.
Using estimates of distance to striking the venue surface of ~1250 feet, and detected lag times of 0.559 sec and 0.374 sec, the slower bullet made the 0.374 lag time; the faster bullet arrived .559 sec before the muzzle blast.
At 1130 fps, the sound would cover 1250 feet in about 1.106 seconds.
A bullet making the 1250 ft trip .559 sec before the sound, made the trip in .547 sec.
A bullet making the 1250 ft trip .374 sec before the sound, made the trip in .732 sec.
1250 feet in .547 sec is an avg velocity of ~2236 fps.
1250 feet in .732 sec is an avg velocity of ~1708 fps.
This assumes both shots were taken from the same location.
What bullets were used can be ascertained by collecting the bullets. What was left in the room should be inventoried, along with what guns were in the room.
Most mfgs recommend a minimum velocity of 1800 fps for proper expansion. The so called "magic number" associate with elk hunting is 1200 lb ft Energy. Below that is risky and I prefer 1400 lb ft as my personal standard. Although every gun is different the ammo mfg. Will put their tested numbers out for their loads. According to Federal their TBT 165 gr out of a 308 maintains 1939 fps and 1377 lb ft at 500 yards. Mathematically that should do the job as long as the bullet hits it's mark. Federal lists the same weight game King at 1708 FPS and 1069 ft lb at 500 yards. Obviously not the best option. If you keep 400 yards and in either a 150 or 165 gr factory loaded bonded round should work fine on elk. You just need to find the one that goes exactly where you want it to every time you press the trigger.
This would suggest the possibility of the 1708 fps round being a .308 (or whatever else gets around 1708 fps at 400 - 450 yards.
This is a .223 ballistics chart (external) generated using our ballistic trajectory calculator. Based off a standard 55gr bullet leaving the barrel at 3,215fps and follows the bullet trajectory all the way to 1000 yards in steps of 50 yard increments. The charting shows the range, drop (based off a 1.5" scope mount), current velocity, energy, and time in seconds in relation to the bullets movement through space and time. This chart does not account for atmospheric conditions, so if you want to take in to effect these things check out the calculators official page. The Ballistic Coefficient for the .223 Remington, Remington Metal Case, 55gr is 0.202 (in this example) but, but may also range from .185 bc to .257
The amplitude graphs of the audio referenced on my meme can be reproduced by anyone with minimal tools. It's REPRODUCIBLE - that's what differentiates valid science from conspiratorial buffoonery.
The amplitude graphs of the audio referenced on my meme can be reproduced by anyone with minimal tools. It's REPRODUCIBLE - that's what differentiates valid science from conspiratorial buffoonery.
That you reproduce meaningless bullshit is meaningful, but not as you intend.
On your spreadsheet chartoon, notice that you calculate T = Tb - Ts.
You calculate elapsed time as the time it took the bullet to travel, minus the time it took the sound to travel.
As the bullet is supersonic, and sound is a constant, the sound would travel 400 yards in 1.06s and the bullet would travel the 400 yards in less than 1.06s. Subtracting 1.06 from a smaller number will always yield a negative number.
At 1200 feet, you actually calculate Tb as 0.448578s, and Ts as 1.062s and calculate the T as -0.6126, negative 0.6126 seconds. The average donkey could recognize that something is wrong when the result is negative time.
Just what do you think happens in negative 0.6126 seconds?
You could at least recognize that if you get a negative number, you have stated the required formula backwards, and you proceeded to perform the calculation backwards, and present the bass ackwards result of your understanding of the study you looked at.
You've got what it takes to make bullets travel in negative time.
Now, ask your donkey - what distance does that MEASURED absolute time difference correspond to on the chart?
No Absolute value is ever expressed as a negative number. Had your undisclosed formula for the last column of your spreadsheet included code to express an absolute value, your spreadsheet results would not appear as negative numbers. But your spreadsheet displays negative numbers and you did not even question it or fix your spreadsheet.
The results should all be positive, like this:
Bullet Time, Velocity FPS, TbTs
d = distance 400 yards, 1200 feet Tb = Time of bullet Ts = Time of sound, 1.062 seconds @ 1,130 feet per second (FPS) (72ºF, 20% Humidity) Ts Tb = Time difference between Tb and Ts
Column 1 = d/FPS = time in seconds Column 2 = Tb stepped in 100 FPS increments, beginning with Ts Column 3 = Ts Tb (time in seconds supersonic bullet arrives ahead of sound)
Row 1 = directly inserted data. Data display is set to show 3 decimal places.
1.062947 is the time for sound to travel 400 yds/1200 ft.
1130 is the distance sound travels in one second. Here it is stated as an assumed bullet average velocity over 400 yds/1200 ft.
0.000 is the time difference between a bullet traveling the speed of sound over 1200 ft and sound traveling 1200 feet.
Row 2 = spreadsheet formulas
Column 1 = 1200 / column 2 (distance / bullet avg velocity) bullet travel time for 1200 ft.
Column 2 = Row 1, Col 1 + 100 (stepping the assumed bullet velocity by 100 fps).
Column 3 = 1.061947 - Row 2, Col 1 (time of sound @1200 ft - time of bullet travel) = time diff between time of sound and time of bullet at 1200 ft.
The formulas for Row 2 are dragged down to generate Rows 3-30.
Bullet time (s), Bullet average velocity (FPS), time difference to sound at 1,200 feet (s)
Yes, but in this case the ABS is implied in knowledge of what the spreadsheet is actually calculating.
If you applied ABS(Tb-Ts-) the chart would loose the information regarding whether the Vb was super-sonic or not, which the negative numbers conveniently tell us.
The author's formula works just fine without your tweakage.
Why do you keep posting this chartoon when all your data is not only wrong, but farcical? The only things you proved is that you do not know how to calculate the average velocity of an imaginary bullet and you are hopeless at spreadsheets. Your entertainment value as a useful idiot is over for now, and you will never figure it out without more help. Help is on the way, grasshopper.
Columns 1, 2, and 3 are direct entry of data generated by entering imaginary data into a generator at http://www.shooterscalculator.com/. I replicated the data taken from the calculator with My BB's. If I input initial velocity as 3240 fps, and other data, and call it My BB's, I can show a chart for magical bbs.
The Shooters Calculator only provides a result based on user input. It does not present a spreadsheet with the formulas to generate the data. The data from the Calculator can be cut and pasted into a spreadsheet, or entered by direct entry; this produces data in the cells, but no spreadsheet formulas in the cells. The chart states the speed of sound as 1130 feet per second (fps).
The remaining 4 columns, (4, 5, 6, 7) were generated by VxH.
Column 6 uses 1130.8 fps to calculate the time for sound to travel the distance stated in Column 1.
Column 4 is labeled as (Avg V) Vb. This column purports to present the average velocity of the bullet to cover the distance for the row it is in. All of the data in this column is epically wrong as the methodology of calculation is absurdly wrong.
To calculate the average velocity of the bullet, divide distance by time.
Instead of this, a personal misbegotten formula was used. Probably a pocket calculator for each cell in Column 4 was used to perform the calculations, and the data was directly entered into the cells by hand.
For the first two data rows, sum 3240 and 3163 and divide by 2. 6403/2 yields the 3201 in Column 4.
For the first three data rows, sum 3240+3163+3088 for 9491. 9491 / 3 yields the 3163.6667 in Column 4.
And so on, and so forth. All the calculated Column 4 data (average Vb), is garbage.
The chosen methodology was to sum the velocity given for each distance, and divide by the number of elements summed. This produces nonsensical data.
Example: You drive a car 100 miles at 80 mph. You drive another 100 miles at 20 mph. With this bogus methodology, 80 + 20 = 100, divide by 2, and your average velocity was 50 mph. Not.
In the real world, you drove 100/80 or 1.25 hours at 80 mph. You drove 100/20 or 5 hours at 20 mph. And you drove 200 miles in 6.25 hours. Your average speed was 200/6.25, or 32 mph.
Column 4, in addition to using an absurd methodology for its calculations, also incorporates two summing errors for the velocities taken from Column 3, at 900 feet and 1275 ft. In each case, the actual sum was 1 less than that calculated.
Spreadsheet formulas are not prone to fat finger syndrome, and do not make such errors, but someone with a pocket calculator or pen and paper does. The data was typed in after external calculation.
Where you calculate 2367.5926 average Vb at 1950 feet, 1950/1.211933 (the velocity of the bullet in Column 5), it yields 1608.9998 fps, remarkably close to the 1609 in Column 3. But then, the elapsed time in Column 2 is 0.86, not 1.21933. It is a conundrum how the bullet traveled for 1.21933 seconds in an elapsed time of 0.86 seconds.
Of course, when you use Column 1 1950 ft and Column 3 1609 fps to derive the time of flight, the formula is d/Vb, and Vb is the Average Velocity.
The bullet will travel 1905 feet distance (Col 1) in 0.86 sec time (Col 2) in 1905/0.86 or 2267.4418 average Vb. Stated in your headnote is Tb is d/Vb.
It is noteworthy that you used Column 3 as the "average" velocity of the bullet in order to derive the other average velocity of the bullet in Column 4.
Column 5 (Tb) incorporates the garbage data from Column 4 into its calculations, and all the resulting calculated data is wrong. GIGO.
Column 7 (T = Tb Ts) incorporates the garbage data from Column 5 and all the calculated data is wrong. GIGO.
The chart is multicolor and pretty, but the data for the imaginary bullet is demonstrably wrong in every column you created, except for column 6 where you succeeded in dividing the distance by 1130.8.
and the data was directly entered into the cells by hand.
Bzzzt. Fail again.
Nope. You said you created spreadsheet and used their formulas. Had you used their formulas you would not have bullshit results, including arithmetic errors in the columns.
Which formula of theirs did you use to manufacture the wrong bullet velocities?
Cite any source that says to find average velocity with the method you used.
When you introduced this bullshit on the other thread at your #19 to A K A Stone, you said:
I found/took their formula, built a spreadsheet, and plugged in 223 balistic data generated via shooterscalculator.com:
Only you did not use their formulas or you would not have gotten all the data you derived bass ackwards wrong, and you did not create formulas and drag them down through the rows, or you would not have the calculation errors the are apparent.
I created a spreadsheet using the same data and created formulas and dragged them down through the rows. They work. That is how I can pinpoint where you made calculating errors in your data entry.
All you did was cut and paste the chart data into a spreadsheet workbook.
Columns 1 thru 3 were cut and paste.
For Column 4, there is no chance that you created a formula and dragged it down through the rows. You go off at range 900 where you summed to 36497 instead of 36496. This error of 1 continues through to range 1275, where you summed to 47,572 instead of 45,570. This put the summing error at 2, which continued through range 1950 where you ended.
This is not a spreadsheet error. I used two different formulas to sum the velocities, with results identical to each other. You used no formula. You sat there with your pocket calculator and added the first two and typed in the result. Then you added the third velocity and typed in the result. And you did this for each data entry in that column. If you have any spreadsheet formula that can replicate your results, produce it.
As Column 4 calculates the sum of the velocities divided by the number of velocities, and the sum of the velocities was not created by a formula on a spreadsheet column, the column was manual data entry.
In Column 5, d/Vb, the distance is correctly divided by the bogus average velocity, yielding a bogus result. When it is as simple as programming one column divided by another, good job. When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.
In Column 6, I stated you were able to divide distance by 1130.8. When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.
In Column 7, you managed to correctly subtract the bogus data in Column 5 from the bogus data in Column 6, yielding all bogus results. When it is as simple as programming one column subtracted from another, good job. It should have included an ABS function to avoid getting negative time results.When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.
As Columns 5 and 7 incorporate the brain dead data in Column 4, with a double whammy of a bogus formula and calculation errors, all data in Columns 5 and 7 is bogus.
Your chart in Column 2 from btgresearch indicates Tb for range 1950 is 0.86 seconds. Column 5 for 1950 range indicates Tb is 0.823621. You call that fixing a rounding error???? How did displaying only two decimal places to 0.86 convert to 0.823621????
As Column 4 calculates the sum of the velocities divided by the number of velocities, and the sum of the velocities was not created by a formula on a spreadsheet column, the column was manual data entry.
Bzzzt. Another Nolu-FAIL.
=SUM(C9:C10)/L9 =SUM(C$9:C11)/L10 =SUM(C$9:C12)/L11 etc. Where column L contains 1 @ row 8 and =+L8+1, =+L9+1 etc for rows 9..34
Now please tell us how Nolu-Time works and then explain why the values of Column J are closer to Time (Column B) than Nolu-Time(Column I)?
decoration-
style: initial; text-decoration-color: initial">more accurate is to divide the distance by the velocity and get the time to more decimal places
If you care about truth why don't you find a list of all the posts yoy made with errors
In this case, the truth is still a work in process.
For the next step in the process - Maybe "yoy" and Noluchan's donkey can tell us why applying a linear calculation (d/v) to a non-linear velocity produces values for Time which are farther away from the Ballistic chart's value for T than rounding can explain?
#119. To: A K A Stone, noluchan, buckeroo (#117)(Edited)
{ crickets crickets crickets }
So,
Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel Illustration B: Vb using my original Average of summed Velocity values.
A:B:
Please explain how, in the context of the highlighted range of interest on the concert field, Noluchan's idea to reconstruct Time by taking (d=75ft)/Vel[x+y] does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into "bullshit"
?
Feel free to consult Noluchan's Donkey, since it probably has better temperament and reading comprehension skills than either of you two have demonstrated.
As per what I said in https://libertysflame.com/cgi-bin/readart.cgi? ArtNum=53046&Disp=105#C105 the next step in the quest is to explore methods of deriving Time relative to the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment.
To find what is at your source, we go to the link, which, like the link to the Khan Academy, only shows that you are bullshitting.
You seem to have a special affinity in providing cut and paste bullshit as as some sort of profound knowledge.
The instantaneous slope of a curve is the slope of that curve at a single point. In calculus, this is called the derivative. It also might be called the line tangent to the curve at a point.
If you imagine an arbitrary curve (just any curve) with two points on it (point P and point Q), the slope between P and Q is the slope of the line connecting those two points. This is called a secant line. If you keep P where it is and slide Q closer and closer to P along the curve, the secant line will change slope as it gets smaller and smaller. When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P.
Mathematically, we say that the slope at P = limh>0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x.
The formula above is a specific case where the derivative is in terms of x and we're dealing with two dimensions. In physics, the instantaneous slope (derivative) of a position function is velocity, the derivative of velocity is acceleration, and the derivative of acceleration is jerk.
Of course, the calculus formula P = limh>0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x was not used anywhere in your spreadsheet, so you are just bullshitting.
Also,
When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P.
However, the slope of a bullet in flight is constantly changing, the deceleration is not constant, and the slope contains an infinite number of points.
Moreover, you have merely bullshitted and have not described any formula to obtain the average velocity of the bullet over a given range, using instantaneous velocities.
While you claim calculus formulas in your spreadsheet, you have yet to show a formula to sum changing parts of a spreadsheet column, i.e., sum row 1 and 2, sum row 1 thru 3, then row 1 thru 4, and so forth. I used such a formula and it showed that your column contained arithmetical errors not created by a spreadsheet formula. When you can program adding sums, I'll consider you doing calculus. As it is, you have not demostrated the ability to consistently add two numbers together, which is what you did to to sum that column. You added rows 1 and 2 to get the row 2 total; then you added row 3 to get the row 3 total, and so on, making two errors in 26 rows. You are fortunate it was now a thousand rows on a spreadsheet in a finance office.
The formula for calculating average velocity (d/t) is given by the Khan Academy in the video you referenced. In their example, they divide a distance fo 1000m by 200s and get an average velocity of 5 m/s, and then they explicitly state, that siad result "doesn't necessarily equal the instantaneous velocities at particular points."
The Khan Academy does not say that you can sum two instantaneous velocities and divide by two, and get an average velocity between the two points. See what you referenced. The first sentence is important pretend you are a physics student.
- [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time.
And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.
Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip.
In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second.
Just as your instantaneous velocity at two discrete and infinitesimal points can not be summed and divided by two to obtain average velocity, the instantaneous slope at two discrete and infinitesimal points will be different and cannot be used to calculate the slope of a traveling bullet whose velocity is contantly changing.
While this bullshit about instantaneous slopes has diverted from your other bullshit about instantaneous velocities, you are still left searching to explain
(1) your calculation used to derive average velocity over the specified distances,
(2) your calculation used to change the formula for calculating average velocity over distance.
Your chart stipulated distance and time.
For 75 feet, you stipulated 0.02 seconds. This is your data, not mine.
Using the formula, d/t=V(avg), that is 3,750 feet per second average velocity.
If we assume that you meant the time to be anything between 0.015 and 0.025 seconds, that is 3000 - 5000 feet per second average velocity.
For 1950 feet, you stipulated 0.86 seconds, and an average velocity of 2367.5926 feet per second, obtained by a formula you can neither present nor explain, nor can you provide any citation to any authority for your bullshit calculation.
V(avg) = d/t = 1950/0.86 = 2267.4418 feet per second average velocity.
If we assume that you meant the time to be anything between 0.855 and 0.865, then,
V(avg) may equal 1950/0.0855 = 2280.7017
V(avg) may equal 1950/0.0865 = 2254.3353
Meanwhile, your bullshit 2367.5926 average velocity allows one to derive the time required to travel 1950 feet. 1950/2367.5926 = 0.823621429 seconds.
Indeed, your second time for Tb, the time of the bullet, in your column E, reflects a bullet flight time of 0.823621 seconds, giving three less decimal points than I did, but rounding the the same precise thing at your chosen four decimal places, indicating how you derived that bullshit Tb from the bullshit average velocity.
To check whether this bullshit time is not impossible with the stipulated data, one need only check if it is within the rounding possibilities of the stipulated data, i.e., from 0.855 to 0.865 seconds. Oh noes, your bullshit average velocity (0.823621) is not possible to reconcile with the stiplulated time, even allowing for the maximum rounding error. Your misbegotten time would round to 0.82 instead of 0.86.
You have yet to explain how you can stipulate a bullet time of 0.86 seconds, and through the magic of VxH formulas, transform that time into 0.823621 seconds, and then use that visibly bullshit time to perform further bullshit calculations.
If the bullet flew 1950 feet in 0.823621, why sure enough it went at an average velocity of 2367.5938 and covered 1950 feet.
However, at the stipulated time of 0.86 seconds, at the bullshit average velocity of 2367.5938 feet per second, the bullet would have flown 2036.1307 feet. The stipulated distance is 1950 feet.
At the maximum rounding down error to 0.855 seconds, at your bullshit average velocity of 2367.5926, the bullet would have flown 2024.292699 feet (0.855 x 2367.5926). The stipulated distance is 1950 feet.
With your stipulated data, you may not have more or less than 1950 feet. You may not have less than 0.855 seconds flight time, nor more than 0.865 seconds flight time. You cannot change the distance the bullet flew, nor do more than consider a rounding error on the time. Your calculated numbers fail miserably.
Your bullshit calculated numbers fall outside the maximum possible error attributable to a rounding error.
Your bullshit calculations result in a new time, not within any rounding error, replacing 0.86 with 0.823621.
Your bullshit average velocity over 1950 feet (2367.5926), at the maximum rounding error for stipulated time (0.86 rounded down to 0.855), requires the bullet to fly a minimum of 2024.292699 feet.
WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???
WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???
Distance and time specified
Time rounded to plus or minus maximum
Avg velocity
Avg velocity
Avg velocity
time for sound
ABS Tb - Ts
ABS Tb - Ts
ABS Tb - Ts
time as given
max possible
min possible
to travel dist
time as given
max possible
min possible
B
C
D
E
F
G
H
I
J
K
L
N
O
P
d
Time
Time -.005
Time +.005
Avg Vel unadj
Avg Vel max
Avg Vel min
t for sound
ABS Tdiff unadj
ABS Tdiff MAX
ABS Tdiff MIN
VxH Avg Vel
VxH Instant
VxH Tdiff
(ft)
(seconds)
(seconds)
b/c
b/d
b/e
b/1130
ABS(c8-i8)
ABS(d8-i8)
ABS(E8-I8)
Velocity
Tb-Ts
7
0
0.00
3240
8
75
0.02
0.015
0.025
3750.00
5000.00
3000.0000
0.0664
0.0464
0.0514
0.0414
3201.5000
3163
0.0429
9
150
0.05
0.045
0.055
3000.00
3333.33
2727.2727
0.1327
0.0827
0.0877
0.0777
3163.6667
3088
0.0852
10
225
0.07
0.065
0.075
3214.29
3461.54
3000.0000
0.1991
0.1291
0.1341
0.1241
3126.2500
3014
0.1270
11
300
0.10
0.095
0.105
3000.00
3157.89
2857.1429
0.2655
0.1655
0.1705
0.1605
3089.2000
2941
0.1682
12
375
0.12
0.115
0.125
3125.00
3260.87
3000.0000
0.3319
0.2119
0.2169
0.2069
3052.6667
2870
0.2088
13
450
0.15
0.145
0.155
3000.00
3103.45
2903.2258
0.3982
0.2482
0.2532
0.2432
3016.4286
2799
0.2488
14
525
0.18
0.175
0.185
2916.67
3000.00
2837.8378
0.4646
0.2846
0.2896
0.2796
2980.6250
2730
0.2881
15
600
0.20
0.195
0.205
3000.00
3076.92
2926.8293
0.5310
0.3310
0.3360
0.3260
2945.2222
2662
0.3269
16
675
0.23
0.225
0.235
2934.78
3000.00
2872.3404
0.5973
0.3673
0.3723
0.3623
2910.2000
2595
0.3650
17
750
0.26
0.255
0.265
2884.62
2941.18
2830.1887
0.6637
0.4037
0.4087
0.3987
2875.5455
2529
0.4024
18
825
0.29
0.285
0.295
2844.83
2894.74
2796.6102
0.7301
0.4401
0.4451
0.4351
2841.3333
2465
0.4392
19
900
0.32
0.315
0.325
2812.50
2857.14
2769.2308
0.7965
0.4765
0.4815
0.4715
2807.4615
2401
0.4753
20
975
0.36
0.355
0.365
2708.33
2746.48
2671.2329
0.8628
0.5028
0.5078
0.4978
2773.8571
2337
0.5107
21
1050
0.39
0.385
0.395
2692.31
2727.27
2658.2278
0.9292
0.5392
0.5442
0.5342
2740.6000
2275
0.5454
22
1125
0.42
0.415
0.425
2678.57
2710.84
2647.0588
0.9956
0.5756
0.5806
0.5706
2707.6875
2214
0.5794
23
1200
0.46
0.455
0.465
2608.70
2637.36
2580.6452
1.0619
0.6019
0.6069
0.5969
2675.1176
2154
0.6260
24
1275
0.49
0.485
0.495
2602.04
2628.87
2575.7576
1.1283
0.6383
0.6433
0.6333
2642.8889
2095
0.6451
25
1350
0.53
0.525
0.535
2547.17
2571.43
2523.3645
1.1947
0.6647
0.6697
0.6597
2610.9474
2036
0.6768
26
1425
0.56
0.555
0.565
2544.64
2567.57
2522.1239
1.2611
0.7011
0.7061
0.6961
2579.3500
1979
0.7077
27
1500
0.60
0.595
0.605
2500.00
2521.01
2479.3388
1.3274
0.7274
0.7324
0.7224
2548.0952
1923
0.7378
28
1575
0.64
0.635
0.645
2460.94
2480.31
2441.8605
1.3938
0.7538
0.7588
0.7488
2517.1364
1867
0.7671
29
1650
0.68
0.675
0.685
2426.47
2444.44
2408.7591
1.4602
0.7802
0.7852
0.7752
2486.5217
1813
0.7956
30
1725
0.73
0.725
0.735
2363.01
2379.31
2346.9388
1.5265
0.7965
0.8015
0.7915
2456.2500
1760
0.8232
31
1800
0.77
0.765
0.775
2337.66
2352.94
2322.5806
1.5929
0.8229
0.8279
0.8179
2426.3200
1708
0.8499
32
1875
0.81
0.805
0.815
2314.81
2329.19
2300.6135
1.6593
0.8493
0.8543
0.8443
2395.7692
1658
0.8758
33
1950
0.86
0.855
0.865
2267.44
2280.70
2254.3353
1.7257
0.8657
0.8707
0.8607
2367.5926
1609
0.9008
34
2025
0.91
0.905
0.915
2225.27
2237.57
2213.1148
1.7920
0.8820
0.8870
0.8770
35
2100
0.96
0.955
0.965
2187.50
2198.95
2176.1658
1.8584
0.8984
0.9034
0.8934
36
2175
1.01
1.005
1.015
2153.47
2164.18
2142.8571
1.9248
0.9148
0.9198
0.9098
37
2250
1.06
1.055
1.065
2122.64
2132.70
2112.6761
1.9912
0.9312
0.9362
0.9262
Column B of above spreadsheet shows the specified distance and the specified time for that distance.
Column C shows the specified time for the distance traveled.
Column D shows the time rounded down to the minimum time possibly explained by rounding.
Column E shows the time rounded up to the maximum time possibly explained by rounding.
Column F shows the Average Velocity (d/t) calculated with the unadjusted time from Column C.
Column G shows the Average Velocity (d/t) calculated with the minimum time possible from Column D. This minimum time of flight shows the maximum possible average velocity of the bullet.
Column H shows the Average Velocity (d/t) calculsted with the maximum time possible from Column E. This maximum time of flight show the minimum average velocity of the bullet.
Column I shows the time for sound to travel the distance at 1130 fps.
Column J shows the time difference between the bullet and the sound using unadjusted time from Column C.
Column K shows the maximum possible time difference between the bullet and the sound using the time rounded down in Column D.
Column L shows the minimum possible time difference between the bullet and the sound using the time rounded up in Column E.
Column N states VXH Average Velocity using undisclosed math, presumably of Klingon origin.
Column O states the instantaneous velocities at the distances specified in Column B. These velocities reflect a specific and infinitesimal point it time only, and do not describe velocity at any other point in time.
Comparing Columns H and N, Column H calculates the maximum possible average velocity with the time round down as far is is possible. Column N is the average velocity claimed by VxH, using his secret Klingon mathematics.
Notice his secret method obtain an average velocity well below the maximum possible for 75 feet, but comes nearer to the maximum possible with every calculation, and at 1200 feet his calculations leave the realm of the possible.
At 1200 feet, at the specified time of 0.46 seconds, the average velocity would be 2608.70 feet per second (1200/0.46). Anyone can do the arithmetic. At 1200 feet, at 0.46 seconds rounded down as far as possible to 0.455 seconds (Column D), the maximum average veocity of 2637.36 feet per second (Column G) is achieved (2637.36/0.455). Anyone can still do the arithmetic. At this point, the VxH calculations exceed the possibilities of reality and achieve 2675.1176 feet per second.
After this point, every VxH calculation widens the error.
At 1950 feet, the Column G max average velocity is 2280.70 (1950/0.0855). After more calculations, the VxH error expands the difference to 2367.5926 feet per second.
If carried on to further distances, the error will simply keep increasing. He started with 64% of the maximum possible average velocity, and surpassed 100% of the maximum on his 16th calculation, and continued to surpass the maximum possible average velocity by a greater and greater amount.
Notice how VxH, in his calculations, at and after 1200 feet, reduces the time of flight of the bullet by more than any possible amount of rounding from two decimal places.
By 1950 feet, VxH has "rounded off" 0.86 and amazingly reduced the stated flight time to his own preferred 0.82621.
Corrected For Atmosphere Adjusted BC: 0.33 Altitude: 2000 ft Barometric Pressure: 29.92 Hg Temperature: 72° F Relative Humidity: 21% Speed of Sound: 1130 fps
Range
Time
Vel[x+y]
(ft)
(s)
(ft/s)
1875
0.81
1658
1878
0.81
1656
1881
0.82
1654
1884
0.82
1652
1887
0.82
1650
1890
0.82
1648
1893
0.82
1646
1896
0.83
1644
1899
0.83
1642
1902
0.83
1640
1905
0.83
1638
1908
0.83
1636
1911
0.83
1634
1914
0.84
1632
1917
0.84
1630
1920
0.84
1628
1923
0.84
1626
1926
0.84
1624
1929
0.85
1622
1932
0.85
1621
1935
0.85
1619
1938
0.85
1617
1941
0.85
1615
1944
0.86
1613
1947
0.86
1611
1950
0.86
1609
Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)?
[VxH #133] Nope. Try to keep up - - I've moved on with a revised curve that reconstructs time from Velocity and Distance,
You have explored methods which require require rewriting the bullet flight times far beyond any possible rounding error. Reconstructing the given travel time is VxH BULLSHIT.
YOUR CALCULATED DATA IS ALL BULLSHIT, AS ARE YOU
Time and distance are given. Rounding the given time up or down does not help your bullshit work. Your bullshit methodology changes the given 0.86 seconds elapsed time to 0.82 seconds.
There is no valid formula in the world for that.
Time and distance are given data. Average velocity equals distance divided by time. Distance in feet, divideded by time in seconds, yields velocity in feet per second.
WHY IS YOUR CALCULATED DATA OUTSIDE THE POSSIBLE LIMITS OF A TIME ROUNDING ERROR???
Distance and time specified
Time rounded to plus or minus maximum
Avg velocity
Avg velocity
Avg velocity
time for sound
ABS Tb - Ts
ABS Tb - Ts
ABS Tb - Ts
time as given
max possible
min possible
to travel dist
time as given
max possible
min possible
B
C
D
E
F
G
H
I
J
K
L
N
O
P
d
Time
Time -.005
Time +.005
Avg Vel unadj
Avg Vel max
Avg Vel min
t for sound
ABS Tdiff unadj
ABS Tdiff MAX
ABS Tdiff MIN
VxH Avg Vel
VxH Instant
VxH Tdiff
(ft)
(seconds)
(seconds)
b/c
b/d
b/e
b/1130
ABS(c8-i8)
ABS(d8-i8)
ABS(E8-I8)
Velocity
Tb-Ts
7
0
0.00
3240
8
75
0.02
0.015
0.025
3750.00
5000.00
3000.0000
0.0664
0.0464
0.0514
0.0414
3201.5000
3163
0.0429
9
150
0.05
0.045
0.055
3000.00
3333.33
2727.2727
0.1327
0.0827
0.0877
0.0777
3163.6667
3088
0.0852
10
225
0.07
0.065
0.075
3214.29
3461.54
3000.0000
0.1991
0.1291
0.1341
0.1241
3126.2500
3014
0.1270
11
300
0.10
0.095
0.105
3000.00
3157.89
2857.1429
0.2655
0.1655
0.1705
0.1605
3089.2000
2941
0.1682
12
375
0.12
0.115
0.125
3125.00
3260.87
3000.0000
0.3319
0.2119
0.2169
0.2069
3052.6667
2870
0.2088
13
450
0.15
0.145
0.155
3000.00
3103.45
2903.2258
0.3982
0.2482
0.2532
0.2432
3016.4286
2799
0.2488
14
525
0.18
0.175
0.185
2916.67
3000.00
2837.8378
0.4646
0.2846
0.2896
0.2796
2980.6250
2730
0.2881
15
600
0.20
0.195
0.205
3000.00
3076.92
2926.8293
0.5310
0.3310
0.3360
0.3260
2945.2222
2662
0.3269
16
675
0.23
0.225
0.235
2934.78
3000.00
2872.3404
0.5973
0.3673
0.3723
0.3623
2910.2000
2595
0.3650
17
750
0.26
0.255
0.265
2884.62
2941.18
2830.1887
0.6637
0.4037
0.4087
0.3987
2875.5455
2529
0.4024
18
825
0.29
0.285
0.295
2844.83
2894.74
2796.6102
0.7301
0.4401
0.4451
0.4351
2841.3333
2465
0.4392
19
900
0.32
0.315
0.325
2812.50
2857.14
2769.2308
0.7965
0.4765
0.4815
0.4715
2807.4615
2401
0.4753
20
975
0.36
0.355
0.365
2708.33
2746.48
2671.2329
0.8628
0.5028
0.5078
0.4978
2773.8571
2337
0.5107
21
1050
0.39
0.385
0.395
2692.31
2727.27
2658.2278
0.9292
0.5392
0.5442
0.5342
2740.6000
2275
0.5454
22
1125
0.42
0.415
0.425
2678.57
2710.84
2647.0588
0.9956
0.5756
0.5806
0.5706
2707.6875
2214
0.5794
23
1200
0.46
0.455
0.465
2608.70
2637.36
2580.6452
1.0619
0.6019
0.6069
0.5969
2675.1176
2154
0.6260
24
1275
0.49
0.485
0.495
2602.04
2628.87
2575.7576
1.1283
0.6383
0.6433
0.6333
2642.8889
2095
0.6451
25
1350
0.53
0.525
0.535
2547.17
2571.43
2523.3645
1.1947
0.6647
0.6697
0.6597
2610.9474
2036
0.6768
26
1425
0.56
0.555
0.565
2544.64
2567.57
2522.1239
1.2611
0.7011
0.7061
0.6961
2579.3500
1979
0.7077
27
1500
0.60
0.595
0.605
2500.00
2521.01
2479.3388
1.3274
0.7274
0.7324
0.7224
2548.0952
1923
0.7378
28
1575
0.64
0.635
0.645
2460.94
2480.31
2441.8605
1.3938
0.7538
0.7588
0.7488
2517.1364
1867
0.7671
29
1650
0.68
0.675
0.685
2426.47
2444.44
2408.7591
1.4602
0.7802
0.7852
0.7752
2486.5217
1813
0.7956
30
1725
0.73
0.725
0.735
2363.01
2379.31
2346.9388
1.5265
0.7965
0.8015
0.7915
2456.2500
1760
0.8232
31
1800
0.77
0.765
0.775
2337.66
2352.94
2322.5806
1.5929
0.8229
0.8279
0.8179
2426.3200
1708
0.8499
32
1875
0.81
0.805
0.815
2314.81
2329.19
2300.6135
1.6593
0.8493
0.8543
0.8443
2395.7692
1658
0.8758
33
1950
0.86
0.855
0.865
2267.44
2280.70
2254.3353
1.7257
0.8657
0.8707
0.8607
2367.5926
1609
0.9008
34
2025
0.91
0.905
0.915
2225.27
2237.57
2213.1148
1.7920
0.8820
0.8870
0.8770
35
2100
0.96
0.955
0.965
2187.50
2198.95
2176.1658
1.8584
0.8984
0.9034
0.8934
36
2175
1.01
1.005
1.015
2153.47
2164.18
2142.8571
1.9248
0.9148
0.9198
0.9098
37
2250
1.06
1.055
1.065
2122.64
2132.70
2112.6761
1.9912
0.9312
0.9362
0.9262
Column B of above spreadsheet shows the specified distance and the specified time for that distance.
Column C shows the specified time for the distance traveled.
Column D shows the time rounded down to the minimum time possibly explained by rounding.
Column E shows the time rounded up to the maximum time possibly explained by rounding.
Column F shows the Average Velocity (d/t) calculated with the unadjusted time from Column C.
Column G shows the Average Velocity (d/t) calculated with the minimum time possible from Column D. This minimum time of flight shows the maximum possible average velocity of the bullet.
Column H shows the Average Velocity (d/t) calculsted with the maximum time possible from Column E. This maximum time of flight show the minimum average velocity of the bullet.
Column I shows the time for sound to travel the distance at 1130 fps.
Column J shows the time difference between the bullet and the sound using unadjusted time from Column C.
Column K shows the maximum possible time difference between the bullet and the sound using the time rounded down in Column D.
Column L shows the minimum possible time difference between the bullet and the sound using the time rounded up in Column E.
Column N states VXH Average Velocity using undisclosed math, presumably of Klingon origin.
Column O states the instantaneous velocities at the distances specified in Column B. There velocities reflect a specific and infinitesimal point it time only, and do not describe velocity at any other point in time.
Comparing Columns H and N, Column H calculates the maximum possible average velocity with the time round down as far is is possible. Column N is the average velocity claimed by VxH, using his secret Klingon mathematics.
Notice his secret method obtain an average velocity well below the maximum possible for 75 feet, but comes nearer to the maximum possible with every calculation, and at 1200 feet his calculations leave the realm of the possible.
At 1200 feet, at the specified time of 0.46 seconds, the average velocity would be 2608.70 feet per second (1200/0.46). Anyone can do the arithmetic. At 1200 feet, at 0.46 seconds rounded down as far as possible to 0.455 seconds (Column D), the maximum average veocity of 2637.36 feet per second (Column G) is achieved (2637.36/0.455). Anyone can still do the arithmetic. At this point, the VxH calculations exceed the possibilities of reality and achieve 2675.1176 feet per second.
After this point, every VxH calculation widens the error.
At 1950 feet, the Column G max average velocity is 2280.70 (1950/0.0855). After more calculations, the VxH error expands the difference to 2367.5926 feet per second.
If carried on to further distances, the error will simply keep increasing. He started with 64% of the maximum possible average velocity, and surpassed 100% of the maximum on his 16th calculation, and continued to surpass the maximum possible average velocity by a greater and greater amount.
Notice how VxH, in his calculations, at and after 1200 feet, reduces the time of flight of the bullet by more than any possible amount of rounding from two decimal places.
By 1950 feet, VxH has "rounded off" 0.86 and amazingly calculated, by secret methodology, the stated flight time to his own preferred 0.82621.
That is VxH bullshit. Not only wrong but impossible on its face.
[VxH]
1950 0.86 1609
Now tell us, Professor DonkeyChan - from the data provided, what is the average Velocity for the 75 ft segment ending at 1950 ft (1950ft, being the point at which, BTW, the instantaneous velocity is 1609fps)?
The average velocity of any object covering 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4419 feet per second. It could be a flying refrigerator. If it goes 1950 feet in 0.86 seconds, the average velocity is 2267.4419 seconds.
The object could have sped up and slowed down between 0 and 1950 feet in any manner and it makes no difference. If the object covers the 1950 feet in 0.86 seconds, the average velocity for the 1950 foot distance is 2267.4419 seconds.
Recall the Khan Academy video you previously referenced:
- [Instructor] Pretend you are a physics student. You are just getting out of class. You were walking home when you remembered that there was a Galaxy Wars marathon on tonight, so you'd do what every physics student would do: run. You're pretty motivated to get home, so say you start running at six meters per second. Maybe it's been a while since the last time you ran, so you have to slow down a little bit to two meters per second. When you get a little closer to home, you say: "No, Captain Antares wouldn't give up "and I'm not giving up either", and you start running at eight meters per second and you make it home just in time for the opening music. These numbers are values of the instantaneous speed. The instantaneous speed is the speed of an object at a particular moment in time.
And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.
Note that this is different from the average velocity. If your home was 1,000 meters away from school and it took you a total of 200 seconds to get there, your average velocity would be five meters per second, which doesn't necessarily equal the instantaneous velocities at particular points on your trip.
In other words, let's say you jogged 60 meters in a time of 15 seconds. During this time you were speeding up and slowing down and changing your speed at every moment. Regardless of the speeding up or slowing down that took place during this path, your average velocity's still just gonna be four meters per second to the right; or, if you like, positive four meters per second.
[snip]
The instantaneous velocity at 1950 feet is irrelevant to the calculation of the average velocity over the range 0 to 1950 feet.
How you coming along with that Average Velocity for the 75 foot segment ending at 1950 ft?
It came along quite well. Anything that travels 1950 feet in 1.06 seconds travels an average velocity of 2122.64 feet per second. The formula is distance divided by time.
How are you coming along with your bullet going splat at ~520 feet ground distance from Mandalay Bay?
How did you work out that negative 33º angle?
Side a represents the vertical height of Paddock's vantage point. At the 32nd floor, and at 10.9 feet per floor, (32-1) x 10.9 = 338 feet.
The VxH specified shooting angle was -33°. This should probably be expressed as a positive angle of declination. Not all ballistic calculators will even accept a negative angle value, but specify 0 to 90 degrees.
It appears that VxH drew an imaginary horizontal line d at a vertical height of 338 feet from the ground, and an imaginary 338 foot line e down to the ground, bringing into view a rectangle with a mirror image triangle to that above.
VxH guessed 33º as the acute angle formed at the junction of sides c and imaginary side d at point B. VxH guessed very wrongly.
With a specified shooting angle of 33º at the junction of lines c and d, the angle made by sides c and b would also be 33º, and angle ß, made by sides a and c would be 57º. (The right angle at point A is 90º. The other two angles must add up to 90º.)
With side a being 338 feet, side b would be 520.4743578 feet, and side c would be 620.5944 feet.
As may be seen, disregarding gravity, if the bullet flew downward at the specified 33º from a height of 338 feet, it would fly a straight line of sight path into the ground at ~520 feet from the Mandalay Bay at ground level.
Calculating the bullet velocity after that point may be difficult, even with secret Klingon math.
This should probably be expressed as a positive angle of declination.
BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity:
There is no 33 degree angle involved. Using your trajectory, Paddock would have come closer to shooting off his big toe than hitting anywhere in the festival venue.
Learn to read:
Declination is downward. Negative 33 degrees inclination is the same as 33 degrees declination. It is the difference between your preferred -33 degrees upward and 33 degrees downward.
It is like walking negative 33 feet east is walking 33 feet west.
The VxH specified shooting angle was -33°. This should probably be expressed as a positive angle of declination. Not all ballistic calculators will even accept a negative angle value, but specify 0 to 90 degrees.
The gundata entry specifies "Shooting angle (0..89)." Stick a negative value in there and it will reject.
As there is no such thing as a triangle with negative angles, the values for every angle of a triangle are positive values.
In a triangle with sides -3 and -4, a2 + b2 = c2 would yield a hypotenuse of positive 5.
BZZZT! Probably not, since using 0.33 instead of -0.33 produces a slower velocity:
(0.33) 1950 0.89 1489
(-0.33) 1950 0.86 1609
The data available at the links shows the only data change between my two charts is one is -33 and the other is 33. Not so for the chart you just created with yet another time calculation. You changed the input data.
This chart made with the original -33 data, shows the bullet rise above the original altitude, and remain above that altitude, for over 300 yards. This is an amazing feat for a bullet shot on a steep downward angle.
Amazingly, when the angle is changed from -33 to 33, the flight path does not change, according to your calculator.
- - - - - - - - - -
When your calculator permits you to enter ridiculous data, it provides you with ridiculous results.
As one may observe, it provides the precise same flight trajectory, whether at 33 or -33. When fired at 33 degrees downward, the bullet goes upward and remains above the original location for over 300 yards.
The data available at the links shows the only data change to be -33 to 33.
The time for 650 yards/1950 feet is 0.86 in either instance. The average velocity for any object that travels 1950 feet in 0.86 seconds is 1950/0.86 = 2267.4418 ft/sec.
- - - - - - - - - -
YOUR DATA WITH A NEW TIME SHOWS YOU ALTERED THE INPUT DATA.
And your flight trajectory chart for -33 degrees featuring a new time