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Title: Forensic acoustic proof of SECOND shooter in the Las Vegas massacre
Source: [None]
URL Source: https://www.youtube.com/watch?v=JxmEFeKy8aI
Published: Oct 11, 2017
Author: Mike Adams TheHealthRanger
Post Date: 2017-10-11 00:40:47 by A K A Stone
Keywords: None
Views: 45558
Comments: 148

Post Comment   Private Reply   Ignore Thread  


TopPage UpFull ThreadPage DownBottom/Latest

Begin Trace Mode for Comment # 122.

#1. To: nolu chan, VXH, buckeroo, tooconservative, cz82, redleghunter (#0)

Found this interesting video.

A K A Stone  posted on  2017-10-11   0:41:36 ET  Reply   Untrace   Trace   Private Reply  


#73. To: A K A Stone, VXH, buckeroo, tooconservative, cz82, redleghunter, sneakypete, Pinguinite, Vicomte13, Liberator, Deckard (#1)

Found this interesting video.

Adams assumes a shooter using an AR-15 with .223 Remington 55 grain ammo.

He states 20% humidity.

He states a 925 m/s bullet velocity which is ~3034.8 fps.

He specifies a 16.5" barrel, but a 3034.8 fps initial velocity would seem to indicate a 20" barrel or different ammo.

I believe the white board has an error. The flight time should be 0.532s, not 0.528s.

It lists both the 400 yard flight time and the lag time as 0.528s. This would mean the bullet velocity was precisely double the speed of sound, and that double 0.528s, or 1.056s would be the 400 yard travel time for the speed of sound. The time of sound travel for 400 yards at 1130 fps is 1.062.

http://gundata.org/blog/post/223-ballistics-chart/

He cites his use of a gundata ballistics chart for travel time.

gundata indicates for 400 yards, the time of travel is 5.32s, specifying a standard 55gr Remington .223 bullet leaving the barrel at 3,215fps. Adams also specified a 16.5 inch barrel, but it seems an AR-15 with a 16.5 barrel does not achieve 3,215 initial velocity.

https://rifleshooter.com/2014/04/223-remington5-56-nato-velocity-versus-barrel-length-a-man-his-chop-box-and-his-friends-rifle/

Testing with different barrel lengths indicates an AR-15, 16.5" barrel, with Remington .223 ammo, does not achieve 3,034.8 muzzle ("initial") velocity.

With a 20" barrel, the same setup gets 3,071 fps muzzle velocity.

A 25" barrel gets it up to 3,221 fps muzzle velocity.

A 16.5" with Federal M193/55 gets 3,187 fps muzzle velocity.

http://guide.sportsmansguide.com/ballistic-chart/remington_charts/223rembal.htm

A ballistics chart indicates that a Remington .223 will not get the stated bullet velocity.

Assuming the shots were fired from room 32135, and that end of the Mandalay Bay Hotel was 1208 feet from the base of the bandstand, and that a bullet struck the pavement at or near the base of the bandstand, the long side a right triangle would be 1208 feet and the short side would be the height of room 32135.

The building claims a height of 480 feet and 44 stories, for an average of 10.91 feet per story. The 32nd floor would be 338.21 feet up. (31 x 10.91, base of floor 1 has zero height).

With sides of 1208 and 338.21, the hypotenuse would be 1254.45 feet.

The actual distance the bullet traveled would be more than that as it would not follow a straight path, but would follow an arc.

Using estimates of distance to striking the venue surface of ~1250 feet, and detected lag times of 0.559 sec and 0.374 sec, the slower bullet made the 0.374 lag time; the faster bullet arrived .559 sec before the muzzle blast.

At 1130 fps, the sound would cover 1250 feet in about 1.106 seconds.

A bullet making the 1250 ft trip .559 sec before the sound, made the trip in .547 sec.

A bullet making the 1250 ft trip .374 sec before the sound, made the trip in .732 sec.

1250 feet in .547 sec is an avg velocity of ~2236 fps.

1250 feet in .732 sec is an avg velocity of ~1708 fps.

This assumes both shots were taken from the same location.

What bullets were used can be ascertained by collecting the bullets. What was left in the room should be inventoried, along with what guns were in the room.

http://onyourownadventures.com/hunttalk/showthread.php?267715-308-Ammo-Help/page2

Thread: 308 Ammo Help

Most mfgs recommend a minimum velocity of 1800 fps for proper expansion. The so called "magic number" associate with elk hunting is 1200 lb ft Energy. Below that is risky and I prefer 1400 lb ft as my personal standard. Although every gun is different the ammo mfg. Will put their tested numbers out for their loads. According to Federal their TBT 165 gr out of a 308 maintains 1939 fps and 1377 lb ft at 500 yards. Mathematically that should do the job as long as the bullet hits it's mark. Federal lists the same weight game King at 1708 FPS and 1069 ft lb at 500 yards. Obviously not the best option. If you keep 400 yards and in either a 150 or 165 gr factory loaded bonded round should work fine on elk. You just need to find the one that goes exactly where you want it to every time you press the trigger.

This would suggest the possibility of the 1708 fps round being a .308 (or whatever else gets around 1708 fps at 400 - 450 yards.

http://gundata.org/blog/post/223-ballistics-chart/

This is a .223 ballistics chart (external) generated using our ballistic trajectory calculator. Based off a standard 55gr bullet leaving the barrel at 3,215fps and follows the bullet trajectory all the way to 1000 yards in steps of 50 yard increments. The charting shows the range, drop (based off a 1.5" scope mount), current velocity, energy, and time in seconds in relation to the bullets movement through space and time. This chart does not account for atmospheric conditions, so if you want to take in to effect these things check out the calculators official page. The Ballistic Coefficient for the .223 Remington, Remington Metal Case, 55gr is 0.202 (in this example) but, but may also range from .185 bc to .257

[...]

.223 Remington, Remington Metal Case, 55gr.

400 yards
-31.7981 [drop, inches]
1588 [Velocity]
308 [energy]
532 [time, milliseconds]

This ballistics chart indicates .532 seconds for 400 yards, at 1588 velocity.

.532 seconds would indicate 2255.6 average velocity for the 400 yards, and the velocity of the bullet leaving the barrel is specified at 3215 fps.

nolu chan  posted on  2017-10-18   19:05:32 ET  Reply   Untrace   Trace   Private Reply  


#78. To: nolu chan (#73)

All numbers he pulled out of his arse?

Plus there's the little problem that he doesn't present any actual audio evidence.

VxH  posted on  2017-10-21   22:03:05 ET  Reply   Untrace   Trace   Private Reply  


#81. To: VxH (#78)

All numbers he pulled out of his arse?

Plus there's the little problem that he doesn't present any actual audio evidence.

The audio he used is presented.

Your chartoon is an absurdity.

nolu chan  posted on  2017-10-23   13:15:59 ET  Reply   Untrace   Trace   Private Reply  


#82. To: nolu chan (#81) (Edited)

The audio he used is presented.

LOL. He scribbled on a whiteboard.

The amplitude graphs of the audio referenced on my meme can be reproduced by anyone with minimal tools. It's REPRODUCIBLE - that's what differentiates valid science from conspiratorial buffoonery.

Show us the actual amplitude graphs or STFU.

VxH  posted on  2017-10-23   13:21:45 ET  Reply   Untrace   Trace   Private Reply  


#83. To: VxH (#82)

The amplitude graphs of the audio referenced on my meme can be reproduced by anyone with minimal tools. It's REPRODUCIBLE - that's what differentiates valid science from conspiratorial buffoonery.

That you reproduce meaningless bullshit is meaningful, but not as you intend.

nolu chan  posted on  2017-10-23   17:53:28 ET  Reply   Untrace   Trace   Private Reply  


#86. To: nolu chan (#83)

That you reproduce meaningless bullshit is meaningful

The amplitude graphs are reproducible by anyone who has simple tools and access to the video on Youtube.

Where's yours?

VxH  posted on  2017-10-23   20:36:49 ET  Reply   Untrace   Trace   Private Reply  


#88. To: VxH (#86)

The amplitude graphs are reproducible...

Proving imbeciles can reproduce. As the U.S. Supreme Court observed, "Three generations of imbeciles are enough."

Your chartoons, with your hilarious analysis, are entertaining, sort of like the scientific sounding youtubers preaching flat Earth theory.

nolu chan  posted on  2017-10-24   1:23:27 ET  Reply   Untrace   Trace   Private Reply  


#89. To: nolu chan (#88)

The amplitude graphs are reproducible by anyone who has simple tools and access to the video on Youtube.

Where's yours?

{ shrug } Maybe you just don't have what it takes.

VxH  posted on  2017-10-24   9:42:51 ET  Reply   Untrace   Trace   Private Reply  


#90. To: VxH (#89)

Maybe you just don't have what it takes.

On your spreadsheet chartoon, notice that you calculate T = Tb - Ts.

You calculate elapsed time as the time it took the bullet to travel, minus the time it took the sound to travel.

As the bullet is supersonic, and sound is a constant, the sound would travel 400 yards in 1.06s and the bullet would travel the 400 yards in less than 1.06s. Subtracting 1.06 from a smaller number will always yield a negative number.

At 1200 feet, you actually calculate Tb as 0.448578s, and Ts as 1.062s and calculate the T as -0.6126, negative 0.6126 seconds. The average donkey could recognize that something is wrong when the result is negative time.

Just what do you think happens in negative 0.6126 seconds?

You could at least recognize that if you get a negative number, you have stated the required formula backwards, and you proceeded to perform the calculation backwards, and present the bass ackwards result of your understanding of the study you looked at.

You've got what it takes to make bullets travel in negative time.

Your brain apparently has zero amplitude.

nolu chan  posted on  2017-10-25   2:15:35 ET  Reply   Untrace   Trace   Private Reply  


#91. To: nolu chan (#90) (Edited)

>>at 1200 feet, you actually calculate Tb  as 0.448578s, and Ts as 1.062s and calculate the T as -0.6126, negative 0.6126 seconds.

0.448578 is the ballistic projectile time. 1.062 is the time to travel the same distance at the speed of sound

The MEASURED, absolute value, of the Ellapsed Time difference, per the audio amplitude graph...

...between the Last Bullet sound event and the Last Report sound event is 0.689655 

Now, ask your donkey - what distance does that MEASURED absolute time difference correspond to on the chart?


 

VxH  posted on  2017-10-25   10:14:11 ET  (2 images) Reply   Untrace   Trace   Private Reply  


#92. To: VxH (#91)

Now, ask your donkey - what distance does that MEASURED absolute time difference correspond to on the chart?

No Absolute value is ever expressed as a negative number. Had your undisclosed formula for the last column of your spreadsheet included code to express an absolute value, your spreadsheet results would not appear as negative numbers. But your spreadsheet displays negative numbers and you did not even question it or fix your spreadsheet.

The results should all be positive, like this:

Bullet Time, Velocity FPS, Tb–Ts

d = distance 400 yards, 1200 feet
Tb = Time of bullet
Ts = Time of sound, 1.062 seconds @ 1,130 feet per second (FPS) (72ºF, 20% Humidity)
Ts – Tb = Time difference between Tb and Ts

Column 1 = d/FPS = time in seconds
Column 2 = Tb stepped in 100 FPS increments, beginning with Ts
Column 3 = Ts – Tb (time in seconds supersonic bullet arrives ahead of sound)

Row 1 = directly inserted data. Data display is set to show 3 decimal places.

  • 1.062947 is the time for sound to travel 400 yds/1200 ft.

  • 1130 is the distance sound travels in one second. Here it is stated as an assumed bullet average velocity over 400 yds/1200 ft.

  • 0.000 is the time difference between a bullet traveling the speed of sound over 1200 ft and sound traveling 1200 feet.

Row 2 = spreadsheet formulas

  • Column 1 = 1200 / column 2 (distance / bullet avg velocity) bullet travel time for 1200 ft.

  • Column 2 = Row 1, Col 1 + 100 (stepping the assumed bullet velocity by 100 fps).

  • Column 3 = 1.061947 - Row 2, Col 1 (time of sound @1200 ft - time of bullet travel) = time diff between time of sound and time of bullet at 1200 ft.

The formulas for Row 2 are dragged down to generate Rows 3-30.

Bullet time (s), Bullet average velocity (FPS), time difference to sound at 1,200 feet (s)

Bullet time (s)Bullet average vel FPSTime diff Ts-Tb

1.06211300.000

0.97612300.086

0.90213300.160

0.83914300.223

0.78415300.278

0.73616300.326

0.69417300.368

0.65618300.406

0.62219300.440

0.59120300.471

0.56321300.499

0.53822300.524

0.51523300.547

0.49424300.568

0.47425300.588

0.45626300.606

0.44027300.622

0.42428300.638

0.41029300.652

0.39630300.666

0.38331300.679

0.37232300.690

0.36033300.702

0.35034300.712

0.34035300.722

0.33136300.731

0.32237300.740

0.31338300.749

0.30539300.757

0.29840300.764

nolu chan  posted on  2017-10-25   19:55:59 ET  Reply   Untrace   Trace   Private Reply  


#93. To: nolu chan (#92) (Edited)

>>No Absolute value is ever expressed as a negative number.

 

https://www.mathsisfun.com/numbers/absolute-value.html

===========

Since we KNOW from the observed audio Vb is supersonic, we can treat the difference between Tb and Ts as Absolute.

Range corresponds to the ABSOLUTE value of the difference in time.

VxH  posted on  2017-10-25   20:06:00 ET  (1 image) Reply   Untrace   Trace   Private Reply  


#95. To: VxH (#93)

Since we KNOW from the observed audio Vb is supersonic, we can treat the difference between Tb and Ts as Absolute.

I know. They have a spreadsheet function for that. It has been around since Lotus 123 and Quatro. ABS(number).

nolu chan  posted on  2017-10-26   2:26:21 ET  Reply   Untrace   Trace   Private Reply  


#96. To: nolu chan (#95) (Edited)

They have a spreadsheet function for that.

Yes, but in this case the ABS is implied in knowledge of what the spreadsheet is actually calculating.

If you applied ABS(Tb-Ts-) the chart would loose the information regarding whether the Vb was super-sonic or not, which the negative numbers conveniently tell us.

The author's formula works just fine without your tweakage.

http://ww w.btgresearch.org/AcousticReconstruction02042012.pdf

And that IS the same formula I have in my illustration:


VxH  posted on  2017-10-26   11:08:52 ET  (2 images) Reply   Untrace   Trace   Private Reply  


#97. To: VxH (#96)

Why do you keep posting this chartoon when all your data is not only wrong, but farcical? The only things you proved is that you do not know how to calculate the average velocity of an imaginary bullet and you are hopeless at spreadsheets. Your entertainment value as a useful idiot is over for now, and you will never figure it out without more help. Help is on the way, grasshopper.

Columns 1, 2, and 3 are direct entry of data generated by entering imaginary data into a generator at http://www.shooterscalculator.com/. I replicated the data taken from the calculator with “My BB's.” If I input initial velocity as 3240 fps, and other data, and call it “My BB's,” I can show a chart for magical bb’s.

http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=34fa8220

The Shooter’s Calculator only provides a result based on user input. It does not present a spreadsheet with the formulas to generate the data. The data from the Calculator can be cut and pasted into a spreadsheet, or entered by direct entry; this produces data in the cells, but no spreadsheet formulas in the cells. The chart states the speed of sound as 1130 feet per second (fps).

The remaining 4 columns, (4, 5, 6, 7) were generated by VxH.

Column 6 uses 1130.8 fps to calculate the time for sound to travel the distance stated in Column 1.

Column 4 is labeled as (Avg V) Vb. This column purports to present the average velocity of the bullet to cover the distance for the row it is in. All of the data in this column is epically wrong as the methodology of calculation is absurdly wrong.

To calculate the average velocity of the bullet, divide distance by time.

Instead of this, a personal misbegotten formula was used. Probably a pocket calculator for each cell in Column 4 was used to perform the calculations, and the data was directly entered into the cells by hand.

For the first two data rows, sum 3240 and 3163 and divide by 2. 6403/2 yields the 3201 in Column 4.

For the first three data rows, sum 3240+3163+3088 for 9491. 9491 / 3 yields the 3163.6667 in Column 4.

And so on, and so forth. All the calculated Column 4 data (average Vb), is garbage.

The chosen methodology was to sum the velocity given for each distance, and divide by the number of elements summed. This produces nonsensical data.

Example: You drive a car 100 miles at 80 mph. You drive another 100 miles at 20 mph. With this bogus methodology, 80 + 20 = 100, divide by 2, and your average velocity was 50 mph. Not.

In the real world, you drove 100/80 or 1.25 hours at 80 mph. You drove 100/20 or 5 hours at 20 mph. And you drove 200 miles in 6.25 hours. Your average speed was 200/6.25, or 32 mph.

Column 4, in addition to using an absurd methodology for its calculations, also incorporates two summing errors for the velocities taken from Column 3, at 900 feet and 1275 ft. In each case, the actual sum was 1 less than that calculated.

Spreadsheet formulas are not prone to fat finger syndrome, and do not make such errors, but someone with a pocket calculator or pen and paper does. The data was typed in after external calculation.

Where you calculate 2367.5926 average Vb at 1950 feet, 1950/1.211933 (the velocity of the bullet in Column 5), it yields 1608.9998 fps, remarkably close to the 1609 in Column 3. But then, the elapsed time in Column 2 is 0.86, not 1.21933. It is a conundrum how the bullet traveled for 1.21933 seconds in an elapsed time of 0.86 seconds.

Of course, when you use Column 1 1950 ft and Column 3 1609 fps to derive the time of flight, the formula is d/Vb, and Vb is the Average Velocity.

The bullet will travel 1905 feet distance (Col 1) in 0.86 sec time (Col 2) in 1905/0.86 or 2267.4418 average Vb. Stated in your headnote is Tb is d/Vb.

It is noteworthy that you used Column 3 as the "average" velocity of the bullet in order to derive the other average velocity of the bullet in Column 4.

Column 5 (Tb) incorporates the garbage data from Column 4 into its calculations, and all the resulting calculated data is wrong. GIGO.

Column 7 (T = Tb – Ts) incorporates the garbage data from Column 5 and all the calculated data is wrong. GIGO.

The chart is multicolor and pretty, but the data for the imaginary bullet is demonstrably wrong in every column you created, except for column 6 where you succeeded in dividing the distance by 1130.8.

nolu chan  posted on  2017-10-28   15:12:09 ET  (1 image) Reply   Untrace   Trace   Private Reply  


#99. To: nolu chan (#97) (Edited)

>> and the data was directly entered into the cells by hand.

Bzzzt.  Fail again.

Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°
Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 750 yd
Maximum Range: 50002 yd
Step Size: 25 yd
Corrected For Atmosphere
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fps

RangeTimeVel[x+y]
(ft) (s) (ft/s)
00.003240
750.023163
1500.053088
2250.073014
3000.102941
3750.122870
4500.152799
5250.182730
6000.202662
6750.232595
7500.262529
8250.292465
9000.322401
9750.362337
10500.392275
11250.422214
12000.462154
12750.492095
13500.532036
14250.561979
15000.601923
15750.641867
16500.681813
17250.731760
18000.771708
18750.811658
19500.861609
20250.911561
21000.961515
21751.011470
22501.061426

VxH  posted on  2017-10-28   17:36:21 ET  (2 images) Reply   Untrace   Trace   Private Reply  


#101. To: VxH, A K A Stone (#99)

and the data was directly entered into the cells by hand.

Bzzzt. Fail again.

Nope. You said you created spreadsheet and used their formulas. Had you used their formulas you would not have bullshit results, including arithmetic errors in the columns.

Which formula of theirs did you use to manufacture the wrong bullet velocities?

Cite any source that says to find average velocity with the method you used.

When you introduced this bullshit on the other thread at your #19 to A K A Stone, you said:

https://libertysflame.com/cgi-bin/readart.cgi?ArtNum=53046&Disp=19#C19

I found/took their formula, built a spreadsheet, and plugged in 223 balistic data generated via shooterscalculator.com:

Only you did not use their formulas or you would not have gotten all the data you derived bass ackwards wrong, and you did not create formulas and drag them down through the rows, or you would not have the calculation errors the are apparent.

I created a spreadsheet using the same data and created formulas and dragged them down through the rows. They work. That is how I can pinpoint where you made calculating errors in your data entry.

All you did was cut and paste the chart data into a spreadsheet workbook.

Columns 1 thru 3 were cut and paste.

For Column 4, there is no chance that you created a formula and dragged it down through the rows. You go off at range 900 where you summed to 36497 instead of 36496. This error of 1 continues through to range 1275, where you summed to 47,572 instead of 45,570. This put the summing error at 2, which continued through range 1950 where you ended.

This is not a spreadsheet error. I used two different formulas to sum the velocities, with results identical to each other. You used no formula. You sat there with your pocket calculator and added the first two and typed in the result. Then you added the third velocity and typed in the result. And you did this for each data entry in that column. If you have any spreadsheet formula that can replicate your results, produce it.

As Column 4 calculates the sum of the velocities divided by the number of velocities, and the sum of the velocities was not created by a formula on a spreadsheet column, the column was manual data entry.

In Column 5, d/Vb, the distance is correctly divided by the bogus average velocity, yielding a bogus result. When it is as simple as programming one column divided by another, good job. When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.

In Column 6, I stated you were able to divide distance by 1130.8. When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.

In Column 7, you managed to correctly subtract the bogus data in Column 5 from the bogus data in Column 6, yielding all bogus results. When it is as simple as programming one column subtracted from another, good job. It should have included an ABS function to avoid getting negative time results.When it is summing a changing number of rows, fuhgetaboutit. That was direct data entry with arithmetic errors.

As Columns 5 and 7 incorporate the brain dead data in Column 4, with a double whammy of a bogus formula and calculation errors, all data in Columns 5 and 7 is bogus.

Your chart in Column 2 from btgresearch indicates Tb for range 1950 is 0.86 seconds. Column 5 for 1950 range indicates Tb is 0.823621. You call that fixing a rounding error???? How did displaying only two decimal places to 0.86 convert to 0.823621????

nolu chan  posted on  2017-10-29   0:02:55 ET  Reply   Untrace   Trace   Private Reply  


#105. To: nolu chan (#101) (Edited)

You stipulate a DISTANCE ratio of 99:1. Nice try.

I correctly illustrate the flaw inherent in taking a momentary point velocity of a continuously decelerating proctile and ASSuming it to be an average.

There's a question regarding whether the value of Vel[x+y] for a given 75ft vector segment is the average Velocity OR whether it's just the momentry V at point d.

Here is the spreadsheet updated with Tcalc where Tcalc is an attempt to reconstruct the elapsed Time for a given Vector:

 

We're moving in the right direction - but the calculation for Tcalc could be even more accurate by deriving it from the slope of the DIFFERENCE between Vmin and Vmax for a given vector segment, rather than taking momentary V at point d and ASSuming it's a constant velocity over the entire 75ft segment... like you are.

VxH  posted on  2017-10-29   10:56:39 ET  (1 image) Reply   Untrace   Trace   Private Reply  


#120. To: VxH, A K A Stone (#105)

I correctly illustrate the flaw inherent in taking a momentary point velocity of a continuously decelerating proctile and ASSuming it to be an average.

There's a question regarding whether the value of Vel[x+y] for a given 75ft vector segment is the average Velocity OR whether it's just the momentry V at point d.

The problem is that you are clueless and do not know what your are doing and do not know what a vector is.

Here is a correct spreadsheet:


BALLISTICS DATA SPREADSHEET

A1 AVERAGE VELOCITY AND TIME DIFF OVER TOTAL DISTANCE AVERAGE VELOCITY FOR EACH 75 FEET SEGMENT
2
3 B C D E F G H I J K L
4 d Time (avg) Vel[x+y] Ts=d/Vs T=Tb - Ts Tb 75 ft Avg Velocity for Segment Segment Segment
5 (ft) d/Vel[x+y] (ft/s) d/Vs ABS(Tb-Ts) +C7-C6 75 foot segment distance begin end
6 0 0.0000 3240 +75/H4 +B7-B6 +K7+75 A7
7 75 0.0237 3163 0.0664 0.0427 0.0237 3163.0000 75 0 75
8 150 0.0486 3088 0.1327 0.0842 0.0249 3016.4744 75 75 150
9 225 0.0747 3014 0.1991 0.1245 0.0261 2876.1533 75 150 225
10 300 0.1020 2941 0.2655 0.1635 0.0274 2741.7798 75 225 300
11 375 0.1307 2870 0.3319 0.2012 0.0287 2617.2620 75 300 375
12 450 0.1608 2799 0.3982 0.2375 0.0301 2490.8930 75 375 450
13 525 0.1923 2730 0.4646 0.2723 0.0315 2378.2353 75 450 525
14 600 0.2254 2662 0.5310 0.3056 0.0331 2266.7686 75 525 600
15 675 0.2601 2595 0.5973 0.3372 0.0347 2160.0657 75 600 675
16 750 0.2966 2529 0.6637 0.3672 0.0364 2057.9351 75 675 750
17 825 0.3347 2465 0.7301 0.3954 0.0381 1967.1773 75 750 825
18 900 0.3750 2400 0.7965 0.4215 0.0403 1860.3774 75 825 900
19 975 0.4172 2337 0.8628 0.4456 0.0422 1777.1863 75 900 975
20 1050 0.4615 2275 0.9292 0.4677 0.0443 1691.5924 75 975 1050
21 1125 0.5081 2214 0.9956 0.4874 0.0466 1609.7315 75 1050 1125
22 1200 0.5571 2154 1.0619 0.5048 0.0490 1531.4566 75 1125 1200
23 1275 0.6089 2094 1.1283 0.5194 0.0518 1448.4509 75 1200 1275
24 1350 0.6631 2036 1.1947 0.5316 0.0542 1384.2156 75 1275 1350
25 1425 0.7201 1979 1.2611 0.5410 0.0570 1315.8863 75 1350 1425
26 1500 0.7800 1923 1.3274 0.5474 0.0600 1250.6135 75 1425 1500
27 1575 0.8436 1867 1.3938 0.5502 0.0636 1179.8360 75 1500 1575
28 1650 0.9101 1813 1.4602 0.5501 0.0665 1127.9144 75 1575 1650
29 1725 0.9801 1760 1.5265 0.5464 0.0700 1071.1245 75 1650 1725
30 1800 1.0539 1708 1.5929 0.5391 0.0738 1016.9418 75 1725 1800
31 1875 1.1309 1658 1.6593 0.5284 0.0770 973.8184 75 1800 1875
32 1950 1.2119 1609 1.7257 0.5137 0.0811 925.3285 75 1875 1950
33 2025 1.2972 1561 1.7920 0.4948 0.0853 879.1211 75 1950 2025
34 2100 1.3861 1515 1.8584 0.4723 0.0889 843.7085 75 2025 2100
35 2175 1.4796 1470 1.9248 0.4452 0.0935 802.5405 75 2100 2175
36 2250 1.5778 1426 1.9912 0.4133 0.0982 763.3722 75 2175 2250
37
38 Total
39 1.5780
40 SUM G7:G36



As a vector is described by a line and not a point, the Column D velocity at 75 feet describes the average bullet velocity for the segment from 0 to 75 feet, and the velocity at 150 feet describes the average bullet velocity from 0 to 150 feet, and so on.

The time for 75 feet indicates the elapsed time for 0 to 75 feet. The time for 150 feet indicates the elapsed time for 0 to 150 feet.

Column C, the time, is derived by dividing Column B (distance) by Column D. In your chart it is was rounded off to two decimal places. I took it to four decimal places.

Your added Rube Goldberg nonsense was not only wrong but unecessary. Average velocity at the stated distances was staring you in the face.

In Columns H thru L, I have provided the data for each 75-foot segment.

At 1575 feet, the bullet opens its largest gap on sound at 0.05502 seconds.

From 1575 to 1650 feet, the bullet travels at an average velocity of 1127.9144 fps, dipping below the speed of sound. After that, sound is traveling faster than the bullet and the gap diminishes.

nolu chan  posted on  2017-10-30   19:52:22 ET  Reply   Untrace   Trace   Private Reply  


#121. To: nolu chan (#120) (Edited)

>>Here is a correct spreadsheet

Too bad it's not one you created with ballistic data as per the methodology:

http://www.btgr esearch.org/AcousticReconstruction02042012.pdf

Meanwhile,

Please explain how, in the context of the highlighted range of interest on the concert field, Your idea to reconstruct Time by taking (d=75ft)/Vel[x+y] does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into " bullshit"

?

Illustration A: Vb calculated from d/Tcalc, where Tcalc= (d=75ft)/Vel
Illustration B: Vb using my original Average of summed Velocity values.

A:  B:

Please explain how, in the context of the highlighted range of interest on the concert field, Noluchan's idea to reconstruct Time by taking (d=75ft)/Vel[x+y]
 does not seem to produce results that magically render the values produced by summing and averaging Vel[x+y] into " bullshit"

?


VxH  posted on  2017-10-30   21:09:34 ET  (2 images) Reply   Untrace   Trace   Private Reply  


#122. To: VxH (#121) (Edited)

It surprises me a little that we have seen no attempts at forensic reconstruction of the shooting by recognized shooting experts and/or audio experts. Other than that sad-sack attempt by the NYSlimes, I haven't seen anything along these lines.

There are experts out there. So why aren't we hearing from them? Is it because they find the audio data to be ambiguous? Who knows.

Tooconservative  posted on  2017-10-30   21:15:42 ET  Reply   Untrace   Trace   Private Reply  


Replies to Comment # 122.

#123. To: Tooconservative (#122)

There are experts out there. So why aren't we hearing from them?

I asked the authors of the study

http://www.btgresearch.org/AcousticReconstruction02042012.pdf

They replied:

"our standard operating procedure is to avoid public comments on shooting events. This better protects our neutrality and value of our analysis in the event that we are retained by an agency or party to subsequent legal proceedings. We also like to restrict our analysis to materials that come into our possession following a proper and documented chain of custody regarding handling of evidence.

When it comes time for depositions or courtroom testimony, most experts who have made prior public comments on a matter find that opposing legal counsel, opposing experts, and the blogosphere find ways to make them regret earlier public comments."

===============

In light of what can be observed here - that makes sense.

VxH  posted on  2017-10-30 21:22:28 ET  Reply   Untrace   Trace   Private Reply  


End Trace Mode for Comment # 122.

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