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Title: Video claims shooter dressed as police
Source:
[None]
URL Source: https://duckduckgo.com/?q=LAS+VEGAS ... a=videos&iax=1&iai=qMxn7hpXmk4
Published: Oct 8, 2017
Author: Planet X Investigations
Post Date: 2017-10-08 15:41:01 by A K A Stone
Keywords: None
Views: 47230
Comments: 186
Video claims shooter dressed as police Poster Comment: Video claims shooter dressed as police
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Begin Trace Mode for Comment # 152.
#1. To: A K A Stone (#0)
(Edited)
SMH. LOL.
You didn't have time to watch the video yet. Debunk it please.
It would be a positive number expression of time. On your spreadsheet chartoon, notice that you calculate T = Tb - Ts. You calculate elapsed time as the time it took the bullet to travel, minus the time it took the sound to travel. The correct formula should be T = Ts – Tb = d/Vs – d/Vb. As the bullet is supersonic, and sound is a constant, the sound would travel 400 yards in 1.06s and the bullet would travel in less than 1.06s. Subtracting 1.06 from a smaller number will always yield a negative number. At 1200 feet, you calculate Tb as 0.448578s, and Ts as 1.062s and calculate the T as -0.6126, negative 0.6126 seconds. The average donkey could recognize that something is wrong when the result is negative time. Just what do you think happens in negative 0.6126 seconds? You could at least recognize that if you get a negative number, you have stated the required formula backwards, and you proceeded to perform the calculation backwards, and present the bass ackwards result of your misunderstanding of the study you looked at. Moreover, while you state backwards that T = Tb - Ts, your spreadsheet never defines what T is supposed to represent. Negative 0.6126 is the time of what? What is the significance of this negative 0.6126 seconds (other than to demonstrate you did not understand the reference study)?
>>The correct formula should be T = Ts – Tb = d/Vs – d/Vb. Nope. You're not even reading from the relevant part of the paper - where the microphone adjacent to the victim scenario is discussed. http://ww w.btgresearch.org/AcousticReconstruction02042012.pdf That's the same formula I have in my illustration:
No, I read the correct part. The formula is correct for a supersonic bullet only if the value is explicitly expressed as an absolute. Otherwise, the correct value is derived by changing the formula. Either will work. You did neither and derived negative times and published them that way.
>>No, I read the correct part. LOL Here's what you quoted: ==================== A microphone was placed a few centimeters from the muzzle to record both the muzzle blast and the sound of the bullet hitting the deer. The time recorded between the muzzle blast and bullet striking the target represents the sum of the bullet time of flight (tb) and the time for the sound to return to the microphone from the target (ts), nolu chan posted on 2017-10-25 16:15:25 ET https://libertysflame.com/cgi- bin/readart.cgi?ArtNum=53025&Disp=120#C120 ==================== And this is the correct section of the paper that deals with a microphone AT THE TARGET, the scenario where the "shooter dressed as police" video in question was taken. http://ww w.btgresearch.org/AcousticReconstruction02042012.pdf >>The formula is correct for a supersonic bullet only if the value is explicitly expressed as an absolute The formula is fine just the way the authors of the paper wrote it. The negative time is perfectly acceptable IF you actually understand what the value and chart are saying: The sound of the Report (Ts) event was recorded 0.6126 seconds after Tb and that time differential corresponds to a distance of 1200 ft from the shooter.
Here's what you quoted: ==================== A microphone was placed a few centimeters from the muzzle to record both the muzzle blast and the sound of the bullet hitting the deer. The time recorded between the muzzle blast and bullet striking the target represents the sum of the bullet time of flight (tb) and the time for the sound to return to the microphone from the target (ts), t = ts + tb = d/Vs + d/Vb nolu chan posted on 2017-10-25 16:15:25 ET https://libertysflame.com/cgi-bin/readart.cgi?ArtNum=53025&Disp=120#C120 You are an ass. How many times did #120 explicitly say it was about your lame attempt to use the taxi video? The taxi was hardly at or near the origin point. It was 338+ feet away. The study placed a microphone "a few centimers" from the muzzle, not 10,302+ centimeters away. The taxi was 338 feet down, some distance out from the building. Even if directly opposite the taxi, the muzzle had to travel 338+ feet to get to the taxi. That still take 0.299 seconds for the muzzle blast to reach the taxi from 338 feet. Adjusting for your cited claim (at #118) that NYT reporting "suggests that Paddock was positioned directly above the camera at this point," with the taxi directly below the window, your blather has not materially changed the problem with your chartoon. The taxi microphone was not a few centimeters from the muzzle, it was over 338 feet away. The problem, of course, is related in your reference study. http://www.btgresearch.org/AcousticReconstruction02042012.pdf Using Sound of Target Impact for Acoustic Reconstructions of Shooting Events At page 2: t = ts + tb = d/Vs + d/Vb where d is the target distance, Vs is the velocity of sound, and Vb is the average bullet velocity over the distance. At page 5: At page 6: Your recording is at a taxi over 338 feet away from the muzzle. You can do all the calculations you desire and the microphone will be no closer to the muzzle. The muzzle was likely around the corner, about 338 feet up, and some angular distance away from the microphone in the taxi. The taxi did not pick up the sounds of the bullets striking people on the ground over 1200 feet away. The muzzle blast echoed back, but you do not know where from, or what path it took to the taxi at ground level. A taxi recording indicates the muzzle blast with a delay by the time the sound took to reach the taxi, about .299 seconds at 338 feet. During that delay, the muzzle blast is on its way to some reflective surface which redirects the sound by some route to the taxi at ground level. The elapsed time at the 338+ foot distant taxi is not the elapsed time of the muzzle burst soundwave out and back. You ignored the ~0.299 second initial delay to reach the taxi, and you have no idea what reflective surface(s) redirected the sound before the echo arrived at the taxi. You do have a nice picture with circles on it though. Also, as there was no firearm seen protruding from any window, if Paddock was the shooter, he and the firearm were inside the room. The sound of muzzle blast had to travel out through the hole in the window in a directional manner. No straight path to the taxi was available.
>>How many times did #120 explicitly say { blah blah blah } You might want to rethink the value of quoting yourself to "prove" what someone else said. Doesn't seem to be working very well for you. The Taxi Video applies to The Test for ECHO meme - not to the video/audio being discussed in this thread which asserts that "shooter dressed as police". That "shooter dressed as police" ASSertion is CLEARLY refuted by the audio data. Audio data that I've analysed using the correct forumula - which works just fine without your tweakage. http://ww w.btgresearch.org/AcousticReconstruction02042012.pdf And that IS the same formula I have in my illustration:
Why do you keep posting this chartoon when all your data is not only wrong, but farcical? The only things you proved is that you do not know how to calculate the average velocity of an imaginary bullet and you are hopeless at spreadsheets. Your entertainment value as a useful idiot is over for now, and you will never figure it out without more help. Help is on the way, grasshopper. Columns 1, 2, and 3 are direct entry of data generated by entering imaginary data into a generator at http://www.shooterscalculator.com/. I replicated the data taken from the calculator with “My BB's.” If I input initial velocity as 3240 fps, and other data, and call it “My BB's,” I can show a chart for magical bb’s. http://www.shooterscalculator.com/ballistic-trajectory-chart.php?t=34fa8220 The Shooter’s Calculator only provides a result based on user input. It does not present a spreadsheet with the formulas to generate the data. The data from the Calculator can be cut and pasted into a spreadsheet, or entered by direct entry; this produces data in the cells, but no spreadsheet formulas in the cells. The chart states the speed of sound as 1130 feet per second (fps). The remaining 4 columns, (4, 5, 6, 7) were generated by VxH. Column 6 uses 1130.8 fps to calculate the time for sound to travel the distance stated in Column 1. Column 4 is labeled as (Avg V) Vb. This column purports to present the average velocity of the bullet to cover the distance for the row it is in. All of the data in this column is epically wrong as the methodology of calculation is absurdly wrong. To calculate the average velocity of the bullet, divide distance by time. Instead of this, a personal misbegotten formula was used. Probably a pocket calculator for each cell in Column 4 was used to perform the calculations, and the data was directly entered into the cells by hand. For the first two data rows, sum 3240 and 3163 and divide by 2. 6403/2 yields the 3201 in Column 4. For the first three data rows, sum 3240+3163+3088 for 9491. 9491 / 3 yields the 3163.6667 in Column 4. And so on, and so forth. All the calculated Column 4 data (average Vb), is garbage. The chosen methodology was to sum the velocity given for each distance, and divide by the number of elements summed. This produces nonsensical data. Example: You drive a car 100 miles at 80 mph. You drive another 100 miles at 20 mph. With this bogus methodology, 80 + 20 = 100, divide by 2, and your average velocity was 50 mph. Not. In the real world, you drove 100/80 or 1.25 hours at 80 mph. You drove 100/20 or 5 hours at 20 mph. And you drove 200 miles in 6.25 hours. Your average speed was 200/6.25, or 32 mph. Column 4, in addition to using an absurd methodology for its calculations, also incorporates two summing errors for the velocities taken from Column 3, at 900 feet and 1275 ft. In each case, the actual sum was 1 less than that calculated. Spreadsheet formulas are not prone to fat finger syndrome, and do not make such errors, but someone with a pocket calculator or pen and paper does. The data was typed in after external calculation. Where you calculate 2367.5926 average Vb at 1950 feet, 1950/1.211933 (the velocity of the bullet in Column 5), it yields 1608.9998 fps, remarkably close to the 1609 in Column 3. But then, the elapsed time in Column 2 is 0.86, not 1.21933. It is a conundrum how the bullet traveled for 1.21933 seconds in an elapsed time of 0.86 seconds. Of course, when you use Column 1 1950 ft and Column 3 1609 fps to derive the time of flight, the formula is d/Vb, and Vb is the Average Velocity. The bullet will travel 1905 feet distance (Col 1) in 0.86 sec time (Col 2) in 1905/0.86 or 2267.4418 average Vb. Stated in your headnote is Tb is d/Vb. It is noteworthy that you used Column 3 as the "average" velocity of the bullet in order to derive the other average velocity of the bullet in Column 4. Column 5 (Tb) incorporates the garbage data from Column 4 into its calculations, and all the resulting calculated data is wrong. GIGO. Column 7 (T = Tb – Ts) incorporates the garbage data from Column 5 and all the calculated data is wrong. GIGO. The chart is multicolor and pretty, but the data for the imaginary bullet is demonstrably wrong in every column you created, except for column 6 where you succeeded in dividing the distance by 1130.8.
>> and the data was directly entered into the cells by hand. Bzzzt. Fail again. http://www.shooterscalculator.com/ballistic-trajectory-chart.php
There are no replies to Comment # 152. End Trace Mode for Comment # 152.
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#4. To: VxH (#1)
#119. To: A K A Stone (#4)
Debunk it please.
What would the Elapsed time between the Last Report sound event and the Last Bullet sound event be if, as the video alleged, the guy "dressed as police" was shooting?
#128. To: VxH, A K A Stone (#119)
What would the Elapsed time between the Last Report sound event and the Last Bullet sound event be....
#131. To: nolu chan (#128)
(Edited)
#135. To: VxH (#131)
You're not even reading from the relevant part of the paper - where the microphone adjacent to the victim scenario is discussed.
#136. To: nolu chan (#135)
(Edited)
t = ts + tb = d/Vs + d/Vb
#145. To: VxH (#136)
LOL
#120. To: VxH (#116)
Regarding my initial meme "TEST FOR ECHO" -- Balistic data is NOT required to determine the total distance sound traveling from, and echoing back to, the ORIGIN point which is essentially where the Taxi driver was.
Yeah, you make believe that the sounds recorded in the taxi can yield an accurate measurement of distance.
A microphone was placed a few centimeters from the muzzle to record both the muzzle blast and the sound of the bullet hitting the deer. The time recorded between the muzzle blast and bullet striking the target represents the sum of the bullet time of flight (tb) and the time for the sound to return to the microphone from the target (ts),
These results show that it is possible to use an audio recording of a shooting event to accurately determine the distance between the target and the shooter. In cases where the location of the microphone is different, the mathematical details are different, but the ideas are the same.
A significant weakness in the study is the placement of the microphone near the muzzle of the gun, an unlikely location in most forensic cases....
#146. To: nolu chan (#145)
(Edited)
#147. To: VxH (#146)
#152. To: nolu chan (#147)
(Edited)
Drag Function: G1
Ballistic Coefficient: 0.300
Bullet Weight: 62 gr
Initial Velocity: 3240 fps
Sight Height : 1.5 in
Shooting Angle: -33°Wind Speed: 0 mph
Wind Angle: 0°
Zero Range: 100 yd
Chart Range: 750 yd
Maximum Range: 50002 yd
Step Size: 25 ydCorrected For Atmosphere
Adjusted BC: 0.33
Altitude: 2000 ft
Barometric Pressure: 29.92 Hg
Temperature: 72° F
Relative Humidity: 21%
Speed of Sound: 1130 fpsRange Time Vel[x+y] (ft) (s) (ft/s) 0 0.00 3240 75 0.02 3163 150 0.05 3088 225 0.07 3014 300 0.10 2941 375 0.12 2870 450 0.15 2799 525 0.18 2730 600 0.20 2662 675 0.23 2595 750 0.26 2529 825 0.29 2465 900 0.32 2401 975 0.36 2337 1050 0.39 2275 1125 0.42 2214 1200 0.46 2154 1275 0.49 2095 1350 0.53 2036 1425 0.56 1979 1500 0.60 1923 1575 0.64 1867 1650 0.68 1813 1725 0.73 1760 1800 0.77 1708 1875 0.81 1658 1950 0.86 1609 2025 0.91 1561 2100 0.96 1515 2175 1.01 1470 2250 1.06 1426 
Replies to Comment # 152.
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